Domains of Rational Expressions

profilefroggermom02
ALEKS360ch5.2.html
close window McGraw-Hill McGraw-Hill 5.2 Special Products and Grouping
    In This Section
    1 Factoring by Grouping
    2 Factoring a Difference of Two Squares
    3 Factoring a Perfect Square Trinomial
    4 Factoring Completely

    In Section 5.1 you learned how to factor out the greatest common factor from allof the terms of a polynomial. In this section you will learn to factor a four-term polynomial by factoring out a common factor from the first two terms and then a common factor from the last two terms.

    1 Factoring by Grouping

    The product of two binomials may have four terms. For example,

    To factor x2 + ax + 3x + 3a, we simply reverse the steps we used to find the product. Factor out the common factor x from the first two terms and the common factor 3 from the last two terms:

    It does not matter whether you take out the common factor to the right or left. So(x + a)(x + 3) is also correct and we could have factored as follows:

    Page 331

    This method of factoring is called factoring by grouping.

    Strategy for Factoring a Four-Term Polynomial by Grouping
    1. Factor out the GCF from the first group of two terms.

    2. Factor out the GCF from t he last group of two terms.

    3. Factor out the common binomial.

    Factor by Grouping

    EXAMPLE 1 Factoring by Grouping

    Use grouping to factor each polynomial.

    a)

    xy + 2y + 5x + 10

    b)

    x2 + wx + x + w

    Solution
    a)

    The first two terms have a common factor of y, and the last two terms have acommon factor of 5:

    Check by using FOIL.

    b)

    The first two terms have a common factor of x, and the last two have a common factor of 1:

    Check by using FOIL.

    Now do Exercises 1–10

    For some four-term polynomials it is necessary to rearrange the terms before factoring out the common factors.

    EXAMPLE 2 Factoring by Grouping with Rearranging

    Use grouping to factor each polynomial.

    a)

    mn + 4m + m2 + 4n

    b)

    ax + b + bx + a

    Solution
    a)

    We can factor out m from the first two terms to get m(n + 4), but we can't get another factor of n + 4 from the last two terms. By rearranging the terms we can factor by grouping:

      b)
    Page 332

    Now do Exercises 11–18

    Note that there are several rearrangements that will allow us to factor the polynomials in Example 2. For example, m2 + 4m + mn + 4n would also work for Example 2(a).

    We saw in Section 5.1 that you could factor out a common factor with a positive sign or a negative sign. For example, we can factor −2x + 10 as 2(−x + 5) or −2(x − 5). We use this technique in Example 3.

    EXAMPLE 3 Factoring by Grouping with Negative Signs

    Use grouping to factor each polynomial.

    a)

    2x2 − 3x − 2x + 3

    b)

    ax + 3y − 3x − ay

    Solution
    a)

    We can factor out x from the first two terms and 1 from the last two terms:

    However, we didn't get a common binomial. We can get a common binomial if we factor out −1 from the last two terms:

    b)

    For this polynomial we have to rearrange the terms and factor out a common factor with a negative sign:

    Now do Exercises 19–28

    2 Factoring a Difference of Two Squares

    In Section 4.7, you learned that the product of a sum and a difference is a difference of two squares:

    So a difference of two squares can be factored as a product of a sum and a difference, using the following rule.

    Factoring a Difference of Two Squares

    For any real numbers a and b,

    Page 333

    Note that the square of an integer is a perfect square. For example, 64 is a perfect square because 64 = 82. The square of a monomial in which the coefficient is an integer is also called a perfect square or simply a square. For example, 9m2 is a perfect square because 9m2 = (3m)2.

    Factoring a Difference of Two Squares

    EXAMPLE 4 Factoring a difference of two squares

    Factor each polynomial.

    a)

    y2 − 81

    b)

    9m2 − 16

    c)

    4x2 − 9y2

    Solution
    a)

    Because 81 = 92, the binomial y2 − 81 is a difference of two squares:

    Check by multiplying.

    b)

    Because 9m2 = (3m)2 and 16 = 42, the binomial 9m2 − 16 is a difference of two squares:

    Check by multiplying.

    c)

    Because 4x2 = (2x)2 and 9y2 = (3y)2, the binomial 4x2 − 9y2 is a difference of two squares:

    Now do Exercises 29–42

    CAUTION

    Don't confuse a difference of two squares a2 − b2 with a sum of two squares a2 + b2. The sum a2 + b2 is not one of the special products and it can't be factored.

    3 Factoring a Perfect Square Trinomial

    In Section 4.7 you learned how to square a binomial using the rule

    You can reverse this rule to factor a trinomial such as x2 + 6x + 9. Notice that

    So if a = x and b = 3, then x2 + 6x + 9 fits the form a2 + 2ab + b2, and

    A trinomial that is of the form a2 + 2ab + b2 or a2−2ab + b2 is called a perfect square trinomial. A perfect square trinomial is the square of a binomial. Perfect square trinomials will be used in solving quadratic equations by completing the square in Chapter 10. Perfect square trinomials can be identified using the following strategy.

    Page 334 Strategy for Identifying a Perfect Square Trinomial

    A trinomial is a perfect square trinomial if

    1. the first and last terms are of the form a2 and b2 (perfect squares), and

    2. the middle term is 2ab or −2ab.

    EXAMPLE 5 Identifying the special products

    Determine whether each binomial is a difference of two squares and whether each trinomial is a perfect square trinomial.

    a)

    x2 − 14x + 49

    b)

    4x2 − 81

    c)

    4a2 + 24a + 25

    d)

    9y2 − 24y − 16

    Solution
    a)

    The first term is x2, and the last term is 72. The middle term, −14x, is −2 ⋅ x ⋅7. So this trinomial is a perfect square trinomial.

    b)

    Both terms of 4x2 − 81 are perfect squares, (2x)2 and 92. So 4x2 − 81 is a difference of two squares.

    c)

    The first term of 4a2 + 24a + 25 is (2a)2 and the last term is 52. However, 2 ⋅ 2a ⋅ 5 is 20a. Because the middle term is 24a, this trinomial is not a perfect square trinomial.

    d)

    The first and last terms in a perfect square trinomial are both positive. Because the last term in 9y2 − 24y − 16 is negative, the trinomial is not a perfect square trinomial.

    Now do Exercises 43–54

    Note that the middle term in a perfect square trinomial may have a positive or a negative coefficient, while the first and last terms must be positive. Any perfect square trinomial can be factored as the square of a binomial by using the following rule.

    Factoring Perfect Square Trinomials

    For any real numbers a and b,

    Page 335 EXAMPLE 6 Factoring perfect square trinomials

    Factor.

    a)

    x2 − 4x + 4

    b)

    a2 + 16a + 64

    c)

    4x2 − 12x + 9

    Solution
    a)

    The first term is x2, and the last term is 22. Because the middle term is −2 ⋅ 2 ⋅ x, or −4x, this polynomial is a perfect square trinomial:

    Check by expanding (x−2)2.

    b)

    a2 + 16a + 64 = (a + 8)2

    Check by expanding (a + 8)2.

    c)

    The first term is (2x)2, and the last term is 32. Because −2 ⋅ 2x ⋅ 3 = −12x, the polynomial is a perfect square trinomial. So

    Check by expanding (2x − 3)2.

    Now do Exercises 55–72

    4 Factoring Completely

    To factor a polynomial means to write it as a product of simpler polynomials. A polynomial that can't be factored using integers is called a prime or irreduciblepolynomial. The polynomials 3x, w + 1, and 4m − 5 are prime polynomials. Note that , but 4m − 5 is a prime polynomial because it can't be factored using integers only.

    A polynomial is factored completely when it is written as a product of prime polynomials. So (y−8)(y + 1) is a complete factorization. When factoring polynomials, we usually do not factor integers that occur as common factors. So 6x(x−7) is considered to be factored completely even though 6 could be factored.

    Some polynomials have a factor common to all terms. To factor such polynomials completely, it is simpler to factor out the greatest common factor (GCF) and thenfactor the remaining polynomial. Example 7 illustrates factoring completely.

    EXAMPLE 7 Factoring completely

    Factor each polynomial completely.

    a)

    2x3 − 50x

    b)

    8x2y − 32xy + 32y

    c)

    2x3 − 3x2 − 2x + 3

    Solution
    a)

    The greatest common factor of 2x3 and 50x is 2x:

    b)
    c)

    We can factor out x2 from the first two terms and 1 from the last two terms:

    However, we didn't get a common binomial. We can get a common binomial if we factor out −1 from the last two terms:

    Page 336

    Now do Exercises 73–98

    Remember that factoring reverses multiplication and every step of factoring can be checked by multiplication.

    Warm-Ups Fill in the blank.
    1. A is the square of an integer or an algebraic expression.

    2. A is the product of a sum and a difference.

    3. A trinomial of the form a2 + 2ab + b2 is a trinomial.

    4. A polynomial is one that can't be factored.

    5. A polynomial is when it is written as a product of prime polynomials.

    True or false?
    1. We always factor out the GCF first.

    2. The polynomial x2 + 16 is a difference of two squares.

    3. The polynomial x2 − 8x + 16 is a perfect square trinomial.

    4. The polynomial 9x2 + 21x + 49 is a perfect square trinomial.

    5. The polynomial 16y + 1 is a prime polynomial.

    6. The polynomial 4x2 − 4 is factored completely as 4(x2 − 1).

    Exercises Study Tips
    • As you study a chapter, make a list of topics and questions that you would put on the test, if you were to write it.

    • Write about what you read in the text. Sum things up in your own words.

    1 Factoring by Grouping

    Factor by grouping. See Example 1.

    1. bx + by + cx + cy

    2. 3x + 3z + ax + az

    3. ab + b2 + a + b

    4. 2x2 + x + 2x + 1

    5. wm + 3w + m + 3

    6. ay + y + 3a + 3

    7. 6x2 + 10x + 3xw + 5w

    8. 5ax + 2ay + 5xy + 2y2

    9. x2 + 3x + 4x + 12

    10. y2 + 2y + 6y + 12

    Factor by grouping. See Example 2.

    1. mn + n + n2 + m

    2. 2x3 + y + x + 2x2y

    3. 10 + wm + 5m + 2w

    4. 2a + 3b + 6 + ab

      Exercise 15 - Factor by Grouping

    5. xa + ay + 3y + 3x

    6. x3 + ax + 3a + 3x2

    Page 337
    • a3 + w2 + aw + a2w

    • a4 + y + ay + a3

    Factor by grouping. See Example 3.

    1. w2 − w − bw + b

    2. x2 − 2x − mx + 2m

    3. w2 + aw − w − a

    4. ap + 3a − p − 3

    5. m2 + mx − x − m

    6. −6n − 6b + b2 + bn

    7. x2 + 7x − 5x − 35

    8. y2 + 3y − 8y − 24

    9. 2x2 + 14x − 5x − 35

    10. 2y2 + 3y − 16y − 24

    2 Factoring a Difference ofTwo Squares

    Factor each polynomial. See Example 4.

    1. a2 − 4

    2. h2 − 9

    3. x2 − 49

      Exercise 32 - Factoring a Difference of Two Squares

    4. y2 − 36

    5. a2 − 121

    6. w2 − 81

    7. y2 − 9x2

    8. 16x2 − y2

    9. 25a2 − 49b2

    10. 9a2 − 64b2

    11. 121m2 − 1

    12. 144n2 − 1

    13. 9w2 − 25c2

    14. 144w2 − 121a2

    3 Factoring a Perfect Square Trinomial

    Determine whether each polynomial is a difference of two squares, a perfect square trinomial, or neither of these. See Example 5. See the Strategy for Identifying Perfect Square Trinomials box on page 334.

    1. x2 − 20x + 100

    2. x2 − 10x − 25

    3. y2 − 40

    4. a2 − 49

    5. 4y2 + 12y + 9

    6. 9a2 − 30a − 25

    7. x2 − 8x + 64

    8. x2 + 4x + 4

    9. 9y2 − 25c2

    10. 9x2 + 4

    11. 9a2 + 6ab + b2

    12. 4x2 − 4xy + y2

    Factor each perfect square trinomial. See Example 6.

    1. Exercise 64 - Factoring a Perfect Square Trinomial

    4 Factoring Completely

    Factor each polynomial completely. See Example 7.

    1. Exercise 78 - Factoring Completely: GCF is a variable

    2. −3x2 + 3y2)

    3. −8a2 + 8b2

      Exercise 87 - Factoring Completely

    4. 2ax2 − 98a

    5. 32x2y - 2y3)

    6. w3 − w − w2 + 1

    7. x3 + x2 − x − 1

    8. x3 + x2 − 4x − 4

    9. a2m − b2n + a2n − b2m

    10. 3ab2 − 18ab + 27a

    11. −2a2b + 8ab − 8b

    12. −4m3 + 24m2n − 36mn2

    13. 10a3 − 20a2b + 10ab2

    14. x2a − b + bx2 − a

    15. wx2 − 75 − 25w + 3x2

    Page 338 Miscellaneous

    Factor each polynomial completely.

    1. 6a3y + 24a2y2 + 24ay3

    2. 8b5c − 8b4c2 + 2b3c3

    3. 24a3y − 6ay3

    4. 27b3c − 12bc3

    5. 2a3y2 − 6a2y

    6. 9x3y − 18x2y2

    7. ab + 2bw − 4aw − 8w2

    8. 3am − 6n − an + 18m

    9. (a − b) − b(a − b)

    10. (a + b)w − (a + b)

    11. (4x2 − 1)2x − (4x2 − 1)

    12. (a2 − 9)a + 3(a2 − 9)

    Applications

    Use factoring to solve each problem.

    1. Skydiving. The height in feet above the earth for askydiver t seconds after jumping from an airplane at 6400 ft is approximated by the formula h(t) = − 16t2 + 6400, provided t < 5.

      a)

      Rewrite the formula with the right-hand side factored completely.

      b)

      Use the result of part (a) to find h(2).

      Figure for Exercise 111
    2. Demand for pools. Tropical Pools sells an aboveground model for p dollars each. The monthly revenue for this model is given by the formula

      Revenue is the product of the price p and the demand (quantity sold).

      a)

      Factor out the price on the right-hand side of the formula. R(p) = p(−0.08p + 300)

      b)

      Write a formula D(p) for the monthly demand.

      c)

      Find D(3000).

      d)

      Use the accompanying graph to estimate the price at which the revenue is maximized. Approximately how many pools will be sold monthly at this price?

      e)

      What is the approximate maximum revenue?

      f)

      Use the accompanying graph to estimate the price at which the revenue is zero.

      Figure for Exercise 112
    3. Volume of a tank. The volume in cubic inches for a fish tank with a square base and height x is given by the formula

      a)

      Rewrite the formula with the right-hand side factored completely.

      b)

      Find an expression for the length of a side of the square base.

      Figure for Exercise 113
    Getting More Involved
    1. Discussion

      For what real number k does 3x2 − k factor as 3(x − 2)(x + 2)?

    2. Writing

      Explain in your own words how to factor a four-term polynomial by grouping.

    3. Writing

      Explain how you know that x2 + 1 is a prime polynomial.

    [No Ajax]