Math 55

11/22/2020 Mid-Chapter 5 Review-Natalie Banks

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Student: Natalie Banks Date: 11/22/20

Instructor: Sam Pearsall Course: Math 55, Oct-Dec F20 Assignment: Mid-Chapter 5 Review

Find the domain of the function f(x) . Write both set-builder notation and interval notation for the answer.= 4x − 7 x + 7

Write the domain in set-builder notation. Select the correct choice below and, if necessary, fill in the answer box to complete your choice.

A. The domain of f is .x|x is a real number and x = (Type an integer or a fraction. Use a comma to separate answers as needed.)

B. The domain of f is .x|x is a real number and x ≠ (Type an integer or a fraction. Use a comma to separate answers as needed.)

C. The domain of f is {x|x is a real number}.

The domain of f is . (Type your answer in interval notation.)

Find the domain of the function.

f(x) = x3 − x2 + x + 2

x2 + 8x + 12

Write the domain in set-builder notation. Select the correct choice below and, if necessary, fill in the answer box to complete your choice.

A. The domain of f is .x x is a real number and x ≠ (Type an integer or a fraction. Use a comma to separate answers as needed.)

B. The domain of f is .x x is a real number and x = (Type an integer or a fraction. Use a comma to separate answers as needed.)

C. The domain of f is .{ }x x is a real number

The domain in interval notation is . (Type your answer in interval notation.)

Simplify by removing factors of 1.

21s2

70s11

= 21s2

70s11

(Simplify your answer.)

Simplify by removing factors of 1.

25z − 10 25

The simplified form is .

11/22/2020 Mid-Chapter 5 Review-Natalie Banks

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Simplify by removing factors of 1.   

d3 − a3

d2 − a2

The simplified form is .

Simplify by removing factors of 1.

z2 − 9z + 20

z2 + 2z − 24

The simplified form is .

Simplify by removing factors of 1.

6x − 48 6x + 48

The simplified form is .

Find the LCM.

15c b , 5c b , 6c b3 6 4 6 2 6

The LCM is .

Find the LCM.

, , 7q2 − 33q − 10 2q2 − 11q + 5 q2 − 25

The LCM is . (Type your answer in factored form.)

Divide and simplify. 

÷ y

2 − 64 y

y + 8 y + 3

÷ y2 − 64

y y + 8 y + 3

=

(Simplify your answer.)

Add.   

+ w − 7 w + 5

w + 3 w − 1

Choose the sum.

A. w2 − 7w + 22 (w + 5)(w − 1)

B. 2w2 + 22 (w − 5)(w + 1)

C. 2w2 + 22 (w + 5)(w − 1)

D. 2w − 4 (w + 5)(w − 1)

11/22/2020 Mid-Chapter 5 Review-Natalie Banks

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Subtract. 

− 3w

w2 − 7w + 10

2w

w2 − 8w + 15

The difference is . (Simplify your answer.)

Simplify.

1 x

+ 5

1 x

− 9

The simplified expression is . (Simplify your answer.)

Multiply and simplify.

• z2 − 81 7z + 21

z + 3 z − 9

= • z2 − 81 7z + 21

z + 3 z − 9

(Simplify your answer. Use integers or fractions for any numbers in the expression.)

Multiply and simplify. 

• b

3 + 64

b 2

− 16

b 2

− 8b + 16

b 2

− 4b + 16

The simplified product is .

Divide and simplify.

÷ y2 − 25

y2 − 16y + 64

4y − 20

y2 − 2y − 48

The simplified quotient is . (Type your answer in factored form.)

Divide.

( ) ( )4b3 + 2b2 + 10 ÷ 2b + 4

Choose the correct answer below.

A. 2b + 3b + 6 +

2 − 22 2b + 4

B. 2b − 3b + 62

C. 2b − 3b − 62

D. 2b − 3b + 6 +

2 − 14 2b + 4

11/22/2020 Mid-Chapter 5 Review-Natalie Banks

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Use synthetic division to divide.

( ) ( )b4 − 625 ÷ b − 5

Choose the correct answer below.

A. b + 25b3

B. b + 5b + 25b + 1254 3 2

C. b + 5b + 25b + 1253 2

D. b − 5b − 25b + 1253 2

Use synthetic division to divide.

( ) ( )2b3 + 16b2 + 26b − 29 ÷ b + 5

( ) ( )2b3 + 16b2 + 26b − 29 ÷ b + 5 = (Simplify your answer. Use integers or fractions for any numbers in the expression.)

Use synthetic division to divide.

( ) ( 1)r2 − 3r + 2 ÷ r +

( ) ( 1)r2 − 3r + 2 ÷ r + = (Simplify your answer. Use integers or fractions for any numbers in the expression.)

Divide and check.

( ) ( )s2 − 7s − 44 ÷ s + 2

( ) ( )s2 − 7s − 44 ÷ s + 2 = (Simplify your answer. Use integers or fractions for any numbers in the expression.)