For a population comprising 30% males, what is the probabilility of drawing a random sample
For a population comprising 30% males, what is the probabilility of drawing a random sample of 313 and getting exactly 94 males? Hint: use the binomial distribution.
4.9% |
30.0% |
46.7% |
50.0% |
53.3% |
If the variable "Age" were uniformly distributed over the range measured in the sample, the mean would be:
26 |
37 |
38.5 |
45 |
71 |
Assume that Pay follows a normal distribution with the parameters measured by the sample. Using this information, what proportion of the population earns more than $45000?
20.9% |
22.7% |
77.3% |
78.1% |
87.6% |
Assume that Pay follows a normal distribution with the parameters measured by the sample. Using this information, what proportion of the population earns between $45000 and $55000?
20.9% |
48.6% |
52.4% |
73.3% |
Cannot be calculated |
The lower bound of the 95% confidence interval for the mean of the variable "Pay" is:
$49632 |
$49878 |
$50004 |
$51307 |
$51432 |
The upper limit of the 90% confidence interval for the proportion of males in the sample is:
35.1% |
34.3% |
25.8% |
25.0% |
23.4% |
In order test whether the mean Tenure is more than 5 years, the hypotheses should be set up as follows:
H0: µ≥5 and HA: µ≤5 |
H0: µ≠5 and HA: µ |
H0: µ and HA: µ≠5 |
H0: µ≥5 and HA: µ<5 |
H0: µ≤5 and HA: µ>5 |
For the equivalent group of employees at Ellion, the mean gross annual remuneration is $51500 with a standard deviation of $7000. At a 1% significance level, testing the hypothesis that the results from the BizProsammmple are the same results in the following decision:
Reject H0 |
Reject HA |
Accept H0 |
Do not reject H0 |
Do not reject HA |
When testing the hypothess that the proportion of males in the sample is 35% at a 1% significance level, the decision is:
Accept the null hypothesis |
Reject the null hypothesis |
Do not reject the null hypothesis |
Do not reject the alternative hypothesis |
Reject the alternative hypothesis |
10 years ago
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