finding the zeros of a parabola
the equation of my parabola is
x= -3(y-1)^2 +6
it opens to the left
the axis of symetry is 1
the vertex is (6,1)
How do I faind the zeros?
what are they?
I am putting $1 as my amount but I really cannot pay anything :( sorry.
13 years ago
1
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