Math work
BG0220 Basic Mathematics
NAME___________________________________ID.______________________________SEC.____________
ASSIGNMENT 2 ( 3% )
Review Chapter 3 ( for Quiz3 and Final )
3. Given the straight line graph below,
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a. find the slope. ______________________________
b. interpret the slope. ___________________________
__________________________________________
c. find the equation. __________________________ |
4. Find the value of y for which the line through the points A ( 1, y ) and B ( 4, 2 )
6. Solve the system of linear equations: x = ________ , y = __________
a.
( 3 , _____ ) , ( _____ , 0 ).
Use graphs of Lines A - D to answer questions 8.1 - 8.6
Line A Line B Line C Line D
8.1 Which line have a negative slope? __________________
8.2 Which line has a slope of zero? __________________
8.3 Which line has an y-intercept at (0, -2)? _________________
8.4 Which line has a slope of ½ ? __________________
Review Chapter 4 ( for Quiz 4 and Final )
1.
2.
3.
a. find x-intercept. ________________________
b. find y-intercept. _________________________
c. find the vertex. _________________________
4.
a. find the vertical asymptote. _________________________
b. find the horizontal asymptote. ________________________
a.
b.
c.
d.
e.
7. Given the graph below,
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a. find the vertical asymptote. _______________________
b. find the horizontal asymptote. ________________________
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following graphs.
Name: Exponential function, Rational function, Square root function,
Quadratic function , Third-degree polynomial function ,
Logarithmic function , Absolute value function, Linear function.
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Graph |
Name |
Function |
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Review Chapter 5 ( for Quiz 5 and Final )
1.
2.
3.
4.
5.
6.
7.
8.
9.
10.
1
()
fx
()
x
fxe
=
2
()
5
x
fx
x
=
-
()25
fxx
=+
(4,7)
2
()1
fxx
=-
()25
fxx
=-
()21
fxx
=-
3
()351
fxxx
=-+
2
()log
fxx
=
x
2
327
x
-
=
21
34
1
7
49
x
x
+
+
æö
=
ç÷
èø
5
log625
x
=
ln2
x
=-
1
log8
2
x
=
8
lnlog10log4
e
-+
log20.301
=
5
3
log30.477
=
log50.699
=
log30
2
log75
0.15
()5000(2)
t
Vt
-
=
t
x
log2log(5)2
xx
+-=
1
8512
x
+
=
(1,2)
--
34
1
7
2401
x
-
=
4
log(95)2
x
+=
1
ln()
x
e
=
1
log6
3
x
=
2
16
lnlog64log1000
e
-+
log20.3010
=
log30.4771
=
log50.6990
=
log270
5
log12
26
xy
-=
t
()756ln(1),012
fttt
=-+££
22
log(5)log(2)3
xx
+--=
2760
322
xy
xy
+=
-=-
24
xy
-³
24
xy
-=
24
xy
-³
x
y
x
y
x
y
x
y
x
y
x
y
x
y
x
y
x
y
3
=
3
+
-
=
x
y
()
fx
()
gx
=
(2)(3)
ff
+
3(4)5(7)
fg
-+
()
fx
1
()
fx
-
((3))
fg
30050
()
50
xforx
fx
xforx
-<
ì
ï
=
í
-³
ï
î
(105)
f
(5)
f
-
2
()1213
fxxx
=+-
4
3
()
728
x
fx
x
=
-
()
fx
(3)5(2)
ff
-+-
237
yx
=-
()
fx
x
()
fx
2
()5
fxx
=+
()54
gxx
=-
()5
hxx
=-
3(0)(2)
fg
+-
(
)
()
fgx
-
()()
fgx
×
()
hx
(1,3)
-
()
fx
()
gx
1
()
gx
-
gof
(((1)))
hgf
-