| Consider the following questions on the pricing of options on the stock of ARB Inc.: |
| a. A share of ARB stock sells for $75 and has a standard deviation of returns equal to 20 percent per year. The current risk-free rate is 9 percent and the stock pays two dividends: (1) a $2 dividend just prior to the option's expiration day, which is 91 days from now (ie, exactly one-quarter of a year), and (2) a $2 dividend 182 days from now (ie., exactly one-half year). Calculate the Black-Shoules value for a European -style call option with an exercise price of $70. |
| Current Security price = S1 = | $ 75.00 |
| Share value = S2 = | $ 73.04 | | S2 = Cum dividend value - present value of dividend | | | | | | S2 = 75 - 2/en = 75 - 2/e 0.09*3/12 = | | | 75 - 1.96 = 73.04 |
| Exercise price = X = | $ 70.00 |
| Time to expiration 1 = T1 | 91 | 0.25 | 0.50 |
| Time to expiration 2 = T2 | 182 | 0.5 | 0.71 |
| Risk-free rate = RFR | 9% |
| Security price volitility = Ơ = | 0.20 |
| Black-Shoules value for a European call option |
| 1) |
| d1 = | ln(S2/D) + (r + Ơ2/2)T |
| | Ơ√T |
| d1 = | ln(73.04/70) + (0.09 + 0.22/2)0.25 | | | | | N(d) = 0.5 + (d)(4.4-d)/10 | | | | | V0 = SN(d1)-Ke-rT N(d2) |
| | 0.2√0.25 | | | | | N(d1) = 0.5 + (d1)(4.4-d1)/10 | | | | | V0 = | 73.04*0.7587 - 70*0.98*0.7277 |
| d1 = | ln(1.0434) + (0.09 + 0.22/2)0.25 | | | | | N(d1) = | 0.5 + (.699)(4.4 - 0.699)/10 | | | | V0 = | 5.495 |
| | 0.2√0.25 | | | | | N(d1) = | 0.7587 |
| d1 = | .0424 + 0.0275 |
| | 0.10 | | | | | N(d2) = 0.5 + (d2)(4.4-d2)/10 |
| d1 = | 0.699 | | | | | N(d2) = | 0.5 + (.599)(4.4 - 0.599)/10 |
| | | | | | | N(d2) = | 0.7277 |
| d2 = | d1 - Ơ √T |
| d2 = | 0.699 - 0.2*√0.25 |
| d2 = | 0.599 |
| b. What would be the price of a 91-day European-style put option on ARB stock having the same exercise price? |
| S + P - C = PV of E |
| 73.04 + P - 5.495 = PV of 70 |
| P = | 68.51 + 5.495 - 73.04 |
| P = | 0.965 |
| c. Calculate the change in a call option's value that would occur if ARB's management suddenly decided to suspend dividend payments and this action had no effect on the price of the company's stock. |
| d1 = | ln(S1/D) + (r + Ơ2/2)T | | | | | N(d) = 0.5 + (d)(4.4-d)/10 | | | | | V0 = SN(d1)-Ke-rT N(d2) |
| | Ơ√T | | | | | N(d1) = 0.5 + (d1)(4.4-d1)/10 | | | | | V0 = | 75.00*0.8314 - 70*0.98*0.8057 |
| d1 = | ln(75/70) + (.09 + .022/2)0.25 | | | | | N(d1) = | 0.5 + (.9647)(4.4 - 0.9647)/10 | | | | V0 = | 7.084 |
| | 0.2√0.25 | | | | | N(d1) = | 0.8314 |
| d1 = | ln(1.0714) + (0.09 + 0.22/2)0.25 | | | | | | | | | | Vo without dividends = | | 7.084 |
| | 0.2√0.25 | | | | | N(d2) = 0.5 + (d2)(4.4-d2)/10 | | | | | Vo with dividends = | | 5.495 |
| d1 = | 0.6897 + 0.0275 | | | | | N(d2) = | 0.5 + (.8647)(4.4 - 0.8647)/10 | | | | Change in value of option = | | 1.589 |
| | 0.10 | | | | | N(d2) = | 0.8057 |
| d1 = | 0.9647 |
| d2 = | d1 - Ơ √T |
| d2 = | 0.9647 - 0.2*√0.25 |
| d2 = | 0.8647 |
| d. Briefly describe (without calculations) how your answer in Part a would differ under the following separate circumstances: (1) volitility of ARB stock increases to 30 percent, (2) the risk-free rate decreases to 8 percent. |
| 1) Security price volitility = Ơ = | 0.30 |
| d1 = | ln(S2/D) + (r + Ơ2/2)T | | | | | N(d) = 0.5 + (d)(4.4-d)/10 | | | | | V0 = S2N(d1)-Ke-rT N(d2) |
| | Ơ√T | | | | | N(d1) = 0.5 + (d1)(4.4-d1)/10 | | | | | V0 = | 73.04*0.6976 - 70*0.98*0.6446 |
| d1 = | ln(73.04/70) + (0.09 + 0.32/2)0.25 | | | | | N(d1) = | 0.5 + (.5077)(4.4 - 0.5077)/10 | | | | V0 = | 6.7331 |
| | 0.30√0.25 | | | | | N(d1) = | 0.6976 |
| d1 = | ln(1.0434) + (0.09 + 0.32/2)0.25 |
| | 0.30√0.25 | | | | | N(d2) = 0.5 + (d2)(4.4-d2)/10 |
| d1 = | ln(1.0434 )+ 0.3375 | | | | | N(d2) = | 0.5 + (.3577)(4.4 - 0.3577)/10 |
| | 0.15 | | | | | N(d2) = | 0.6446 |
| d1 = | 0.0424 + 0.03375 |
| | 0.15 |
| d1 = | 0.5076666667 |
| d2 = | d1 - Ơ √T |
| d2 = | 0.5077 - 0.3*√0.25 |
| d2 = | 0.3576666667 |
| 2) Change in RFR = 8% | 0.2 |
| d1 = | ln(S2/D) + (r + Ơ2/2)T | | | | | N(d) = 0.5 + (d)(4.4-d)/10 | | | | | V0 = S2N(d1)-Ke-rT N(d2) |
| | Ơ√T | | | | | N(d1) = 0.5 + (d1)(4.4-d1)/10 | | | | | V0 = | 73.04*0.7511 - 70*0.98*0.7196 |
| d1 = | ln(73.04/70) + (0.08 + 0.32/2)0.25 | | | | | N(d1) = | 0.5 + (.674)(4.4 - 0.674)/10 | | | | V0 = | 5.4958 |
| | 0.20√0.25 | | | | | N(d1) = | 0.7511 |
| d1 = | ln(1.0434) + (0.08 + 0.32/2)0.25 |
| | 0.20√0.25 | | | | | N(d2) = 0.5 + (d2)(4.4-d2)/10 |
| d1 = | ln(1.0434 )+ 0.025 | | | | | N(d2) = | 0.5 + (.574)(4.4 - 0.574)/10 |
| | 0.1 | | | | | N(d2) = | 0.7196 |
| d1 = | 0.0424 + 0.025 |
| | 0.1 |
| d1 = | 0.674 |
| d2 = | d1 - Ơ √T |
| d2 = | 0.674 - 0.2*√0.25 |
| d2 = | 0.574 |