It-340 assignment 2

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IT340Assignment2studentanswer.docx

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Question Four

Assignment 2

Deadline: Tuesday 03/11/2020 @ 23:59

[Total Mark for this Assignment is 6]

Network Management

IT 340

https://www.seu.edu.sa/sites/ar/SitePages/images/logo.png

College of Computing and Informatics

Question One

1 Marks

Learning Outcome(s):

Recognize conceptual and practical knowledge of different versions of Simple Network Management Protocol (SNMP).

Explain GetBulkRequest message in SNMPv2? How does it support GetNextRequest operation to retrieve data?

Answer

The GetBulkRequest message is generated by manager application. It’s used to transfer large amounts of data from the agent to the manager, especially if it includes retrieval of multiple rows of data from a table. It minimizes the number of protocol exchanges required to retrieve a large amount of management information.

The retrieval is fast and efficient. The receiving entity generates and fills data for each entry in the request and transmits all the data as a response message back to the originator of the request.

The basic operation of get-bulk-request is the same as get-next-request.The GetBulkRequest operation uses the same selection principle as the GetNext-Request operation; that is, selection is always of the next object instance in lexicographic order. The difference is that, with GetBulkRequest, it is possible to specify that multiple lexicographic successors be selected.

Question Two

2 Marks

Learning Outcome(s):

Evaluate different SNMP tools, network statistics tools, and protocol analyzer for network management.

What are the two new data types that are defined in RMON textual conventions? Also, highlight, how they appear in ASN.1?

Answer

· Two new data types that are defined in RMON1 textual conventions are OwnerString and EntryStatus

· OwnerString contains information about the owner such as lP address, management station name, network manager's name, location. or telephone number

· EntryStatus used to create and delete conceptual row in tables in addition to resolving conflicts between management systems in manipulating control tables.

· The EntryStatus data type can exist in one of four states: (l) valid, (2) createRequest, (3) underCreation,and(4) invalid.

Question Three

1.5 Marks

Learning Outcome(s):

Recognize conceptual and practical knowledge of different versions of Simple Network Management Protocol (SNMP).

Fill in the values for the SNMPv2 Trap PDU for a message sent by the hub shown below, 3 seconds after it is reset following a failure. The SNMPv2 Trap PDU included varBinds are: sysUpTime(1.3.6.1.2.1.1.3), snmpTrapOID (1.3.6.1.6.3.1.1.4.1) , snmpTrapEnterprise(1.3.6.1.6.3.1.1.4.3) and snmp Traps(1.3.6.1.6.3.1.1.5).

Title: System Information: 172.16.46.2

Name or IP Address: 172.16.46.2

System Name:

System Description: 3Com LinkBuilder FMS, SW version: 3.02

System Contact:

System Location:

System Object ID: iso.org.dod.internet.private.enterprises.43.1.8.5

System Up Time: (2475380437) 286 days, 12:03:24.37

Answer

PDU type

7

Request ID

100

Error Status

0

Error Index

0

VarBind 1 sysUpTime

1.3.6.1.2.1.1.3

VarBind 1 value

300

VarBind 2 snmpTrapOID

1.3.6.1.6.3.1.1.4.1

VarBind 2 value

1.3.6.1.6.3.1.1.5.1

VarBind 3

1.3.6.1.6.3.1.1.4.3

VarBind 3 value

1.3.6.1.4.1.43.1.8.5

Question Four

1.5 Marks

Learning Outcome(s):

Recognize conceptual and practical knowledge of different versions of Simple Network Management Protocol (SNMP).

Explain the full SNMP engine ID for:

(a) SNMPv1 for a 3Com(43) switch with the IPv4 address 129.54.46.5 in the 6th to 9th octets followed by 0s in the rest.

(b) SNMPv3 for the Cisco(9) router interface with IPv6 address 3B:77:A1::E5.

Answer

A)

(a) 3Com (43) switch with IP address 129.54.46.5:

For IPv4, the address is filled in the 6th to 9th octets followed by 0s in the rest.

00

00

00

2b

01

81

36

2E

05

00

00

00

Enterprise ID 1st bit= 0

IPV4

129

54

46

5

Not used

The answer is 00 00 00 2b 01 81 36 2E 05 00 00 00

b)

Cisco (9) router with IPv6 address 3B:77:A1::E5.

IPv6 requires 16 bytes

first three bytes are 3B,77,A1

· :: means all zeros

· last byte is E5

80

00

00

09

02

3B

77

A1

00

00

00

00

00

00

00

00

00

00

00

00

E5

Enterprise ID 1st bit= 1

IPv6

3B

77

A1

0

0

0

0

0

0

0

0

0

0

0

0

E5

The answer is:

80 00 00 09 02 3B 77 A1 00 00 00 00 00 00 00 00 00 00 00 00 E5