chm 1045
QUIZ 04 TAKE HOME part. CHEM 1045 Dr. T. Mc CAFFREY
NAME: _______________________________________ DATE: ____________________________
6) RELATIVE COMPARATIVE DIFFUSION and EFFUSION of GASES:
A) Are dependent on the atmospheric pressure
B) Are dependent on the temperature
C) Are dependent on the volume of the container
D) Both are inversely proportional to the square root √ 1/ MW
E) Are not influenced by molecular weight of the gases.
7) As a person travels from Miami to Cusco Peru, the oxygen partial pressure;
A) remains the same;
B) increases and causes hypertension;
C) decreases;
D) increases and causes hypotension;
E) the ratio of carbon dioxide and oxygen becomes inverted
8) A girl carries a balloon of Nitrogen gas on the airplane flight from Miami,
P1 = 760 mm, T1 = 310 oK , and V1 = 1.00 L
She gets off the plane in Cusco Peru,
P2 = 725 mm, T2 = 278 oK
CALCULATE V2 = ?
A) 1.50 L
B) 2.15 L
C) 0.940 L
D) 5.50 L
12) In the hospital and in the clinics, the blood pressure is reported as
A. millimoles / Liter
B. milliequivalents / Liter
C. millimeters of Hg
D. millitorrs
E millipascals
.
26. 10 points. Fill in the boxes with the electron configuration for the element Se
__________ 4s
_______ 3d
SHAPE \* MERGEFORMAT
SHAPE \* MERGEFORMAT
SHAPE \* MERGEFORMAT
SHAPE \* MERGEFORMAT
27. FREEZING POINT DEPRESSION of 2 % (w/w) Ethylene Glycol in 500 mL solution in water. Assume that the density of the solution is 1.00 gm/mL.
A. Calculate the molality. (Formula Wt of Ethylene Glycol is 62).
B. Calculate the ΔT freezing depression assuming that the Kf of water is 1.86 0C/molal
30. Calculate the empirical formula for the following NSAID Drugs: [See Chapter 3. Section 3.5, 3.6, 3.7]
A. Acetaminophen: C = 63.56%; H = 6.00 %; N = 4.20%; O = 21.17%
B. Naproxen: C = 73.03 %; H = 6.13%; O = 20.84%
32.0 Consult Chapter 3, section 3.5, 3.6, 3.7.
Elemental analysis of a well known psychiatric drug for depression gives the following results for elemental analysis:
C = 66.01 %; H = 5.87 %; F = 18.43 %; N = 4.53% ; and O = 5.17%
Calculate the empirical formula for this compound.
EXTRA CREDIT: 4 points. Score the gases from the highest velocity to the lowest velocity “4” = highest, “1” = lowest.
CH4 (MW = 16) ______________
SO3 ( MW = 80) _______________
CO2 (MW = 44) _______________
N2 (MW = 28) ________________
HINT: Recall the interrelationship between diffusion , velocity, and Molecular Weight.
32.0 LIMITING REAGENT PROBLEM. Consult Chapter 3, section 3.7, page 106
27. LIMITING REACTANT PROBLEM 20 points
Consider the balanced reaction: Place one block of metallic Aluminum into a solution of HNO3. Room Temperature.
2 Al + 6 HNO3 2 Al(NO3)3 + 3 H2
GIVEN:
60.0 gram Al solid
1.00 Liters of 2.00 M HNO3 solution.
CONVERSION FACTORS:
[1 mole Al / 27.00 gram Al]
[2 moles Al(NO3)3 ] / [2 moles Al]
[ 2 moles Al(NO3)3] / [6 moles HNO3]
2.00 Molar Acid Solution = [2.00 moles HNO3/1.00L]
[213 gram Al(NO3)3 / 1mole]
A. SET UP two parallel calculations: one for HNO3 and one for Al
B. Determine for both reactants how many MOLES of Al(NO3)3 are produced
C. How many grams of Al (NO3)3 in both cases?
D. Indicate clearly which is the limiting reactant? = 1 point “LIMITING”
E. What remains in grams unreacted in the vessel after the reaction? = 5 point
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