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November13,2009 Math 221 - 02: Exam 3 Name:
Prob | 1 | 2 | 3 | 4 | 5 | 6 | Total |
Value | 12 | 10 | 8 | 10 | 8 | 22 | 70 |
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Show properworkforfull creditin problems3-6
1.(2pts each)Answertrueorfalse.No Justification Required.
(a) IfAisaninvertible matrix, then thecolumnvectorsofAmust belinearlyindependent.
(b) IfAisanm×nmatrix,then row(A)isasubspaceofRm.
(c) IfV isasubspace ofR5 withdimension 3,then the orthogonal complementofV,V⊥,musthavedimension2.(i.e. dim(V⊥)=2)
(d) Everysubspaceofdimension1inR2 isrepresented byalinethat goesthroughtheorigin.(e) IfAisanm×nmatrixwithnullity(A) =0,then col(A)=Rm .
(f) Ifspan{~v1,~v2,...,~vn }=Rn ,then theset{~v1 ,~v2,...,~vn }islinearlyindependent.
2.(2pt each)ShortAnswer. No Justification Required.
SupposeAisamatrixwith
|
1
2
3
1
−1
0
row(A)=span
,
0 −5
and col(A)=span
1,0
Givethefollowing:
(i)ThesizeofAis
2
1
(ii)Rank(A)= (iii)Nullity(A)=
(iv)Rank(AT)= (v)Nullity(AT)=
3.(8pts) LetA~x=~bbealinearsystemofmequations innunknowns.
Provethat ifA~x=~bisconsistent,then~bisinthecolumnspaceofA.Proof:
4.(10pts) LetWbeasubspaceofRn .Showthat W⊥ isasubspaceofRn .
Proof:
5.(8pts) Whatisthedimensionofthesubspace U=span{v~1,v~2,v~3}ofR3,where
v~1=(1,2,1)
v~2=(2,9,0)
v~3=(0,−5,2)
Justify yourconclusion!
−1 1 3
6.GiventhematrixA=−1 −5 −3
|
|
0 3 3
−1 −2 0
(a) (5pts) Determine thereducedrowechelonformofA.
(b) (4pts) Find abasisfortherowspaceofA
(c) (4pts) Find abasisforthecolumnspaceofA
(d) (5pts) Find abasisforthenullspaceofA
(e) (4pts) Verifythatrow(A)⊥null(A)
13 years ago
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- linear_algebra_answers.pdf