SPC tools and techniques– part 2 & Fundamentals of Statistics—Part 1

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Lecture8.pdf

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Lecture 8: Fundamentals of Statistics—Part 1

Chapter 5

Outline

 Statistics, type of data, data description

 Frequency distribution and histogram

 Measures of central tendency

 Measures of dispersion

 Population, sample,

 Normal curve

 Computer program

Types of Data

 Variable

 Quality characteristics that are measurable, continuous.

 Example: length, weight

 Attribute

 Classified either conforming or nonconforming (yes/no, accept/reject)

Go/NoGo gauge

 A Go/no go refers to an inspection tool used to check a workpiece against its allowed tolerances. Its name derives from its use: the gauge itself has two tests; the check involves the workpiece's having to ‘pass’ one test (Go) and 'fail' the other (No Go).

Go/NoGo gauge

Lower gauge is a plain plug gauge of 12.60mm for 'Go' and 12.90mm as 'NoGo‘ For checking tolerance between 12.60-12.90.

For a washer with dia= 12.75, pass one and fail the other and a washer with dia= 12.5, fail at both end

Describe Data

 Summarizing data:

 Graphical (describe picture)

 Plot or picture of frequency distribution

 Analytical (math calculations)

 Measures of central tendency (mean, mode, median)

 Measures of dispersion (range, std. deviation)

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Descriptive statistics

 Mean = average()

 Median = median()

 Mode = Mode()

 Std. Dev. = STDEV()

 Variance = var()

 Count = count()

 Max = max()

 Min = min()

 Range = max()-min()

 Skewness = skew()

 Kurtosis = kurt()

 Sum =sum()

 Student scores

 82.64, 84.47, 77.12, 79.08, 95.21, 81.84, 94.66, 80.50, 84.96, 89.18, 87.76

 Mean=85.22

 Median=84.47

 Max= 95.21

 Min=77.12

Describe Data

0

1

2

3

4

5

6

7

<75 <80 <85 <90 <95 <100

Frequency

Frequency

Frequency Distribution

 Ungrouped data: a listing of the individual observed values

 Grouped data: a lumping together (subgroups) of the observed values

Frequency Distribution– ungrouped data

 A table that includes the number of daily billing errors of a larger organization

Example— number of daily billing errors

 Organize the data (array)

 Tabulate the frequency of each value

Different types of frequency distributions

 Histogram: consists of a set of rectangles that represent the frequency in each

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Different types of frequency distributions

 Relative frequency distribution: proportion or fraction of the total

Different types of frequency distributions

 Cumulative frequency

Different types of frequency distributions

 Relative cumulative frequency

Summarization of this billing example

 This example shows how to organize and sort the data by frequency, relative frequency, cumulative frequency, and relative cumulative frequency.

 We have practiced this tasks in Pareto chart

 Students should be able to chart these frequency data by Excel

Frequency Distribution– grouped data

 Sometimes the collected data is a large volume of data set. If we still use the previous method, the frequency distribution result may not give a good explanation.

Frequency Distribution– example of grouped data

 Example: steel shaft weight (kilograms)

 Simplify data by coded value: the weights are coded from 2.500Kg, a weight with a value of 31 is equivalent to 2.531Kg (2.500+0.031)

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Steel shaft weight

 Total: 110

 Highest: 75

 Lowest: 31

Frequency Distribution– grouped data

 Collect data and construct a tally sheet

 Determine the range

 Determine the cell (subgroup) interval

 Determine the cell midpoints

 Determine the cell boundaries

 Post the cell frequency

1. Data tabulation: from lowest to highest, a tally sheet

 A large number of categories

2. Determine the range

 Where R=range

 Xh= highest data

 Xl = lowest data

044.0531.2575.2  lh

XXR

How many cells (categories) should be formed– grouping

 Number of cells is based on judgment

 General rule of thumb is the number of cells should be between 5 and 20

 5 to 9 when observations are < 100

 8 to 17 observations are between 100 & 500

 15 to 20 when observations are > 500

Three issues in creating the cells

 Equal width of cell intervals

 Cell midpoints

 Cell boundaries

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3. Determine the cell interval width

 Cell interval is the distance between adjacent cell midpoints. Odd number is preferred because of easy calculation

0057.0 )110log(322.31

044.0

log322.31 

 

 

n

R i

3. Determine the cell interval length

 All trial-and-error method, here h is the total number of intervals needed

 Assume i=0.003, then

 Assume i=0.005, then

 Assume i=0.007, then

9 005.0

044.0 

i

R h

15 003.0

044.0 

i

R h

6 007.0

044.0 

i

R h

4.Determine the cell boundaries and midpoints

 When constructing a histogram, it’s important to remember two things:

 Histogram must contain all of the data

 One particular value cannot fit into two different cells, which means cells cannot overlap

4.Determine the cell boundaries and midpoints

 1st method-- the simplest technique is to choose the lowest value measured as first midpoint, and so on…

 2nd method-- lowest value will be the lower boundary for first cell (then, the first midpoint would be the lowest value plus half of interval), and so on…

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i XMP

ll 

4.Determine the cell boundaries and midpoints— by 1st method

 Lowest value as the first midpoint → so

 first Midpoint =2.531

 Since width=0.005, so first cell boundaries:

Lower-B=2.531-0.005/2

= 2.5285

Upper-B=2.531+0.005/2

=2.5335

Midpoint Cell boundaries

2.531 2.5285 - 2.5335

2.536 2.5335 - 2.5385

2.541 2.5385 – 2.5435

2.546 2.5435 – 2.5485

2.551 2.5485 - 2.5535

2.556 2.5535 - 2.5585

2.561 2.5585 – 2.5635

2.566 2.5635 – 2.5685

2.571 2.5685 – 2.5735

2.576 2.5735 – 2.5785

4.Determine the cell boundaries and midpoints— by 2st method

 Lowest value as the lower boundary of the first cell → so Lower-B=2.531,

Adjust a little bit, then

 Lower-B=2.530

 First Midpoint =2.530+0.005/2 = 2.5325

Upper-B=2.530+0.005

=2.535

Midpoint Cell boundaries

2.5325 2.530 - 2.535

2.5375 2.535 - 2.540

2.5425 2.540 - 2.545

2.5475 2.545 – 2.550

2.5525 2.550 - 2.555

2.5575 2.555 - 2.560

2.5625 2.560 – 2.565

2.5675 2.565– 2.570

2.5725 2.570 – 2.575

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4.Determine the cell boundaries and midpoints

 Other midpoints: 2.533+0.005=2.538

 2.538+0.005=2.543…..

533.2 2

005.0 531.2

2 

i XMP

ll

4.Determine the cell boundaries and midpoints

 Boundaries are established so there is no question as to the location of an observation.

2.530 2.535 2.540 2.575 2.545 2.550 2.555 2.560 2.565 2.570

6. Post the cell frequency Excel Histogram function

 Histogram command

 Input range — entire data

 Bin range — using upper boundary to separate the cells

 Given these two parameters, Excel will generate frequency column

 Be careful: you must have “Data Analysis ToolPak” loaded

Characteristics of Graphs

 Symmetry or lack of symmetry of the data (Distribution around the central value, Skewness)

 Number of peaks

 Peakedness of the data

 Platykurtic (flat shape)

 Leptokurtic (clear peak)

Characteristics of frequency distributions

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Analysis of Histogram

 Many cases are expected to have a normal pattern (bell)

 Graphical representation can help figure out problems if there is any in the process.

 If not normally distributed, then something in the process may be out of control or the data follows some other basic pattern

Differences due to location, spread, and shape

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Histogram Computing function with Excel

 Define the data range

 Find out mean, median, mode, standard deviation

Construct histogram

 Name “data” or other names  Use functions to describe data  Define midpoint and U-boundary  Tool— Data Analysis—Histogram

 Input range — data  Bin range— U-boundary  Output range—

 Chart data— midpoint and frequency columns  One useful website about histogram with

Excel

Procedures of using Excel to make histogram

How many cells

or categories

Boundaries of

cells or categories

Excel histogram

function (data, Bin) Chart

function

R=max(data)-min(data)

i=R/(1+3.322log(n)) # of cells = R/i

The very left cell,

L-bound

U-bound= L-bound + i

U-bound (n+1) = U-

bound (n) +i

Cell

midpoint Midpoint=(L-bound + U-bound)/2

Midpoint=L-bound + i/2

Assignment today/this week

 InClass 6: Histogram function in Excel

 Homework 2