Chemistry Lab

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CHM101LM5FactorsAffectingReactionRatesLabReport.docx

5

Factors Affecting Reaction Rates Student Name Date

Data

Activity 1

Data Table 1: Calibration

Trial

Na2S2O3 (drops)

Reaction time (sec)

1

2

3

1. How many drops will be used in the remaining experiments?

Activity 2

Data Table 2a. Effects of KI (I-) Concentration

Trial

KI

(drops)

HCl

(drops)

Starch

(drops)

H2O

(drops)

Na2S2O3

(drops)

H2O2

(mL)

Time1 (sec)

Time2 (sec)

Average time

(Tavg) (sec)

Rate (1/Tavg)

1

8

2

4

0

0.4

2

8

2

4

0

0.4

3

6

2

4

2

0.4

4

6

2

4

2

0.4

5

4

2

4

4

0.4

6

4

2

4

4

0.4

7

2

2

4

6

0.4

8

2

2

4

6

0.4

Data Table 2b. Effects of H2O2 Concentration

Trial

KI

(drops)

HCl

(drops)

Starch

(drops)

H2O

(mL)

Na2S2O3

(drops)

H2O2

(mL)

Time1 (sec)

Time2 (sec)

Average time

(Tavg) (sec)

Rate (1/Tavg)

1

8

2

4

0

0.4

2

8

2

4

0

0.4

3

8

2

4

0.1

0.3

4

8

2

4

0.1

0.3

5

8

2

4

0.2

0.2

6

8

2

4

0.2

0.2

7

8

2

4

0.3

0.1

8

8

2

4

0.3

0.1

Data Table 2c. Effects of HCl (H+) Concentration

Trial

KI

(drops)

HCl

(%)

Starch

(drops)

H2O

(drops)

Na2S2O3

(drops)

H2O2

(mL)

Time1 (sec)

Time2 (sec)

Average time

(Tavg) (sec)

Rate (1/Tavg)

1

8

100%

4

0

0.4

2

8

100%

4

0

0.4

3

8

75%

4

0

0.4

4

8

75%

4

0

0.4

5

8

50%

4

0

0.4

6

8

50%

4

0

0.4

7

8

25%

4

0

0.4

8

8

25%

4

0

0.4

Activity 3

Data Table 3. Temperature Effects

Water bath trial

Temperature of the water bath (°C)

Reaction time (sec)

Cold water

Room-temperature water

Hot water

2. Explain how each of these treatments affected the reaction rate. Describe the effect at a molecular level.

a. Concentration

b. Temperature

Activity 4

Data Table 4. Catalyst

Trial

Water (drops)

CuSO4 (drops)

Reaction time (sec)

1

2

3

4

5

3. How did the addition of copper(II) sulfate affect the reaction rate? Did the amount of catalyst affect the reaction rate?

Activity 5:

Data Table 5. Orders of Reactants in the Rate Law

R = k[I–]m[H2O2]n[H+]p

Calculated Reaction order (X) (e.g. )

Reactant

Concentration

Average Rate

Calculated Reaction order (X)

Average Reaction order

Reaction Order (integer)

KI (I)

8 drops

m =

KI (I)

6 drops

KI (I)

4 drops

KI (I)

2 drops

H2O2

0.4 mL

n =

H2O2

0.3 mL

H2O2

0.2 mL

H2O2

0.1 mL

HCl (H+)

100%

p =

HCl (H+)

75%

HCl (H+)

50%

HCl (H+)

25%

Rate law

Overall order of the reaction

4. Use the rate-law expression you determined for Data Table 5 to answer the following questions.

a. If the concentration of I– was doubled, how would that affect the reaction rate?

b. If the concentration of H2O2 was halved, how would that affect the reaction rate?

c. If the concentrations of I– and H2O2 were both doubled, how would that affect the reaction rate?

d. If the concentration of H+ (HCl) was doubled, how would that affect the reaction rate?

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