Quote Request (TSM Class)
SuperClassShow all your calculations neatly. If I can’t follow your work I can’t grant partial credit. Lc = 46.3 + 33.9logF - 13.82logHb – a(Hm) + [44.9-6.55logHb]logD + C F = 800Mhz to 2000Mhz For rural or suburban (flat) environments Hb = 4m to 50m a(Hm) = (1.1logF-0.7)Hm – (1.56logF – 0.8) Hm = 1m to 3m For urban environments (many tall buildings in path) Radius of Coverage = .02Km to 5Km a(Hm) = 3.20(log(11.75Hm))2 – 4.97 For F > 400Mhz C = 0dB for rural and 3dB for urban Lh = 69.55 + 26.16logF - 13.82logHb – Ch + [44.9-6.55logHb]logD F = 150Mhz to 1500Mhz Rural or Suburban Hb = 30m to 200m Ch = 0.8 + (1.1logF-0.7)Hm – 1.56logF Hm = 1m to 10m Urban Radius of Coverage = 1Km to 20Km Ch = 3.20(log(11.75Hm))2 – 4.97 For F between 200Mhz & 1.5Ghz We are building a network using radios that operate at 1Ghz in an urban area. Once end of the link will have the antenna mounted on a 40 meter (approximately 43 feet) tower. The other end will be hand held at head height by people walking up to 3.75 miles (6Km) away. Which model should I use to estimate path loss over the link? Why? Model: _______________________ Reason: _______________________ A sharp edge on a building or a sharp mountain ridge is likely to give rise to what propagation mechanism? Answer: _______________________ If moving 4 or 5 feet clears up a noise broadcast FM signal, what type of interference am I likely to be experiencing? Answer: _______________________ Stating your answer in complete sentences explain fully what was causing the problem in question 3 and how my movement caused the signal to go from noisy to clear. What is the formula for the correction factor for mobile antenna height when using the Hata model with the location pictured? Answer: ___________________________________ ________________ and __________________ are really the sam epropagation mechanism viewed from different perspectives. Given the folloiwng equation: Ch = 3.20(log(11.75Hm))2 –...
10 years ago
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