FLUID MECH URGENT HELP

profilestrength
4QUES.pdf

Page 2 of 4

3. a) The uniform stream of velocity U approaches a channel (of width b). After flowing a

distance le (“entrance length”) flow inside the channel will become “fully developed”. Show that

the entrance length le is proportional to the Reynolds number Re (based on the channel width b).

Fluid’s dynamic viscosity is  and density is . (10 points)

b) The uniform stream of velocity U and temperature T approaches stationary flat

plate whose temperature is TW (TW > T). Fluid’s kinematic viscosity is , thermal diffusivity is

, and Prandtl number Pr = 10. Estimate distances xv and xT (measured from the leading edge) where velocity boundary

layer reaches thickness v ~ L and thermal boundary layer reaches thickness T ~ L, respectively. What is the ratio xT / xv ? (15 points)

U

Fully developed

flow

Entrance region

Potential core

Boundary layer

Boundary layer

le

b

x

U T T

U

TW



Page 3 of 4

4. A fluid is flowing from A to B through the network of tubes due to the known pressure

difference pA - pB (see schematic). Obtain an expression for the flow rate Q as a function of fluid

viscosity (), pressure difference (pA-pB), tube radius (R) and tube length (L).

Neglect elbow effects and disturbance in various tube junctions. Consider simple laminar flow

through straight circular pipe throughout the system. Neglect body forces.

To save you some integration time: mean velocity in a circular pipe is one half of the maximum

velocity.

Page 4 of 4

Navier-Stokes Equation in Cylindrical Coordinates

 

 

2 2 2

2 2 2

2 2

2 2

2

2 2

1

1 1

1 1 2

1 2

r z

r r r r r

r r

z

V v v v r r z

r r r r r z

r momentum

vv vp V v v g v

t r r r r

momentum

v v v vvp V v g v

t r r r r

z momentum

v

t

 

     

  

   

      

  

         

    

              

   

              

   

   2

1 z z z

p V v g v

z 

       

  • ytyt
  • 4Q