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Ch-9-OM_Calculations.xlsx

9.1Old

hours	minutes	Secs	Total time	units required	Takt time in minutes
			420	250	1.68	minutes/unit
Time to produce one product					total operation time
1.1	1.1	1.7	3.1	1	8
number of workers required				=8/1.68	4.76
Therefore, 5 workers are required.

hours	minutes	Secs	Total time	units required	Takt time in minutes
			720	240	3	minutes/unit
Time to produce one product					total operation time
2	3	1.5	1		7.5
number of workers required				=7.5/3	2.50
Therefore, 3 workers are required.
c. The special consideration has to be given for the operation Stir-frying of chiken.

hours	minutes	Secs	Total time	units required	Cycle time in minutes (b)
			480	50	9.6	minutes/unit
Time to produce one product					total operation time			Sum
4	7	6	5	6	7	8	6	49
c)number of workstations required					=49/9.6	5.10
Therefore, 6 work stations are required.
e)Idle time = (No. of workstations X Largest Cycle time) - Total Opertation time
		=(6X11)-49			17	minutes per cycle
Idle time = E+F+G+H = (11-6)+(11-7)+(11-8)+(11-6)
			Idle Time = Largest Cycle time - operation time
	E	6	5
	F	7	4
	G	8	3
	H	6	5
		Total	17
f) No. of cycles in 8 hour shift = Total available time/Largest cycle time = 480/11 = 43.6363 Cycles/day
Total Idle time per cycle = 17 minutes
Total Idle time per day = 17 minutes /cycle * 43.6363 cycles =						741.8171	minutes/day
						12.36361833	Hours
					12 hours	21.8171	minutes
g) Efficiency =49/(6*11)				0.7424242424
				74.24242424
				74.24%

hours	minutes	Secs	Total time	units required	Cycle time in minutes
			3600	180	20	Secs/unit
Time to produce one product					total operation time
12	15	8	5	20	60
number of workstations required					=60/20	3.00
Therefore, 3 work stations are required.
C. Yes, with 3 workstations and 20 as cycle time can be achieve.