A lead shot is projected from the ground level with a velocity U, at an angle O, to the horizontal....
A lead shot is projected from the ground level with a velocity U, at an angle O, to the horizontal. Given that the times t, for the lead shot to reach its maximum height as t=UsinO/g. Where g is acceleration due to gravity. Show that H reached by the body is Hmax=U^2sin^2O/2g
12 years ago
999999.99
Answer(0)
Bids(0)
other Questions(10)
- lottery probability
- Excelling in mathematics, how, favorite sub catergory was Trigonometry 400 words
- margin of error: confidence interval 99%: n=201, x bar= 175. s=21 i keep getting Margin of error, E = 3.85213 and...
- Summarize the article
- informative essay- write a informative essay on Masefield's experience as a seafarer
- Race in Turn of the Century America
- United States Department of Labor guidelines for nursing home - discussion post
- Can you please make a childrens/shortened version of the silver sword?
- what is la madera and el petroleo
- Business Law