Louis Katz, a cost accountant at Papalote Plastics, Inc. (PPI), is analyzing the manufacturing costs

Question 13

Louis Katz, a cost accountant at Papalote Plastics, Inc. (PPI), is analyzing the manufacturing costs of a molded plastic telephone handset produced by PPI. Louis's independent variable is production lot size (in 1,000's of units), and his dependent variable is the total cost of the lot (in $100's). Regression analysis of the data yielded the following tables.

Louis's regression model is _____________.

Question 20

According to a study several years ago by the Personal Communications Industry Association, the average wireless phone user earns $62,600 per year. Suppose a researcher believes that the average annual earnings of a wireless phone user are lower now, and he sets up a study in an attempt to prove his theory. He randomly samples 18 wireless phone users and finds out that the average annual salary for this sample is $58,974, with a population standard deviation of $7,810. Use α = .01to test the researcher’s theory. Assume wages in this industry are normally distributed.

The value of the test statistic rounded to 2 decimal places is z =   and we  .

The tolerance is +/- 0.05.

A random sample of 51 items is taken, with   and s² = 25.68. Use these data to test the following hypotheses, assuming you want to take only a 1% risk of committing a Type I error and that x is normally distributed.


StartLayout 1st Row 1st Column Upper H Subscript 0 Baseline colon mu equals 60 ⁢EndLayout StartLayout 1st Row 1st Column Upper H Subscript a Baseline colon mu less-than 60 EndLayout

Round your answer to 2 decimal places, the tolerance is +/-0.01.

The value of the test statistic is   and we  .

Question 34

Louis Katz, a cost accountant at Papalote Plastics, Inc. (PPI), is analyzing the manufacturing costs of a molded plastic telephone handset produced by PPI. Louis's independent variable is production lot size (in 1,000's of units), and his dependent variable is the total cost of the lot (in $100's). Regression analysis of the data yielded the following tables.

Using α = 0.05, Louis should ___________.