Lesson4bIntegralsoflnx.docx

Integrals of ln NAME: _____________________________________________________________

Find the integral of the following natural logarithmic functions by SUBSTITUTION METHOD.

RECOGNIZE THE QUOTIENT FORM OF the LN rule as of following:

# 1 to 12 let U = the denominator for SUBSTITUTION

Definite integrals: Remind

Use Long division before integrating for # 13 and 14 below before integrating

Use U-sub for ln(expression) rule

(

)

3.

5

:ln5

x

x

x

e

dx

e

ansec

-

-+

ò

2

2

2

4.

5

:ln5

x

x

x

e

dx

e

ansec

-

-+

ò

(

)

4

5

5

1

5

5.

7

:ln7

x

dx

x

ansxc

+

++

ò

(

)

sin

6.

cos

:lncos

x

dx

x

ansxc

-+

ò

(

)

sin

sin

sin

cos

7.

2

:ln2

x

x

x

xe

dx

e

anseC

+

++

ò

(

)

1

8.

(ln5)

:lnln5

dx

xx

ansxc

×+

++

ò

(

)

1

5

cos(5)

9.

sin(5)5

:lnsin(5)5

x

dx

x

ansxc

+

++

ò

(

)

21

33

1

3

1

10.

:3ln1

dx

xx

ansxc

æö

+

ç÷

èø

++

ò

(

)

()()()

b

b

x

a

a

fdxFxFbFa

==-

ò

2

1

8.

ln

:ln2

e

e

dx

xx

ans

ò

(

)

4

2

3

2

4

3

csc

12.

3cot

:ln4ln3ln

x

dx

x

ans

p

p

-

-=

ò

2

2

32

1

6

2

13.

:4ln(1)

xx

x

x

dx

ansxxc

-+

+

-+++

ò

(

)

2

2

2

1

2

1

14.

1

:ln1

xx

dx

x

ansxxc

++

+

+++

ò

(

)

2

2

15.

56

:ln6

xx

xx

x

ee

dx

ee

Factoraspolynomial

ansec

+

--

-+

ò

(

)

2

2

(tan3)sec

16.

tan2tan3

:lntan1

xx

dx

xx

Factoraspolynomial

ansxc

-

--

++

ò

(

)

(

)

'

1

'&ln

x

x

U

dUUdxdxdUUC

UU

===+

òò

cot

17.

ln(sin)

:ln(ln(sin))

x

dx

x

ansxc

+

ò

tan

18.

lnsec

:ln(ln(sec))

x

dx

x

ansxc

+

ò

5

5

1

5

1

19.

ln

:ln(ln))

dx

xx

ansxc

+

ò

(

)

2

1

2

20.ln(sin)cot

:ln(sin)

xxdx

ansxc

+

ò

(

)

2

1

2

21.ln(cos)tan

:ln(cos)

xxdx

ansc

-+

ò

(

)

3

2

3

1

6

ln

22.

:ln

x

dx

x

ansxc

+

ò

(

)

(

)

(

)

2

1

6

ln35

23.

(35)

:ln35

x

dx

x

ansxc

+

+

++

ò

(

)

(

)

(

)

(

)

2

1

2

ln1

24.

1

:ln1

xx

x

x

ee

dx

e

ansec

+

+

++

ò

2

3

3

1

3

1.

3

:ln(3)

x

dx

x

ansxc

-

--+

ò

2

csc

2.

cot

:ln|cot|

t

dt

t

ansc

-+

ò