Operations and Supply Chain Management
Week 4
Chapter 12
Inventory Management
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1
Learning Objectives
1 Conduct an A B C analysis
2 Explain and use cycle counting
3 Explain and use the E O Q model for independent inventory demand
4 Compute a reorder point and explain safety stock
5 Apply the production order quantity model
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2
Inventory Management
The objective of inventory management is to strike a balance between inventory investment and customer service
Importance of Inventory
One of the most expensive assets of many companies representing as much as 50% of total invested capital
Less inventory lowers costs but increases chances of shortages, which might stop processes or result in dissatisfied customers
More inventory raises costs but improves the likelihood of meeting process and customer demands
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Types of Inventory
Raw material
Purchased but not processed
Work-in-process (W I P)
Undergone some change but not completed
A function of flow time for a product
Maintenance/repair/operating (M R O)
Necessary to keep machinery and processes productive
Finished goods
Completed product awaiting shipment
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4
The Material Flow Cycle
Managing Inventory
How inventory items can be classified (A B C analysis)
How accurate inventory records can be maintained
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5
A B C Analysis (1 of 4)
Divides inventory into three classes based on annual dollar volume
Class A – high annual dollar volume
Items may represent 15% of the total items
Represent 70%-80% of the total dollar volume
Class B - medium annual dollar volume
Items may represent 30% of the total items
Represent 15%-25% of the total dollar volume
Class C - low annual dollar volume
Items may represent 55% of the total items
Represent 5% of the total dollar volume
ABC categories need not be exact.
Used to establish policies that focus on the few critical parts and not the many trivial ones
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6
A B C Analysis (2 of 4)
Figure 12.2
Class A – 15% of the total items
70%-80% of the total dollar volume
Class B - 30% of the total items
15%-25% of the total dollar volume
Class C - 55% of the total items
5% of the total dollar volume
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7
A B C Analysis (3 of 4)
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8
A B C Analysis (4 of 4)
Other criteria than annual dollar volume may be used
High shortage or holding cost
Anticipated engineering changes
Delivery problems
Quality problems
Policies employed may include
More emphasis on supplier development for A items
Tighter physical inventory control for A items
More care in forecasting A items
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9
Exercise
Your company has compiled the following data on the small set of products that comprise the specialty repair parts division.
Perform ABC analysis on the data.
Over which product do you suggest the firm keep the tightest control?
| SKU | Annual Demand | Unit Cost |
| R11 | 125 | $25 |
| S22 | 55 | $90 |
| T33 | 100 | $500 |
| U44 | 150 | $550 |
| V55 | 2000 | $4 |
Answer: D
A) R11
B) S22
C) T33
D) U44
E) V55
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Exercise
Your company has compiled the following data on the small set of products that comprise the specialty repair parts division. Perform ABC analysis on the data. Over which products do you suggest the firm keep the tightest control? Explain.
| SKU | Annual Demand | Unit Cost |
| R11 | 125 | $25 |
| S22 | 55 | $90 |
| T33 | 100 | $800 |
| U44 | 150 | $150 |
| V55 | 100 | $45 |
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Answer
T33 and U44 represent almost 90% of the firm's volume in this area.
T33 is classified A, U44 is classified B, and all others are C.
The tightest controls go to T33, then U44 because of their high percentage of sales volume.
| SKU | Volume | Unit cost | Dollar volume | % Dollar volume | Cumulative $-vol % | Class | |
| T33 | 100 | $800 | $80,000 | 69.52% | 69.52% | A | |
| U44 | 150 | $150 | $22,500 | 19.55% | 89.07% | B | |
| S22 | 55 | $90 | $4,950 | 4.30% | 93.37% | C | |
| V55 | 100 | $45 | $4,500 | 3.91% | 97.28% | C | |
| R11 | 125 | $25 | $3,125 | 2.72% | 100.00% | C | |
| Total | $115,075 |
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Group discussion: Have you once tried to use ABC analysis in your work or life?
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Cycle Counting
Items are counted and records updated on a periodic basis
Often used with A B C analysis
Has several advantages
Eliminates shutdowns and interruptions
Eliminates annual inventory adjustment
Trained personnel audit inventory accuracy
Allows causes of errors to be identified and corrected
Maintains accurate inventory records
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14
Cycle Counting Example
5,000 items in inventory
500 A items, 1,750 B items, 2,750 C items
| ITEM CLASS | QUANTITY | CYCLE COUNTING POLICY | NUMBER OF ITEMS COUNTED PER DAY |
| A | 500 | Each month | 500/20 = 25/day |
| B | 1,750 | Each quarter | 1,750/60 = 29/day |
| C | 2,750 | Every 6 months | 2,750/120 = 23/day |
| blank | blank | blank | 77/day |
Policy is to count
A items every month (20 working days),
B items every quarter (60 days), and
C items every six months (120 days)
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15
Control of Service Inventories
Can be a critical component of profitability
Losses may come from shrinkage or pilferage
Applicable techniques include
Good personnel selection, training, and discipline
Tight control of incoming shipments
Effective control of all goods leaving facility
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16
Inventory Models
Independent demand - the demand for item is independent of the demand for any other item in inventory
Dependent demand - the demand for item is dependent upon the demand for some other item in the inventory
Holding costs - the costs of holding or “carrying” inventory over time
Ordering cost - the costs of placing an order and receiving goods
Setup cost - cost to prepare a machine or process for manufacturing an order
May be highly correlated with setup time
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17
Holding Costs (1 of 2)
Determining Inventory Holding Costs
| CATEGORY | Cost (and range) as a percentage of inventory value |
| Housing costs (building rent or depreciation, operating costs, taxes, insurance) | 6% (3 - 10%) |
| Material handling costs (equipment lease or depreciation, power, operating cost) | 3% (1 - 3.5%) |
| Labor cost (receiving, warehousing, security) | 3% (3 - 5%) |
| Investment costs (borrowing costs, taxes, and insurance on inventory) | 11% (6 - 24%) |
| Pilferage, space, and obsolescence (much higher in industries undergoing rapid change like tablets and smart phones) | 3% (2 - 5%) |
| Overall carrying cost | 26% |
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18
Holding Costs (2 of 2)
Determining Inventory Holding Costs
| CATEGORY | COST (AND RANGE) AS A PERCENTAGE OF INVENTORY VALUE |
| Housing costs (building rent or depreciation, operating costs, taxes, insurance) | 6% (3 - 10%) |
| Material handling costs (equipment lease or depreciation, power, operating cost) | 3% (1 - 3.5%) |
| Labor cost (receiving, warehousing, security) | 3% (3 - 5%) |
| Investment costs (borrowing costs, taxes, and insurance on inventory) | 11% (6 - 24%) |
| Pilferage, space, and obsolescence (much higher in industries undergoing rapid change like tablets and smart phones) | 3% (2 - 5%) |
| Overall carrying cost | 26% |
Holding costs vary considerably depending on the business, location, and interest rates. Generally greater than 15%, some high tech and fashion items have holding costs greater than 40%.
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19
Inventory Models for Independent Demand
Need to determine when and how much to order
Basic economic order quantity (E O Q) model
Production order quantity model
Quantity discount model
Important assumptions
Demand is known, constant, and independent
Lead time is known and constant
Receipt of inventory is instantaneous and complete
Quantity discounts are not possible
Only variable costs are setup (or ordering) and holding
Stockouts can be completely avoided
Basic E O Q Model
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20
Inventory Usage Over Time
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21
Minimizing Costs
Objective is to minimize total costs
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Minimizing Costs (annual setup cost)
Q = Number of pieces per order
Q* = Optimal number of pieces per order (E O Q)
D = Annual demand in units for the inventory item
S = Setup or ordering cost for each order
H = Holding or carrying cost per unit per year
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23
Minimizing Costs (annual holding cost)
Q = Number of pieces per order
Q* = Optimal number of pieces per order (E O Q)
D = Annual demand in units for the inventory item
S = Setup or ordering cost for each order
H = Holding or carrying cost per unit per year
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24
Minimizing Costs (Economic order quantity)
Q = Number of pieces per order
Q* = Optimal number of pieces per order (EOQ)
D = Annual demand in units for the inventory item
S = Setup or ordering cost for each order
H = Holding or carrying cost per unit per year
Optimal order quantity is found when annual setup cost equals annual holding cost
Solving for Q*
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E O Q-Determine optimal number of order
D = 1,000 units
S = $10 per order
H = $.50 per unit per year
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E O Q –Determine expected number of orders
D = 1,000 units Q* = 200 units
S = $10 per order
H = $.50 per unit per year
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EOQ—Determine optimal time between orders
D = 1,000 units Q* = 200 units
S = $10 per order N = 5 orders/year
H = $.50 per unit per year
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E O Q—Determine the total annual cost
D = 1,000 units Q* = 200 units
S = $10 per order N = 5 orders/year
H = $.50 per unit per year T = 50 days
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The E O Q Model
When including actual cost of material P
Robust Model
The E O Q model is robust
It works even if all parameters and assumptions are not met
The total cost curve is relatively flat in the area of the E O Q
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E O Q model is robust
Only 2% less than the total cost of $125 when the order quantity was 200
Ordering old Q*
Ordering new Q*
If the demand is actually 1500 units rather than 1000 units, but EOQ of 200 is still used, how about TC?
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Exercise
If Demand remains at 1000, Holding cost per unit per year is still $0.5. We order 200 needles at a time.
If the true order cost=$15 (rather than $10), what is the annual cost?
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Reorder Points
E O Q answers the “how much” question
The reorder point (R O P) tells “when” to order
Lead time (L) is the time between placing and receiving an order
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Reorder Point Curve
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Reorder Point Example
Demand = 8,000 iPhones per year
250 working day year
Lead time for orders is 3 working days, may take 4
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35
Production Order Quantity Model (1 of 5)
Used when inventory builds up over a period of time after an order is placed
Used when units are produced and sold simultaneously
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Production Order Quantity Model (2 of 5)
Q = Number of units per order p = Daily production rate
H = Holding cost per unit per year d = Daily demand (usage) rate
t = Length of the production run in days
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Production Order Quantity Model (3 of 5)
Q = Number of units per order p = Daily production rate
H = Holding cost per unit per year d = Daily demand (usage) rate
t = Length of the production run in days
However, Q = total produced = pt ; thus t = Q/p
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Production Order Quantity Model (4 of 5)
Q = Number of units per order p = Daily production rate
H = Holding cost per unit per year d = Daily demand (usage) rate
t = Length of the production run in days
Comparing with
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Production Order Quantity Example
D = 1,000 units p = 8 units per day
S = $10 d = 4 units per day
H = $0.50 per unit per year
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Production Order Quantity Model (5 of 5)
Note:
When annual data are used the equation becomes:
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41
Exercise
For a certain item, the cost-minimizing order quantity obtained with the basic EOQ model is 200 units, and the total annual inventory (carrying and setup) cost is $400. What is the inventory carrying cost per unit per year for this item?
A product has a demand of 4000 units per year. Ordering cost is $20, and holding cost is $4 per unit per year. The EOQ model is appropriate. The cost-minimizing solution for this product will cost ________ per year in total annual inventory (holding and setup) costs.
The assumptions of the production order quantity model are met in a situation where annual demand is 3650 units, setup cost is $50, holding cost is $12 per unit per year, the daily demand rate is 20 and the daily production rate is 100. What is the production order quantity for this problem?
A production order quantity problem has a daily demand rate = 10 and a daily production rate = 50. The production order quantity for this problem is approximately 750 units. What is the average inventory for this problem?
Answers:
1. $2. 2. $800. 3. 195 4. 300
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Questions?
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Quantity Discount Models (1 of 5)
Reduced prices are often available when larger quantities are purchased
Trade-off is between reduced product cost and increased holding cost
Table 12.2 A Quantity Discount Schedule
| Price range | Quantity ordered | Price per unit p |
| Initial price | 0 to 119 | $ 100 |
| Discount price 1 | 120 to 1,499 | $ 98 |
| Discount price 2 | 1,500 and over | $ 96 |
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44
Quantity Discount Models (2 of 5)
where Q = Quantity ordered P = Price per unit
D = Annual demand in units I = Holding cost per unit per year
S = Ordering or setup cost per order expressed as a percent of price P
Because unit price varies, holding cost is expressed as a percentage (I) of unit price (P)
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Quantity Discount Models (3 of 5)
Steps in analyzing a quantity discount
Starting with the lowest possible purchase price, calculate Q* until the first feasible E O Q is found. This is a possible best order quantity, along with all price-break quantities for all lower prices.
Calculate the total annual cost for each possible order quantity determined in Step 1. Select the quantity that gives the lowest total cost.
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46
Quantity Discount Models (4 of 5)
Figure 12.7
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Quantity Discount Models (5 of 5)
Calculate Q* for every discount starting with the lowest price
Infeasible – calculate Q* for next-higher price
Feasible
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Quantity Discount Example
Table 12.3 Total Cost Computations for Chris Beehner Electronics
Choose the price and quantity that gives the lowest total cost
Buy 275 drones at $98 per unit
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49
Quantity Discount Variations
All-units discount is the most popular form
Incremental quantity discounts apply only to those units purchased beyond the price break quantity
Fixed fees may encourage larger purchases
Aggregation over items or time
Truckload discounts, buy-one-get-one-free offers, one-time-only sales
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Probabilistic Models and Safety Stock
Used when demand is not constant or certain
Use safety stock to achieve a desired service level and avoid stockouts
Annual stockout costs = The sum of the units short for each demand level × The probability of that demand level × The stockout cost/unit × The number of orders per year
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51
Safety Stock Example (1 of 2)
ROP = 50 units Stockout cost = $40 per frame
Orders per year = 6 Carrying cost = $5 per frame per year
| NUMBER OF UNITS | PROBABILITY |
| 30 | .2 |
| 40 | .2 |
| ROP 50 | .3 |
| 60 | .2 |
| 70 | .1 |
| blank | 1.0 |
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52
Safety Stock Example (2 of 2)
ROP = 50 units Stockout cost = $40 per frame
Orders per year = 6 Carrying cost = $5 per frame per year
A safety stock of 20 frames gives the lowest total cost
ROP = 50 + 20 = 70 frames
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53
Probabilistic Demand (1 of 3)
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Probabilistic Demand (2 of 3)
Use prescribed service levels to set safety stock when the cost of stockouts cannot be determined
where
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55
Probabilistic Demand (3 of 3)
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Probabilistic Example (1 of 3)
μ = Average demand = 350 kits
σdLT = Standard deviation of demand during lead time = 10 kits
Stockout policy = 5% (service level = 95%)
Using Appendix I, for an area under the curve of 95%, the Z = 1.645
Safety stock = ZσdLT = 1.645(10) = 16.5 kits
Reorder point = Expected demand during lead time + Safety stock
= 350 kits + 16.5 kits of safety stock
= 366.5 or 367 kits
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57
Other Probabilistic Models (1 of 4)
When data on demand during lead time are not available, there are other models available
When demand is variable and lead time is constant
When lead time is variable and demand is constant
When both demand and lead time are variable
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Other Probabilistic Models (2 of 4)
Demand is variable and lead time is constant
where
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Probabilistic Example (2 of 3)
Average daily demand (normally distributed) = 15
Lead time in days (constant) = 2
Standard deviation of daily demand = 5
Service level = 90%
Z for 90% = 1.28
From Appendix I
Safety stock is about 9 computers
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Other Probabilistic Models (3 of 4)
Lead time is variable and demand is constant
where
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61
Probabilistic Example (3 of 3)
Daily demand (constant) = 10
Average lead time = 6 days
Standard deviation of lead time = σLT = 1
Service level = 98%, so Z (from Appendix I) = 2.055
Reorder point is about 81 cameras
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62
Other Probabilistic Models (4 of 4)
Both demand and lead time are variable
where
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63
Probabilistic Example
Average daily demand (normally distributed) = 150
Standard deviation = σd = 16
Average lead time 5 days (normally distributed)
Standard deviation = σLT = 1 day
Service level = 95%, so Z = 1.645 (from Appendix I)
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64
Single-Period Model
Only one order is placed for a product
Units have little or no value at the end of the sales period
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65
Single-Period Example (1 of 2)
Average demand = μ = 120 papers/day
Standard deviation = σ = 15 papers
Cs = cost of shortage = $1.25 − $.70 = $.55
Co = cost of overage = $.70 − $.30 = $.40
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66
Single-Period Example (2 of 2)
From Appendix I, for the area .579, Z ≅ .199
The optimal stocking level
= 120 copies + (.199)(σ)
= 120 + (.199)(15) = 120 + 3 = 123 papers
The stockout risk = 1 − Service level
= 1 − .579 = .421 = 42.1%
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67
Fixed-Period (P) Systems (1 of 3)
Fixed-quantity models require continuous monitoring using perpetual inventory systems
In fixed-period systems orders placed at the end of a fixed period
Periodic review, P system
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Fixed-Period (P) Systems (2 of 3)
Inventory counted only at end of period
Order brings inventory up to target level
Only relevant costs are ordering and holding
Lead times are known and constant
Items are independent of one another
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Fixed-Period (P) Systems (3 of 3)
Figure 12.9
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Fixed-Period Systems
Inventory is only counted at each review period
May be scheduled at convenient times
Appropriate in routine situations
May result in stockouts between periods
May require increased safety stock
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dLT
Z
s
Number of standard deviations
Standard deviation of demand during lea
d time
dLT
Z
s
=
=
dLT
ROP = daily demand Lead time
)
in das
(
y +Z
Average
s
´
=Lead time
=Standard deviation of demand per day
dLTd
d
ss
s
(
)
(
)
(
)
ROP 15 units 2 days
30 1.285 2
30 9.02 39.02 39
dLT
Z
s
=´+
=+
=+=»
ROP = Daily demand × lead time in days
+ × (Daily de
(
m ×
)
and)
LT
AverageZ
s
Standard deviation of lead time in days
LT
s
=
(
)
(
)
(
)
ROP = 10 units × 6 days + 2.05510 units1
= 60 + 20.55 = 80.55
ROP = Average daily demandd
(
×Average lea time +
)
LT
Z
s
(
)
2
2
2
Standard deviation of demand per day
Standard deviation of lead time in day
s
(Average lead timeAverage daily demad
)
n
d
LT
dLTLT
d
s
s
sss
=
=
=´+
(
)
(
)
(
)
(
)
(
)
(
)
222
ROP(150 packs5 days)1.645
5 days161501525622,5001
1,28022,50023,780154
ROP (1505)1.645(154)7502531,003 packs
dLT
dLT
s
s
=´+
=´+´=´+´
=+=@
=´+@+=
Cost of shortage Sales price/unit – Co
st/unit
Cost of overage Cost/unit – Salvage va
lue
s
o
C
C
=
==
=
Service level
s
so
C
CC
=
+
Service level
.55
.55.40
.55
.579
.95
s
so
C
CC
=
+
=
+
==