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Chapters6and7CHEM101PostLesson.pptx

Chapters 6 and 7: Properties of Electrons and Light

CHEM 101

Fall 2020

Dr. Lauren Genova

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Chapter 4

By the end of this chapter, you will be able to:

Calculate related light-wave properties such as frequency, wavelength, and energy

Recognize the wave-particle duality of light and matter

Compare and contrast the Bohr model of the hydrogen atom with the quantum mechanical description of electrons in an atom

Describe the four quantum numbers that form the basis for specifying the state of an electron in an atom

Determine the electron configuration of an atom

Characterize an element as paramagnetic or diamagnetic

Describe and explain the observed trends in atomic size, ionization energy, electron affinity, and electronegativity of the elements

Predict the reactivity trends for metals vs. non-metals

Chapters 6 and 7: Learning Objectives

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Electronic Structure of Atoms

Electrons are the ultimate determinant of the properties and reactivity of atoms.

Understanding how electrons behave and what influences them is critical to understanding chemistry.

3

Chapter 6

Late 1800s-early 1900s saw an increased understanding of atomic structure.

To better understand the configuration of electrons around an atom’s nucleus, scientists exposed atoms to various forms of electromagnetic energy.

J.J. Thomson “Plum Pudding Model,” 1904

Bohr Model

1913

Electronic Structure of Atomic Models

4

Chapter 6

Continuous range of radiant energy (also called electromagnetic radiation)

The Electromagnetic Spectrum

Longer wavelength

Lower frequency

Lower energy

Shorter wavelength

Higher frequency

Higher energy

 Visible light = the portion of the electromagnetic spectrum that the human eye can view!

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Chapter 6

5

Electrons, as we will see, can behave as both waves and particles. And so, let’s start with waves: namely, by reviewing the electromagnetic spectrum.

Wavelengths of visible light (nm)

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Chapter 6

6

Scientist Spotlight Dr. Felix S. Alfonso Postdoctoral Scholar, Department of Chemistry and Chemical Biology, Cornell University (Ithaca, NY) Topic: Light Favorite books: The Little Prince by Antoine de Saint-Exupéry and The Alchemist by Paulo Coelho

Wavelength (λ): the distance from crest to crest or trough to trough.

Typical units: m to nm

Frequency (υ): the number of wave cycles passing a stationary point of reference per unit of time

1 wave cycle = 1 complete wavelength

Typical unit: Hz (s-1)

υ = Greek letter nu (pronounced as “new”)

Wave Properties of Light

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Chapter 6

8

Wavelength (λ) and frequency (υ) are related by:

λυ = c

where c is the speed of light:

c = 2.998 × 108 m/s

λυ = c = 2.998 × 108 m/s

Wave Properties and Light

9

Chapter 6

Wavelength and frequency are inversely proportional.

9

One of my favorite radio stations broadcasts at a frequency of 104.5 MHz (1 MHz = 106 Hz). What is the wavelength (in m) of these radio waves?

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Example: Wavelength and Frequency

https://i.iheart.com/v3/re/assets.brands/5c6f2321fda9bbc152bc32e6

Double check your work! (2.869 m)(1.045 × 108 s−1) = 2.998 × 108 m/s ✓

Chapter 6

1.) CD players use lasers which emit red light with a wavelength of 685 nm. What is the frequency of this light?

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Practice: Wavelength and Frequency

Chapter 6

4.38 X 1014 s-1 (or Hz)

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1.) CD players use lasers which emit red light with a wavelength of 685 nm. What is the frequency of this light?

Approach:

12

Practice: Wavelength and Frequency

Chapter 6

4.38 X 1014 s-1 (or Hz)

12

Irradiating matter with light can cause electrons to be ejected from a material.

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Electronic Structure of Atoms

Chapter 6

Light is a carrier of energy

Energy of a moving electron = kinetic energy (KE)

Unit of energy: Joules

++

++

+++

+++

The energy of the incoming light is equal to the energy of the ejected electron

Different elements require different energies due to differing numbers of protons and electrons

What happens if we use different colors (frequencies) of light?

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Atomic View of Electron Removal

Energy is required to overcome attraction between negative electron and positive nucleus

Chapter 6

For low-frequency light, no electrons are emitted, regardless of the intensity of the light.

Electrons are emitted by a given metal above a specific threshold frequency, ν0 .

For light frequency greater than ν0, the number of electrons emitted increases with the intensity of light.

For light frequencies above ν0, KE of electrons increases linearly with the frequency of light.

e-

e-

e-

15

The Photoelectric Effect (Einstein, 1905)

Charged metal plate

Chapter 6

The photoelectric effect is the emission of electrons when electromagnetic radiation, such as light, hits a material. Electrons emitted in this manner are called photoelectrons. This phenomenon is commonly studied in electronic physics and in fields of chemistry such as quantum chemistry and electrochemistry. (https://en.wikipedia.org/wiki/Photoelectric_effect)

0- Here we have a charged metal plate onto which we will shine light with a variety of frequencies.

1- When low-frequency light is directed onto a charged metal surface, no electrons are ejected.

2- When the intensity of the low-frequency light is increased, the result is the same.

3- These experiments showed that for low-frequency light, no electrons are emitted regardless of the intensity of the light.

4- When light with a high enough frequency is used, we see that electrons are ejected from the charged metal surface. This minimum frequency is called the threshold frequency.

5- Electrons are emitted by a given metal above a specific threshold frequency, ν0 .

6- When the intensity of this light is increased, we observe a larger number of ejected electrons.

7- For light frequency greater than ν0, number of electrons emitted increases with the intensity of light.

8- If the light used has a frequency higher than the threshold frequency, we observe the electrons with a higher kinetic energy.

9- For light frequencies above ν0, KE of electrons increases linearly with frequency of light.

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Along with other experiments involving light, the observation of the photoelectric effect led to the concept of wave-particle duality

Light is both a wave and a particle

Individual light “packets” are photons with energy determined by frequency

A photon can be considered a light particle, though it has no mass

Equation for calculating the energy of a single photon is:

Planck’s constant, h = 6.63 x 10-34 J*s

E = hυ or E = hc/λ

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Photon Energy

Chapter 6

 We’ll practice using this equation in a bit

The many forms of electromagnetic energy make up a continuous spectrum, where all possible wavelengths and frequencies are represented below:

Chapter 6

Continuous vs. Line Spectra

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More common example of a continuous spectrum: the “rainbow” seen when white light is separated into its component colors by a prism

Each color blends into the next; there are no gaps in the visible spectrum (i.e., we observe a continuous spectrum of λ)

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Chapter 6

Continuous vs. Line Spectra

Examples of white light: sunlight, incandescent light bulb

Dispersion, the separation of visible light into a spectrum, may be accomplished by means of a prism or a diffraction grating. Each different wavelength or frequency of visible light corresponds to a different color , so that the spectrum appears as a band of colors ranging from violet at the short-wavelength (high-frequency) end of the spectrum through indigo, blue, green, yellow, and orange, to red at the long-wavelength (low-frequency) end of the spectrum. In addition to visible light, other types of electromagnetic radiation may be spread into a spectrum according to frequency or wavelength. (https://www.infoplease.com/encyclopedia/science/physics/concepts/spectrum/continuous-and-line-spectra)

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But, if light emitted from an excited atom is passed through a prism, only a few frequencies or wavelengths of visible light are present (there are gaps in the visible light spectrum)

This type of spectrum is called a line emission spectrum because each line represents a particular λ of visible light emitted from the atom; the missing λ’s appear as dark lines or gaps

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Chapter 6

Continuous vs. Line Spectra

Let’s look at hydrogen as an example.

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Each element has its own characteristic line emission spectra

Spectral lines are called the “fingerprints of the elements” or “chemical bar codes,” because they are unique for each element and therefore can be used to identify which elements are present in matter of unknown composition! http://chemistry.bd.psu.edu/jircitano/periodic4.html

Study of the hydrogen line spectrum led physicist Niels Bohr to a model of the H atom

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Chapter 6

Line Emission Spectra

Line emission spectra of the light from excited hydrogen, mercury, and neon atoms:

In contrast to continuous spectrum of white light:

Line spectra aren’t just unique to hydrogen! – the spectra produced by other elements are also discontinuous!

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Chapter 6

Bohr and the Hydrogen Atom

https://www.atomicheritage.org/sites/default/files/Niels_Bohr_Date_Unverified_LOC_0.jpg

Bohr Model of the Atom:

In 1913, Niels Bohr reasoned electrons in an atom were restricted to certain orbits (also called energy levels) surrounding the atomic nucleus

Called orbits because electrons were thought to orbit the nucleus in a fixed path, like how the planets orbit the sun.

Electrons could not exist between these orbits (their energy is quantized)

Electrons can’t exist between energy levels, just like people can’t stand between stair steps!

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Chapter 6

Electrons Exist in Quantized Energy Levels… just like steps on a staircase!

https://slideplayer.com/slide/12448767/;https://thumbs.dreamstime.com/z/businessman-standing-stairs-gray-background-32142377.jpg

You can only stand on the steps, not in between the steps.

You could choose to stand on the first step, the 2nd step, or the 3rd step, but not on the 1½ step or 2¼ step – no such step exists!

Only certain elevations are allowed.

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Bohr Model of the Atom:

In 1913, Niels Bohr reasoned electrons in an atom were restricted to certain orbits (also called energy levels) surrounding the atomic nucleus

Called orbits because electrons were thought to orbit the nucleus in a fixed path, like how the planets orbit the sun.

Electrons could not exist between these orbits (their energy is quantized)

Energy in the form of photons could be absorbed/emitted to cause electrons to move between these discrete energy levels

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Chapter 6

Bohr and the Hydrogen Atom

https://www.atomicheritage.org/sites/default/files/Niels_Bohr_Date_Unverified_LOC_0.jpg

Energy Level: refers to the potential energy associated with an electron/shell in an atom (represented by each of the blue orbits here; designated by n)

Energy levels get closer together when further from the nucleus

Ground State: an atom or electron in its lowest energy state (consider this the “normal” state)

Excited State: an atom or electron in an energy state higher than the ground state because of added energy

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Chapter 6

Electronic States: Definitions

Electrons can move from the ground state to the excited state (absorption) and fall back down to lower energy (emission)

https://www.webassign.net/labsgraceperiod/ucscgencheml1/lab_6/manual.html Reason for E levels getting closer together: shielding! (n=1 is shielding the nucleus. As the energy levels increase, the pull on the electrons to the nucleus decreases gradually; therefore, they are closer when n= 3,4,5...)

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Chapter 6

Absorption vs. Emission

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n=3

n=2

n=1

n=3

n=2

n=1

excited states

ground state

Absorption: when electrons gain energy and jump from the ground state to a higher energy level (i.e., an excited state)

– This energy is from a photon!

Emission: when electrons lose energy and jump from an excited state to a lower energy level

– The difference in energy is emitted as a photon (aka EM radiation aka light!)

Electrons can move from the ground state to the excited state (absorption) and fall back down to lower energy (emission)

photon (lower E)

photon (higher E)

photon

https://www.webassign.net/labsgraceperiod/ucscgencheml1/lab_6/manual.html

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Which electron transition would emit a photon with the greatest energy?

A. Starting at n=1 and jumping to n=5

B. Starting at n=1 and jumping to n=6

C. Starting at n=5 and jumping to n=1

D. Starting at n=6 and jumping to n=1

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Chapter 6

Predicting Photon Emission

Chapter 2

Chapter 2

Poll Question #1

Which electron transition would emit a photon with the greatest energy?

A. Starting at n=1 and jumping to n=5

B. Starting at n=1 and jumping to n=6

C. Starting at n=5 and jumping to n=1

D. Starting at n=6 and jumping to n=1

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Chapter 6

Predicting Photon Emission

Chapter 2

Chapter 2

Poll Question #1

Absorption (low  high energy)

Emission (high  low energy)

Which electron transition would emit a photon with the greatest energy?

A. Starting at n=1 and jumping to n=5

B. Starting at n=1 and jumping to n=6

C. Starting at n=5 and jumping to n=1

D. Starting at n=6 and jumping to n=1

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Chapter 6

Predicting Photon Emission

Chapter 2

Chapter 2

Poll Question #1

Absorption (low  high energy)

Emission (high  low energy)

Which electron transition would emit a photon with the greatest energy?

A. Starting at n=1 and jumping to n=5

B. Starting at n=1 and jumping to n=6

C. Starting at n=5 and jumping to n=1

D. Starting at n=6 and jumping to n=1

Chapter 6

Predicting Photon Emission

Chapter 2

Chapter 2

Poll Question #1

n=6 is at a higher energy level than n=5, so the energy difference between n = 6  1 is greater than the energy difference from n = 5  1

https://courses.lumenlearning.com/cheminter/chapter/spectral-lines-of-hydrogen/

Energy

Chapter 6

Predicting Photon Emission

Chapter 2

Chapter 2

Poll Question #1

n=6 is at a higher energy level than n=5, so the energy difference between n = 6  1 is greater than the energy difference from n = 5  1

https://courses.lumenlearning.com/cheminter/chapter/spectral-lines-of-hydrogen/

Energy

Which electron transition would emit a photon with the greatest energy?

A. Starting at n=1 and jumping to n=5

B. Starting at n=1 and jumping to n=6

C. Starting at n=5 and jumping to n=1

D. Starting at n=6 and jumping to n=1

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Chapter 6

31

The Bohr Model and Line Emission Spectrum of Hydrogen

The relationship between the energy level change of a single electron and the energy of the photon emitted can be expressed as:

RE= Rydberg constant

These equations will give you magnitude of photon properties

But you must figure out whether energy (photon) is absorbed or emitted based on the sign of the energy level change

Absorbed = positive value of ΔE; emitted = negative value of ΔE

or

New constant developed from RE, h, and c to be more convenient

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Chapter 6

Rydberg Equation to Predict Energy from n

2a.) What is the wavelength (in nm) of the line in the spectrum of hydrogen that represents the movement of an electron from Bohr orbit n = 2 to n = 4?

The answer should correspond to a wavelength in the visible region, and so it is consistent with expectations!

Chapter 6

Example: The Rydberg Equation

initial

final

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(no need to memorize wavelengths and colors in this course)

Chapter 6

Example: The Rydberg Equation

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Or, working backwards from what we’ve already solved ( ):

2b.) What is the energy (in J) of this line?

2a.) What is the wavelength (in nm) of the line in the spectrum of hydrogen that represents the movement of an electron from Bohr orbit n = 2 to n = 4?

initial

final

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Chapter 6

Example: The Rydberg Equation

2c.) Was this energy emitted or absorbed?

ΔE is POSITIVE, so this energy was absorbed! (you can also tell because n goes from 2  4 (i.e., electron is jumping to an excited state; needs to absorb energy to get there)

2a.) What is the wavelength (in nm) of the line in the spectrum of hydrogen that represents the movement of an electron from Bohr orbit n = 2 to n = 4?

initial

final

2b.) What is the energy (in J) of this line?

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The spectra produced by other elements are also discontinuous! However, spectra for elements other than H are more difficult to predict because there are multiple electrons. This is where the Bohr model falls apart.

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Chapter 6

Emission Spectra of Other Elements

the spectra produced by other elements are also discontinuous!

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Strengths:

Accurately predicts emission spectrum of single electrons within atoms (e.g., H) or ions (e.g., He+, Li2+, Be3+, etc.)

Provided early model of electron organization in the atom

Limitations:

Does not explain spectra of multi-electron atoms

Requires that electrons act only as predictable particles, which later experiments disproved

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Chapter 6

The Bohr Model Evaluation

A new model was needed to describe more complex atoms.

37

We’ve established that light has wave-particle duality…. but could a particle in motion, such as electron, also behave as a wave?

Louis de Broglie (French grad student in physics, 1924) sought to answer this question! Let’s walk through his thought process and derivation:

Assuming that particles and waves have the same traits, de Broglie hypothesized that the energies for each of these systems would be equal.

And so, by combining the equation for the energy of waves (E = hυ) with Einstein’s equation famous relationship relating matter and energy (E = mc2), de Broglie derived the following equation:

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Chapter 6

Are Electrons Particles or Waves?

Givens: E = hυ, E = mc2

Assumption: these energies are equal.

Therefore, E = E

hυ = mc2

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(Skipped in 2019)

de Broglie’s derivation, continued:

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Chapter 6

Are Electrons Particles or Waves?

Givens: E = hυ, E = mc2. Assumption: these energies are equal. Therefore, E = E

hυ = mc2

By rearranging the equation c = λυ, we know

By substituting this value for υ into the equation hυ = mc2, we obtain:

Because real particles do not travel at the speed of light, de Broglie substituted velocity (v) for the speed of light (c).

By solving for λ, we obtain:

 note: velocity (v) is NOT the same as frequency (υ)

And so, de Broglie was able to show that matter (represented by “m” in the equation) indeed has wave properties (represented by λ)!

(No, I won’t ask you to derive this on an exam )

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(Skipped in 2019)

If electrons can behave as both particles AND waves simultaneously, what happens to Bohr’s model?

Where Bohr had postulated the electron as being a particle orbiting the nucleus in quantized orbits, de Broglie argued that Bohr’s assumption of quantization can be explained if the electron is considered not solely as a particle, but rather as a circular standing wave of matter such that only an integer number of wavelengths could fit exactly within the orbit.

Bohr model (electrons as particles)

Electrons as matter waves

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Chapter 6

Electrons as Matter Waves

Standing waves = good model of the wave behavior of electrons

Each red dot = a node (point in which wave amplitude = 0)

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Chapter 6

Standing Waves

For an electron in a circular orbit, only whole-number multiples of wavelengths are allowed. Any fractional number of wavelengths would result in cancellation of the wave due to destructive interference.

Just like the Bohr model of the atom, where only certain orbits were possible, the idea of quantization still remains here (where only certain discrete wavelengths are allowed!)

node

Standing wave – oscillates up and down between the nodes but doesn’t “travel”

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In 1926, Austrian physicist Erwin Schrödinger expanded on this idea of electrons’ wave-particle duality by describing electrons as 3-D standing waves of matter, or wavefunctions, represented by Ψ (Greek letter psi).

– This led to the creation of a brand new field: quantum mechanics!

His equation states that the energy of an electron (EΨ, right-side of equation) needs to incorporate energy of motion, energy due to distance from nucleus, and energy from wave properties (left-side of equation)

This is the model of the atom that is still accepted today!

– Can be applied to atoms with more than one electron

The solutions to Schrödinger’s wave equations for electrons in atoms are very complex, but we can graph them to see what they look like!

Chapter 6

The Schrödinger Equation

Newton’s laws don’t work well when you attempt to describe things as small as atoms and molecules.

YIKES. A more complete mathematical description is encompassed in quantum mechanics. This involves a set of postulates that are not intuitive (e.g. energy is quantized??) You don’t experience this in your world. Would it make sense if you could drive your car only 50 mph or 60 mph, but no values in between???) Scientists with a background in physics and mathematics developed a framework that appears to explain the observed phenomena. We will take this in good faith and not attempt to gain a deeper understanding that requires a fundamentally better mathematical understanding. Instead, we will highlight a few of the important findings and use them to make sense of some aspects of general chemistry. A more in-depth description comes in physical chemistry and beyond.

42

Chapter 6

Plotting 3-D Electron Probability Clouds

Step 2: Function is squared (ψ2)

– Gives probability function

Ψ

Ψ2

These 3-D regions in which electrons are most likely to be found are called orbitals

Step 1: Wavefunction (Ψ) for a given energy is solved

Step 3: Ψ2 function is plotted such that it reflects the probability of finding an electron in a given space (example: 90% probability)

Darker regions show increased electron density…aka, increased probability of finding an electron!)

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A region in 3-D space in which electrons in atoms are most likely to be found

Centered at the nucleus of an atom (at the origin of these plots!)

Note: we can only discuss the probability of finding an electron at a specific location because any attempt to measure its exact location causes it to move

Heisenberg uncertainty principle: “It is impossible to know both the position and the momentum of a small particle simultaneously.”

In the Schrödinger equation, we can know the energy of an electron precisely, but not its precise location

Called orbitals because they are similar to (but not the same as!) the “orbits” for electrons in the Bohr model of the atom

3 variables (called quantum numbers) are used to describe an orbital: n, l and ml

This information is contained within Schrödinger’s equation!

Chapter 6

Orbitals

=

location of

nucleus

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n, related to radius

(principle quantum number)

Radial function

Angular functions

ml, projection of angular momentum in 3D

(magnetic quantum number)

l, related to angle

(angular momentum quantum number)

Chapter 6

A Closer Look into the Schrödinger Equation

Newton’s laws don’t work well when you attempt to describe things as small as atoms and molecules.

YIKES. A more complete mathematical description is encompassed in quantum mechanics. This involves a set of postulates that are not intuitive (e.g. energy is quantized??) You don’t experience this in your world. Would it make sense if you could drive your car only 50 mph or 60 mph, but no values in between???) Scientists with a background in physics and mathematics developed a framework that appears to explain the observed phenomena. We will take this in good faith and not attempt to gain a deeper understanding that requires a fundamentally better mathematical understanding. Instead, we will highlight a few of the important findings and use them to make sense of some aspects of general chemistry. A more in-depth description comes in physical chemistry and beyond.

45

Before we go any further into orbitals and quantum numbers, I know this was a LOT of information to handle.

Chapter 6

So, let’s review the key take-away points!

https://www.wgi.org/the-pride-of-the-netherlands-brings-m-c-escher/escher-penrose-500/

Please don’t panic if these concepts are hard to wrap your head around – they ARE! Particle physics is a very complex field filled with apparent contradictions… it’s analogous to Escher’s staircase (where the top of the staircase is actually the bottom… just as wave–particle duality ascribes two seemingly contradictory traits to a single object!)

46

47

Chapter 6

Bohr vs. Schrödinger’s Quantum Mechanical Model of the Atom

Bohr Model Quantum Mechanical Model (model still accepted today!)
2-D model of the atom 3-D model of the atom (an expansion of Bohr’s 2-D model)
Can only describe atoms with one electron Can describe more complex atoms (i.e., those with more than one electron)
Energy is quantized Energy is quantized
Electron treated as a particle (classical mechanics) Electron treated as a matter wave (quantum mechanics)
Electron energy and location are known precisely (note: location could be known precisely because the electrons were thought to orbit the nucleus in a fixed path) Electron energy is known precisely, but location is not (Heisenberg uncertainty principle). We can only predict the probable location (orbital) of an electron by the Schrödinger equation.
Electrons are in energy levels (orbits, n) Electrons are in energy levels (n), sublevels (l) and sub-sub-levels (ml), all of which are needed to describe an orbital (electron cloud)

Wavefunctions’ energies in Schrödinger’s equations depend on the values of 3 quantum numbers: n, l and ml

These quantum numbers, along with a 4th quantum number ms (spin), are needed to completely describe the probable “location” (orbital) of each electron in an atom.

Pauli exclusion principle: Since two electrons cannot occupy the same space at the same time, no two electrons in an atom can have the same four quantum numbers.

Therefore, each electron has a unique “postal address” to describe its location (as designated by its unique four quantum numbers)

48

Chapter 6

Quantum Numbers: “Electron Addresses”

No two cities have the same zip code, and no two electrons have the same “zip code” in an atom!

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Principal quantum number, n

Related to “energy level” or “shell number”

Higher n values are further from nucleus

Describes the size of the orbital

Angular momentum quantum number, l

Possible values depend on n

Describes the shape of the orbital

Magnetic quantum number, ml

Possible values depend on l

Describes the orientation (direction) of the orbital in space

Chapter 6

The Quantum Numbers n, l, and ml

n is still defined as energy levels, similar to Bohr’s model

n follows same rules as for Bohr’s model: lowest level is n = 1 and counts up in whole-number increments (n = 1, 2, 3, 4, 5, 6…)

n is also called the shell number

Shells of an atom can be thought of as concentric circles radiating out from the nucleus

The electrons that belong to a specific shell are most likely to be found within the corresponding circular area

n describes the size of the orbital

As the value of n increases, the energy of the electron increases, and the distance of the electron from the atomic nucleus increases (just like the Bohr model!)

50

Chapter 6

Principal Quantum Number, n

Each l value tells us the shape of the orbital (or which subshell in which the electron is located)

Subshells are s (l = 0), p (l = 1), d (l = 2), f (l = 3), etc.

For a given n, possible l values are 0 through n-1

Again scales by integers: l = 0, 1, 2, 3, … n-1

Example: n = 4 means that l can equal 0, 1, 2, or 3

l=0

l=1

l=2

l=3

s orbital

p orbitals

d orbitals

f orbitals

For n=4,

l can equal:

51

Chapter 6

Angular Momentum Quantum Number, l

l shape
0 s
1 p
2 d
3 f

The 1st energy level (n=1, where l =0) has only 1 type of subshell, or orbital: s (l =0)

The 2nd energy level (n=2, where l =0,1) has 2 types of subshells, or orbitals: s (l =0), p (l =1)

In the 3rd energy level (n=3, where l =0,1,2), there are 3 types of subshells, or orbitals: s (l =0), p (l =1), d (l =2)

And so on…

l=0

l=1

l=2

l=3

s orbital

p orbitals

d orbitals

f orbitals

52

Chapter 6

Another way to think about l

l shape
0 s
1 p
2 d
3 f

For n=4,

l can equal:

ml=0

ml= –1, 0 or 1

ml= –2, –1, 0, 1 or 2

ml= –3, –2, –1, 0,

1, 2 or 3

s orbital

p orbitals

d orbitals

f orbitals

l=0

l=1

l=2

l=3

53

Chapter 6

Magnetic Quantum Number, ml

The magnetic quantum number, ml, tells about the arrangement of an orbital in space, or the orientation around the nucleus.

ml has whole-number values spanning from ml = –l to +l (intervals of 1).

E.g., if l = 2 (defined as a d orbital), ml = –2, –1, 0, 1, or 2.

p orbitals

d orbitals

f orbitals

54

Chapter 6

Magnetic Quantum Number, ml

The number of allowed values of ml for a particular subshell (l) reveal the total number of possible arrangements (orientations):

1 arrangement for an s type (l = 0) orbital (ml =0)

3 arrangements for a p type (l = 1) orbital (ml = –1, 0, 1)

5 arrangements for a d type (l = 2) orbital (ml = –2, –1, 0, 1, 2)

7 arrangements for a f type (l = 3) orbital (ml = –3, –2, –1, 0, 1, 2, 3)

And so on…

s orbital

ml=0

ml= –1, 0 or 1

ml= –2, –1, 0, 1 or 2

ml= –3, –2, –1, 0,

1, 2 or 3

l=0

l=1

l=2

l=3

55

Chapter 6

Part of 4.) Subshell Quantum Numbers: Summary of the Last Few Slides

Type of subshell mℓ ( ±ℓ ) Number of arrangements (orientations)
0 s 0 1
1 p –1, 0, 1 3
2 d –2, –1, 0, 1, 2 5
3 f –3, –2, –1, 0, 1, 2, 3 7

Let’s talk about the SHAPES of each of these orbitals, or subshells!

55

s orbitals (ℓ =0)

The shape of an s orbital is a sphere (just one possible orientation!)

Orbital available for all values of n

The number before the orbital name designates the energy level/shell number, n (e.g., 2s is an s-orbital that is in the 2nd energy level/shell)

As n increases, the size of the s orbital spheres get larger increasing energy level, increasing distance

56

Chapter 6

s Orbitals

1s

3s

2s

56

57

Chapter 6

The Three p Orbitals

p orbitals (ℓ =1) are possible in energy level n=2 or higher.

Shaped like two identical balloons tied together at the nucleus (or, like a dumbbell or hourglass!)

Direction given by third quantum number, mℓ

Possible ml values are –1, 0, 1  three values means there are three different orientations

The number before the orbital name designates the energy level/shell number, n (e.g., 2p is a p-orbital that is in the 2nd energy level)

 Composite view = depiction of p-orbitals arranged at 90o angles to each other along the x, y, and z axes

57

58

Chapter 6

The Five d Orbitals

d orbitals (ℓ =2) are possible in energy level n=3 or higher.

Possible ml values are –2, –1, 0, 1, 2 Five values means there are five different orientations

Four of them are shaped like four identical balloons tied together at the nucleus (or, like a four-leaf clover!)

The other looks like a p-orbital inside a donut

The number before the orbital name designates the energy level/shell number, n (e.g., 3d is a d-orbital that is in the 3rd energy level)

58

59

Chapter 6

The Seven f Orbitals

f orbitals (ℓ =3) are possible in energy level n=4 or higher.

Possible ml values are –3, –2, –1, 0, 1, 2, 3 Seven values means there are seven different orientations

By far some of the most exotic-looking shapes we have seen so far! Some are shaped like eight identical balloons tied together at the nucleus (or, like an octopus); another looks like a p-orbital inside two donuts

59

60

Chapter 6

Orbital Nodes

Just as standing waves have nodes, orbitals do, too!

In the context of orbitals, nodes are regions of zero electron density (i.e., where the probability of finding an electron is always 0).

There are two types of nodes that orbitals can have: radial nodes and angular nodes. In this course, we’ll only discuss angular nodes.

The number of angular nodes that an orbital has is equal to the orbital angular quantum number, l

# angular nodes = l

node

60

61

Chapter 6

Number of Angular Nodes = l

Each s orbital (l = 0) has zero angular nodes

Each p orbital (l = 1) has one angular node (i.e., one angle at which the probability of finding an electron is always zero)

Each d orbital (l = 2) has two angular nodes (two angles at which the probability of finding an electron is always zero)

Each f orbital (l = 3) has three angular nodes (three angles at which the probability of finding an electron is always zero)

And so on…

https://lavelle.chem.ucla.edu/forum/viewtopic.php?t=34046; https://socratic.org/questions/the-orientation-in-space-of-an-atomic-orbital-is-associated-with-what

61

Type of subshell (and representative sketch) Number of angular nodes mℓ ( ±ℓ ) Number of arrangements (orientations)
0 s 0 0 1
1 p 1 –1, 0, 1 3
2 d 2 –2, –1, 0, 1, 2 5
3 f 3 –3, –2, –1, 0, 1, 2, 3 7

Chapter 6

Rest of 4.) Subshell Quantum Numbers

Chapter 6

Quantum numbers: Study chart

n ℓ (0 through n-1) mℓ ( ±ℓ ) Subshell designation
1 0 0 1s
2 0 0 2s
1 –1, 0, 1_ 2p
3 0 0__ 3s
1 –1, 0, 1__ 3p
2 –2, –1, 0, 1, 2__ 3d
4 0 0____ 4s
1 –1, 0, 1____ 4p
2 –2, –1, 0, 1, 2____ 4d
3 –3, –2, –1, 0, 1, 2, 3___ 4f

5.) Identify the subshell (orbital, e.g., 3p) in which electrons with the following quantum numbers are found:

(a) n = 2, ℓ = 1

(b) n = 4, ℓ = 2

(c) n = 5, ℓ = 0

64

Chapter 6

Quantum Numbers: Practice

n = 2 means that this orbital is in the 2nd energy level

ℓ = 1 means that this is a p-orbital

And so, the subshell is 2p.

5.) Identify the subshell (orbital, e.g., 3p) in which electrons with the following quantum numbers are found:

(a) n = 2, ℓ = 1

(b) n = 4, ℓ = 2

(c) n = 5, ℓ = 0

65

Chapter 6

Quantum Numbers: Practice

n = 2 means that this orbital is in the 2nd energy level

ℓ = 1 means that this is a p-orbital

And so, the subshell is 2p.

n = 4 means that this orbital is in the 4th energy level

ℓ = 2 means that this is a d-orbital

And so, the subshell is 4d.

n = 5 means that this orbital is in the 5th energy level

ℓ = 0 means that this is an s-orbital

And so, the subshell is 5s.

Which of these is a valid set of quantum numbers to describe a 5d orbital?

A) n = 5, ℓ = 2, mℓ = +3 B) n = 5, ℓ = 3, mℓ = +2

C) n = 5, ℓ = 2, mℓ = +1 D) n = 5, ℓ = 1, mℓ = 0

66

Chapter 6

Quantum Numbers: Practice

Chapter 6

Chapter 2

Chapter 2

Poll Question #2

66

Which of these is a valid set of quantum numbers to describe a 5d orbital?

A) n = 5, ℓ = 2, mℓ = +3 B) n = 5, ℓ = 3, mℓ = +2

C) n = 5, ℓ = 2, mℓ = +1 D) n = 5, ℓ = 1, mℓ = 0

Let’s dissect this question piece-by-piece.

Starting with the “5” part of “5d,” we know this orbital is in the 5th energy level, so n must equal 5 (n = 5). Can’t eliminate any answer choice yet.

Moving on to the “d” component, we know that a d orbital means that ℓ = 2. And so, we can eliminate choices B and D.

Finally, regarding the orientation or arrangement) of this orbital, as indicated by quantum number mℓ, we know that mℓ = ± ℓ, and so all possible values for mℓ = −2, −1, 0, 1, 2. And so, we can eliminate choice A.

67

Chapter 6

Quantum Numbers: Practice

Chapter 6

Chapter 2

Chapter 2

Poll Question #2

67

Which of these is a valid set of quantum numbers to describe a 5d orbital?

A) n = 5, ℓ = 2, mℓ = +3 B) n = 5, ℓ = 3, mℓ = +2

C) n = 5, ℓ = 2, mℓ = +1 D) n = 5, ℓ = 1, mℓ = 0

Let’s dissect this question piece-by-piece.

Starting with the “5” part of “5d,” we know this orbital is in the 5th energy level, so n must equal 5 (n = 5). Can’t eliminate any answer choice yet.

Moving on to the “d” component, we know that a d orbital means that ℓ = 2. And so, we can eliminate choices B and D.

Finally, regarding the orientation or arrangement) of this orbital, as indicated by quantum number mℓ, we know that mℓ = ± ℓ, and so all possible values for mℓ = −2, −1, 0, 1, 2. And so, we can eliminate choice A.

Answer is C!

68

Chapter 6

Quantum Numbers: Practice

Chapter 6

Chapter 2

Chapter 2

Poll Question #2

68

Whereas 3 quantum numbers are sufficient to describe an atomic orbital (n, l, ml), an additional quantum number (called ms) becomes necessary to describe an electron that occupies the orbital.

History – not all spectral features could be explained by wave equations:

Experiments involving the emission spectra of hydrogen and sodium atoms indicated that each line in the emission spectra could be split into TWO lines by the application of an external magnetic field!

Chapter 6

The Spin Magnetic Quantum Number ms

The only way physicists could explain these results was to assume that electrons act like tiny spinning magnets

According to electromagnetic theory, a spinning charge generates a magnetic field, and it is that motion that causes an electron to behave like a magnet

The magnitude of the overall electron spin can have only one value, and an electron can only spin in one of two quantized states

4th quantum number (ms) describes electron spin: ms = +½ or –½

An orbital can contain a maximum of only 2 electrons

Two electrons within the same orbital must have opposite spins (referred to as “paired spins”)

Chapter 6

The Spin Magnetic Quantum Number ms

Spin

–½

(down)

Spin

(up)

+½ or –½ are the 2 fundamental spin states of an electron in an orbital.

70

The “atomic address” of a specific electron can only be completely described if all 4 quantum numbers are known

Example:

n = 3, l = 1, ml = 0, ms = +½

Describes an electron in a p orbital of the 3rd energy level that has an ml = 0 and a +½ spin.

71

Chapter 6

The Four Quantum Numbers

** Note that 4s is lower in energy than 3d ** (I’ll show you why soon!)

The energy of atomic orbitals increases as the principal quantum number, n, increases

In any atom with two or more electrons, the repulsion between electrons leads to the splitting of energy levels

– In other words, electrostatic repulsions between electrons leads to the splitting of a shell (n) into subshells (l) of different energies (e.g., 2p is at a higher energy level than 2s).

72

Chapter 6

Orbital Energies

Atomic orbitals are represented by lines or boxes and are occupied by electrons

Electrons are represented by arrows: or

A maximum of 2 electrons can fill each orbital

Electrons fill orbitals in predictable ways

3 rules:

Aufbau Principle

Pauli Exclusion Principle

Hund’s Rule

Chapter 6

Rules for Electrons Filling Orbitals

73

1.) Aufbau Principle

When e− fill atomic orbitals, they fill the lowest energy orbitals (closest to the nucleus) first.

From the German word aufbau = “to build up”

“Diagonal rule”

Chapter 6

Where are the Electrons? 3 Rules

1s

2s

3s

4s

5s

6s

7s

2p

3p

4p

5p

6p

3d

4d

5d

4f

1s

2s

2p

3s

3p

4s

3d

4p

5s

4d

5p

6s

4f

5d

6p

7s etc.

(Please don’t memorize this order! Just use the diagonal rule!)

Order of the orbital energy levels (low  high energy)

74

5f

6d

7p

Example: if we had 10 electrons to fill:

2.) Pauli Exclusion Principle

Each orbital can only contain up to two electrons

Example: or

If paired up, electrons must be of opposite spins

Chapter 6

Where are the Electrons? 3 Rules

75

Example: if we had 10 electrons to fill:

Thought Question: Why only 2 electrons?

76

Chapter 6

Thought Question

Why can each orbital contain a maximum of only two electrons?

77

Chapter 6

Thought Question

Why can each orbital contain a maximum of only two electrons?

Because no two electrons in the same atom can have the same four quantum numbers (n, l, ml, ms)! (Pauli Exclusion Principle)

– And so, if two electrons have the same n, l, and ml, (meaning that they occupy the same orbital), then they must have different values of ms: that is, one with an ms of +½ and the other with an ms of –½.

– Because there are only two possible values for ms, and no two electrons in the same orbital can have the same value for ms, only two electrons can occupy the same atomic orbital.

This is also why electrons in the same orbital must have opposite spins ( ) – you can’t have two electrons in the same orbital with the same ms value! (i.e., can’t have or )

No two electrons in the same atom can have identical sets of quantum numbers  therefore, no two electrons in the same atom can have exactly the same energy.

77

78

Chapter 6

Where are the Electrons? 3 Rules

Example: if we had 10 electrons to fill:

2.) Pauli Exclusion Principle

Each orbital can only contain up to two electrons

Example: or

If paired up, electrons must be of opposite spins

Determines the max # of e− allowed in each orbital:

2 electrons in s  1 possible orientation

6 electrons in p  3 possible orientations

10 electrons in d  5 possible orientations

Example: if we had 10 electrons to fill:

3.) Hund’s Rule

Electrons fill orbitals of equivalent energy one at a time, and then pair up

Orbitals of equivalent energy (same n and l) are said to be degenerate.

Examples of degenerate orbitals:

The three p orbitals: same size (n=2) and shape (l =1) but pointing different directions (ml = −1,0,1).

The five d orbitals

The seven f orbitals

Chapter 6

Where are the Electrons? 3 Rules

4f

Equivalent energy (degenerate orbitals) = same energy level on y-axis of graph

79

Example: if we had 10 electrons to fill:

3.) Hund’s Rule

Basic take-away: When electrons fill degenerate orbitals, they pair only if they have to

Sometimes called the “bus seat” rule, because strangers boarding buses don’t sit next to anyone unless they must!

Chapter 6

Where are the Electrons? 3 Rules

1s

2s

2p

 orbital diagram (pictorial representation of electronic configuration)

Equivalent energy (degenerate orbitals) = same energy level on y-axis of graph

80

An atom’s electron configuration tells the arrangement of electrons in all orbitals

There are multiple ways to write electron configuration. You will need to know both ways:

orbital diagram

spdf notation

81

Chapter 6

Writing Electron Configurations in Atoms

*

82

Chapter 6

Orbital Diagram Notation

Each box is one orbital

Each box is labeled with the principal quantum number (n) and type of orbital (s, p, d, f, etc.) and arranged in order of increasing energy (based on Aufbau Principle)

Boxes for degenerate orbitals are connected

Each arrow represents 1 electron

Direction of arrow (up vs down) indicates spin direction

Remember to follow Hund’s rule:

Fill degenerate orbitals with unpaired electrons first, then pair with opposite spins

How many unpaired electrons are there in a sodium (Z=11) atom?

83

Chapter 6

7.) Examples: Orbital Diagrams

1s

2s

Lithium (3Li)

1s

2s

2p

Carbon (6C)

1s

2s

2p

Neon (10Ne)

83

How many unpaired electrons are there in a sodium (Z=11) atom?

Chapter 6

7.) Examples: Orbital Diagrams

1s

2s

Lithium (3Li)

1s

2s

2p

Carbon (6C)

1s

2s

2p

Neon (10Ne)

1s

2s

2p

Sodium (11Na)

3s

One unpaired electron!

84

An atom’s electron configuration tells the arrangement of electrons in all orbitals

There are multiple ways to write electron configuration. You will need to know both ways:

orbital diagram ✅

spdf notation

85

Chapter 6

Writing Electron Configurations in Atoms

*

86

Chapter 6

spdf Notation

1

1

s

value of n (shell)

value of l (subshell)

number of

electrons

1s

Orbital diagram

spdf notation

The written distribution of electrons among various orbitals in an atom

Instead of using an arrow to visually represent electrons (orbital diagram notation), the number of electrons in spdf notation are written as superscripts above the subshell

Example: Hydrogen (1H)

86

Chapter 6

7.) Practice: Writing spdf Notation

1s

2s

2p

Lithium (3Li)

1s

2s

2p

Carbon (6C)

1s

2s

2p

1s

2s

2p

Sodium (11Na)

3s

Orbital diagram

spdf notation

1s22s1

Neon (10Ne)

87

Chapter 6

1s

2s

2p

Lithium (3Li)

1s

2s

2p

Carbon (6C)

1s

2s

2p

Neon (10Ne)

1s

2s

2p

Sodium (11Na)

3s

1s22s22p2

1s22s1

1s22s22p6

1s22s22p63s1

Orbital diagram

spdf notation

7.) Practice: Writing spdf Notation

88

89

Chapter 6

Basis for spdf Notation: The Periodic Table!

The arrangement of the periodic table is based on electronic configurations!

Alternative to Aufbau Principle for determining electron configuration.

Just begin at hydrogen (Z = 1) and include each subshell as you “build up” in increasing atomic number!

1s

2s

3s

4s

5s

6s

7s

2p

3p

4p

5p

6p

3d

4d

5d

4f

5f

6d

7p

(Aufbau Principle)

89

90

Basis for spdf Notation: The Periodic Table!

1

2

3

4

5

6

7

Elements can be grouped into “blocks” according to the type of subshell (s, p, d, or f) being filled with electrons.

90

91

Basis for spdf Notation: The Periodic Table!

* learn this!*

Noble Gas Configuration

An abbreviated version of spdf notation

Method: replace the closest preceding noble gas with its bracketed chemical symbol, then finish configuration.

Examples:

Sodium (11Na) = [Ne]3s1

Titanium (22Ti) = [Ar]4s2 3d2

92

Chapter 6

Electron Configuration “Shorthand”

Chapter 6

1s

2s

2p

Lithium (3Li)

1s

2s

2p

Carbon (6C)

1s

2s

2p

1s

2s

2p

Sodium (11Na)

3s

Orbital diagram

7.) Practice: Writing Noble Gas Configuation

spdf notation

Noble gas config.

[He] 2s1

Neon (10Ne)

1s22s22p2

1s22s1

1s22s22p6

1s22s22p63s1

93

Chapter 6

1s

2s

2p

Lithium (3Li)

1s

2s

2p

Carbon (6C)

1s

2s

2p

Neon (10Ne)

1s

2s

2p

Sodium (11Na)

3s

1s22s22p2

1s22s1

1s22s22p6

1s22s22p63s1

Orbital diagram

spdf notation

7.) Practice: Writing Noble Gas Configuation

Noble gas config.

[He] 2s1

[He] 2s22p2

[He] 2s22p6

= [Ne]

[Ne] 3s1

94

Paramagnetic. The physical property of being attracted to a magnetic field.

Property arises due to unpaired electrons in orbitals: the unpaired electron is attracted to a magnet

Diamagnetic. The physical property of being slightly repelled by a magnetic field.

Arises due to paired electrons in orbitals.

Two electrons in an orbital act like magnets paired to each other; it would cost them energy to pull apart from each other to adjust to an external magnet.

95

Chapter 6

Paramagnetic vs. Diamagnetic Elements

https://i.redd.it/xoebllg20bu01.png

Chapter 6

1s

2s

2p

Lithium (3Li)

1s

2s

2p

Carbon (6C)

1s

2s

2p

Neon (10Ne)

1s

2s

2p

Sodium (11Na)

3s

Unpaired electron ∴ paramagnetic

Orbital diagram

Paramagnetic or Diamagnetic?

7.) Practice: Paramagnetic or Diamagnetic?

96

Chapter 6

1s

2s

2p

Lithium (3Li)

1s

2s

2p

Carbon (6C)

1s

2s

2p

Neon (10Ne)

1s

2s

2p

Sodium (11Na)

3s

Unpaired electron ∴ paramagnetic

Orbital diagram

Paramagnetic or Diamagnetic?

7.) Practice: Paramagnetic or Diamagnetic?

Unpaired electrons ∴ paramagnetic

All electrons are paired ∴ diamagnetic

Unpaired electron ∴ paramagnetic

97

Are any elements unusual below?

98

Chapter 6

Electron Configuration for Transition Metals

Are any elements unusual below?

99

Chapter 6

Electron Configuration for Transition Metals

Half-filled or filled sets of degenerate orbitals lower the energy of the atom.

Electrons in orbitals close in energy might spread out to reach a half-filled or filled arrangement

Fill d before s for these exceptions

Sc

Ti

V

Cr

Mn

Fe

Co

Ni

Cu

Zn

100

Chapter 6

Electron Configuration Exceptions

100

Figure: 08-02-09UN

Title:

Electron configurations of the first transition series elements

Caption:

The electron configurations of the first transition series elements show that these elements generally follow the predicted sequence of filling of subshells. For those that violate the rules, the energy of the subshells must be different for these particular cases because electrons fill the lowest energy orbitals first.

Notes:

The two main exceptions to the prediction occur with Cr and Cu. In the case of Cr, both the 4s and the 3d orbitals are half-filled. In the case of Cu, the 3d orbital is completely filled, leaving only the 4s half filled.

Which element below do you expect to have a ground state electron configuration that breaks the Aufbau principle (like Cr or Cu)?

A.) Zr

B.) Nb

C.) Mo

D.) Tc

101

Chapter 6

Electron Configuration Exceptions

Chapter 6

Chapter 6

Chapter 2

Chapter 2

Poll Question #3

Which element below do you expect to have a ground state electron configuration that breaks the Aufbau principle (like Cr or Cu)?

A.) Zr

B.) Nb

C.) Mo [Kr]4d55s1

D.) Tc

102

Chapter 6

Electron Configuration Exceptions

Chapter 6

Chapter 6

Chapter 2

Chapter 2

Poll Question #3

Elements in the same vertical column of the periodic table tend to share similar properties

Scientist Spotlight Lauryn “Wren” Gibbs

Undergraduate Research Assistant, Department of Chemistry and Chemical Biology, Cornell University (Ithaca, NY) Topic: Metals (3d block) Favorite quote: “If I am worth anything later, I am worth something now. For wheat is wheat, even if people think it is a grass in the beginning." ~Vincent Van Gogh

Completely filled shells (n levels) are especially stable

Electrons in completely filled shells are called “core” electrons

Core electrons don’t contribute to the chemical behavior of the element (but they’re still important to count)

The number of electrons in the outermost shell of a particular atom determines its reactivity, or tendency to form chemical bonds with other atoms.

This outermost shell is known as the valence shell, and the electrons found in it are called valence electrons

Valence e− are available for chemical rxns

Can be predicted from location on periodic table

104

Chapter 6

Core vs. Valence Electrons

https://o.quizlet.com/F8wkjcHut17E5hdQ.E9.zg.png

Valence electrons are the outermost electrons that are responsible for most chemical properties and are the same within a family

Valence electrons are all the electrons after the noble gas in the abbreviation with the highest n (e.g., Br has seven valence electrons: [Ar]4s2 3d104p5)

105

Chapter 6

Valence Electrons and Chemistry

Formation of ions: The gain or loss of valence electrons to achieve stable electron configuration (completely filled shell).

Cations:

Na(g) → Na+(g) + e–

[Ne]3s1 → [Ne] + e–

Anions:

Cl(g) + e– → Cl–(g)

[Ne]3s23p5 + e– → [Ne]3s23p6 = [Ar]

Isoelectronic – describes atoms/ions having identical electron configurations.

K+, Cl–, Ca2+, Ar = 1s22s22p63s23p6

106

Chapter 6

Electron Configurations and Ion Formation

106

Which one of the following species is not isoelectronic with neon?

A. Mg2+

B. Na+

C. O2-

D. S2-

E. Al3+

107

Chapter 6

Chapter 6

Chapter 6

Chapter 6

Chapter 2

Chapter 2

Poll Question #4

Isoelectronic Species

Which one of the following species is not isoelectronic with neon?

A. Mg2+

B. Na+

C. O2-

D. S2-

E. Al3+

108

Chapter 6

[Ne] = 1s22s22p6 = 10 electrons

Mg2+ = (12 − 2) e− = 10 electrons

Na+ = (11 − 1) e− = 10 electrons

O2− = (8 + 2) e− = 10 electrons

S2− = (16 + 2) e− = 18 electrons

Al3+ = (13 − 3) e− = 10 electrons

Chapter 6

Chapter 6

Chapter 6

Chapter 2

Chapter 2

Poll Question #4

Isoelectronic Species

Transition metal cations lose electrons with highest n first

Loss of s electrons first and then d electrons

Examples:

Fe: [Ar] 4s23d6

Fe2+ = [Ar]3d6

Fe3+ = [Ar]3d5

(loss of s orbital e–)

(loss of one 3d = half-filled d subshell, stable configuration for Fe)

109

Chapter 6

Cations of Transition Metals

Demonstrate with orbital box

109

Physical Properties

Atomic Radius (atomic size)

Ionic Radius: The radius of an ion

Ionization Energy

Electron Affinity / Electronegativity

Periodic Trends in Chemical Properties

Periodic trends in reactivity of metals vs nonmetals

110

Chapter 7

Chapter 7: Periodic Trends (Periodicity)

Size increases going down a group.

Size decreases going across a period.

111

Chapter 7

The size of an atom is expressed as atomic radius

Periodic Trends in Atomic Radius

Why?

As we move down the periodic table, size increases because electrons are placed in higher energy orbitals further from the nucleus (n increases aka number of shells increase, thus expanding the size of the atom)

Electrons between valence electrons and nucleus decrease +/- charge attraction (shielding)

112

Atomic Radius Increases Down a Group

Chapter 7

Shielding – when inner electrons partially shield the outer electrons from the pull of the nucleus

112

Size decreases across a period due to an increase in apparent nuclear charge (Z*, or Zeff). The shell is the same (same value of n), but each successive element has one more proton than the last.

Each added electron in the outer shell feels a greater and greater (+) charge and pull toward the radius, leading to a decrease in size across a row.

113

Atomic Radius Decreases Across a Period

Chapter 7

113

Size increases going down a group.

Size decreases going across a period.

114

Atomic Radius Explanation

Due to increasing # of shells

Due to increasingly positive nucleus going right 

Why?

Chapter 7

115

Chapter 6

Ionic Radius: Cations

Do you think the size of an atom goes up or down when it loses an electron to form a cation?

A.) Size goes up (atom gets bigger)

B.) Size goes down (atom gets smaller)

Chapter 6

Chapter 6

Chapter 6

Chapter 6

Chapter 2

Chapter 2

Poll Question #5

?

Li, 152 pm

3e− and 3p

Li

+

2e− and 3p

116

Chapter 6

Ionic Radius: Cations

Do you think the size of an atom goes up or down when it loses an electron to form a cation?

A.) Size goes up (atom gets bigger)

B.) Size goes down (atom gets smaller)

?

Chapter 6

Chapter 6

Chapter 6

Chapter 6

Chapter 2

Chapter 2

Poll Question #5

Li, 152 pm

3e− and 3p

Li

+

2e− and 3p

, 78 pm

117

Ionic Radius: Cations

Li, 152 pm

3e− and 3p

Li

+

2e− and 3p

+

CATIONS are SMALLER than the atoms they come from.

One of the more electrons are taken out of the largest outermost orbital, leaving electrons in the smaller inner orbitals

There are the same number of protons pulling on fewer electrons. The stronger attraction pulls electrons closer in towards the nucleus, so size DECREASES.

Chapter 7

F, 71 pm

9e− and 9p

F

10e− and 9 p

118

Chapter 6

Ionic Radius: Anions

Do you think the size of an atom goes up or down when it gains an electron to form an anion?

A.) Size goes up (atom gets bigger)

B.) Size goes down (atom gets smaller)

Chapter 6

Chapter 6

Chapter 6

Chapter 6

Chapter 2

Chapter 2

Poll Question #5

?

F, 71 pm

9e− and 9p

F

10e− and 9 p

119

Chapter 6

Ionic Radius: Anions

Do you think the size of an atom goes up or down when it gains an electron to form an anion?

A.) Size goes up (atom gets bigger)

B.) Size goes down (atom gets smaller)

Chapter 6

Chapter 6

Chapter 6

Chapter 6

Chapter 2

Chapter 2

Poll Question #5

?

, 133 pm

-

120

F, 71 pm

9e− and 9p

F

10e− and 9 p

Ionic Radius: Anions

ANIONS are LARGER than the atoms they come from.

One or more electrons are added to the outermost orbital, but the number of protons stays the same.

Since each proton is now pulling on more electrons, it attracts each electron less strongly, so the size of the electron cloud INCREASES.

Chapter 7

121

Periodic Trends in Ionic Radius

Periodic trends in ion sizes across the periodic table follow the same trends in atomic sizes, noting differences between cations and anions

Chapter 7

Ionization energy is the energy required to remove an electron from an atom

122

Periodic Trends in Ionization Energy (IE)

What trend do you observe in 1st IE moving across a period?

Chapter 7

Equation for ionization of Mg

122

Ionization energy is the energy required to remove an electron from an atom

123

Periodic Trends in Ionization Energy (IE)

What trend do you observe in 1st IE moving across a period?

Ionization energy increases due to valence shell stability (a full valence shell = very stable atom; it doesn’t want to lose electrons!)

What trend do you observe in 1st IE moving down a group?

Ionization energy decreases as n increases large atoms easily lose electrons (shielding)

Chapter 7

Equation for ionization of Mg

123

124

Periodic Trends in Electron Affinity (EA)

Electron Affinity is the tendency of an atom to attract an electron

The more negative the EA, the stronger the atom’s tendency to gain an electron

You can think of the concept of EA as being the opposite of ionization energy (lose vs. gain electrons)

Electron affinity is low for metals Not favorable to pick up electrons

Electron affinity is high for non-metals (especially halogens!)  Very favorable to pick up electrons to get a stable shell

Chapter 7

Electronegativity (Χ): A measure of an atom’s ability to attract electrons to itself

Uses an arbitrary scale from 0 (lowest) to 4 (highest)

An atom with Χ near zero has almost no ability to attract e−

An atom with Χ near four has a very strong ability to attract e−.

Since electronegativity and electron affinity are two different scales to measure the same tendency, the two periodic trends are the same.

125

Electronegativity

Fluorine = the most electronegative atom! (attracts electrons the most! Wants that stable shell)

Cs and Fr = least electronegative

Chapter 7

126

Note: Same trend for ionization energy and electron affinity but mean opposite things

If IE is high, difficult to remove electron

If EA is high, easy to pick up electron

9.) Summary of Periodic Trends

https://www.thoughtco.com/chart-of-periodic-table-trends-608792

/ Reactivity

/ Reactivity

Chapter 7

Ionic radius (size) increases as you move down a group.

Electronegativity (ability of an atom to attract electrons to itself) decreases as you move down a group.

Metal reactivity (tendency to lose electrons) should increase as you move down a group.

What do you predict is the most reactive metal in the alkali metal series Li, Na, K?

127

Reactivity Trends for Metals

Chapter 7

Ionic radius (size) increases as you move down a group.

Electronegativity (ability of an atom to attract electrons to itself) decreases as you move down a group.

Metal reactivity (tendency to lose electrons) should increase as you move down a group.

What do you predict is the most reactive metal in the alkali metal series Li, Na, K?

Potassium (K)

128

Reactivity Trends for Metals

Chapter 7

Ionic radius (size) increases as you move down a group.

Electronegativity (ability of an atom to attract electrons to itself) decreases as you move down a group.

Non-metal reactivity (tendency to gain electrons) should decrease as you move down a group.

What do you predict is the most reactive nonmetal in the halogen series F, Cl, Br, I?

129

Reactivity Trends for Non-Metals

Chapter 7

Ionic radius (size) increases as you move down a group.

Electronegativity (ability of an atom to attract electrons to itself) decreases as you move down a group.

Non-metal reactivity (tendency to gain electrons) should decrease as you move down a group.

What do you predict is the most reactive nonmetal in the halogen series F, Cl, Br, I?

Fluorine (F)

130

Reactivity Trends for Non-Metals

Chapter 7

131

Periodic Reactivity

https://www.youtube.com/watch?v=EO1YgSW2tTY

Chapter 7

Fig. 7.3, p.299

λ = 2.869 m

l = 2.869 m

c = λν 2.998 × 108 m*s−1 = λ(1.045 × 108 s−1)

c = ln

2.998 ´ 10

8

m*s

-1

= l(1.045 ´ 10

8

s

-1

)

1.045 × 108 s−1 = 1.045 × 108 s−1

1.045 ´ 10

8

s

-1

= 1.045 ´ 10

8

s

-1

104.5 MHz × 10 6 Hz

1 MHz = 1.045 × 108 Hz = 1.045 × 108 s−1

104.5 MHz ´

10

6

Hz

1 MHz

= 1.045 ´ 10

8

Hz = 1.045 ´ 10

8

s

-1

ν = 4.38 × 1014 s−1

= 4.38 × 1014 Hz

n = 4.38 ´ 10

14

s

-1

= 4.38 ´ 10

14

Hz

685 nm× 1 m 109 nm

= 6.85 × 10−7 m

685 nm´

1 m

10

9

nm

=6.85 ´ 10

-7

m

c = λν 2.998 × 108 m*s−1 = (6.85 × 10−7 m)(ν )

c = ln

2.998 ´ 10

8

m*s

-1

= (6.85 ´ 10

-7

m)(n)

6.85 × 10−7 m = 6.85 × 10−7 m

6.85 ´ 10

-7

m = 6.85 ´ 10

-7

m

1 λ = 1.097×10−2 nm−1 1

nfinal 2

– 1

ninitial 2

⎝ ⎜

⎠ ⎟

1

l

= 1.097´10

-2

nm

-1

1

n

final

2

1

n

initial

2

æ

è

ç

ö

ø

÷

ΔE = Efinal – Einitial = – 2.178×10 −18 J

1 nfinal 2

– 1

ninitial 2

⎝ ⎜

⎠ ⎟

DE = E

final

– E

initial

= –2.178´10

-18

J

1

n

final

2

1

n

initial

2

æ

è

ç

ö

ø

÷

1 λ = 1.097×10−2 nm−1 1

nfinal 2

– 1

ninitial 2

⎝ ⎜

⎠ ⎟

1

l

= 1.097´10

-2

nm

-1

1

n

final

2

1

n

initial

2

æ

è

ç

ö

ø

÷

1 λ = 1.097×10−2 nm−1 1

42 –

1 22

⎛ ⎝⎜

⎞ ⎠⎟

1

l

= 1.097´10

-2

nm

-1

1

4

2

1

2

2

æ

è

ç

ö

ø

÷

1 λ = 1.097×10−2 nm−1 – 0.1875( )

1

l

= 1.097´10

-2

nm

-1

– 0.1875

()

λ = 486.2 nm

l = 486.2 nm

1 λ = −0.002057nm−1

1

l

= -0.002057nm

-1

1 λ = 0.002057 nm−1

1

l

= 0.002057 nm

-1

1 = (0.002057nm−1)λ

1 = (0.002057nm

-1

)l

0.002057nm−1 0.002057nm−1

0.002057nm

-1

0.002057nm

-1

E = 4.086×10−19 J

E = 4.086´10

-19

J

486.2×10−9 m 486.2×10−9 m

486.2´10

-9

m 486.2´10

-9

m

ΔE = Efinal – Einitial = – 2.178×10 −18 J

1 42

– 1 22

⎛ ⎝⎜

⎞ ⎠⎟

DE = E

final

– E

initial

= –2.178´10

-18

J

1

4

2

1

2

2

æ

è

ç

ö

ø

÷

ΔE = Efinal – Einitial = – 2.178×10 −18 J –0.1875( )

DE = E

final

– E

initial

= –2.178´10

-18

J –0.1875

()

ΔE = Efinal – Einitial = 4.084 × 10 −19 J

DE = E

final

– E

initial

= 4.084 ´ 10

-19

J

λ = 486.2 nm

l = 486.2 nm

c = λν 2.998 × 108 m*s−1 = (486.2 × 10−9 m)(ν )

c = ln

2.998 ´ 10

8

m*s

-1

= (486.2 ´ 10

-9

m)(n)

ν = 6.166 × 1014 s−1

n = 6.166 ´ 10

14

s

-1

E = (6.626×10−34 J*s)(6.166×1014 s−1)

E = (6.626´10

-34

J*s)(6.166´10

14

s

-1

)

E = hν

E = hn

ν = c λ

n =

c

l

h c λ

⎛ ⎝⎜

⎞ ⎠⎟ = mc2

h

c

l

æ

è

ç

ö

ø

÷

= mc

2

h v λ

⎛ ⎝⎜

⎞ ⎠⎟ = m v( )2

h

v

l

æ

è

ç

ö

ø

÷

= mv

()

2

λ = hv mv2

= hv mv*v

l =

hv

mv

2

=

hv

mv*v

λ = h mv

l =

h

mv

− h 2

8π 2m 1 r2

∂ ∂r

r2 ∂ψ ∂r

⎛ ⎝⎜

⎞ ⎠⎟ + 1 r2 sinθ

∂ ∂θ

sinθ ∂ψ ∂θ

⎛ ⎝⎜

⎞ ⎠⎟ + 1 r2 sin2θ

∂ 2ψ ∂φ 2

⎣ ⎢ ⎢

⎦ ⎥ ⎥ +V r ,θ ,φ( )ψ = Eψ

-

h

2

8p

2

m

1

r

2

¶r

r

2

¶y

¶r

æ

è

ç

ö

ø

÷

+

1

r

2

sinq

¶q

sinq

¶y

¶q

æ

è

ç

ö

ø

÷

+

1

r

2

sin

2

q

2

y

¶f

2

é

ë

ê

ê

ù

û

ú

ú

+Vr,q,f

()

y=Ey

p.362

p.362