ECON 2300 CH 5 Quiz

Econ2300
assignment: Ch5 Quiz

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Exercise 5.12 METHODS AND APPLICATIONS
Suppose that the probability distribution of a random variable x can be described by the formula
 
  P(x) = x
 ________________________________________
 15
 
for each of the values x = 1, 2, 3, 4, and 5. For example, then, P(x = 2) = p(2) =2/15.
 
(a) Write out the probability distribution of x. (Write all fractions in reduced form.)

  x 1   2   3   4   5
  
  
  
  
    

  P(x) ________________________________________   ________________________________________   ________________________________________   ________________________________________   ________________________________________
  
  
  
  
    

________________________________________

(b) Show that the probability distribution of x satisfies the properties of a discrete probability distribution.(Round other answers to the nearest whole number. Leave no cells blank - be certain to enter "0" wherever required.)

  P(x) ≥   for each value of x. 

(c) Calculate the mean of x. (Round your answer to 3 decimal places.)

  µx    

(d) Calculate the variance, σ2x , and the standard deviation, σx. (Round your answer σx2 in to 3 decimal places and round answer σx in to 4 decimal places.)

  σx2   

  σx   

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Exercise 5.23 METHODS AND APPLICATIONS
Suppose that x is a binomial random variable with n = 5, p = 0.3, and q = 0.7.
 
(b)  For each value of x, calculate p(x), and graph the binomial distribution. (Round final answers to 5 decimal places.)
 
  p(0) =  , p(1) =  , p(2) =  , p (3) =  ,
  p(4) =  , p(5) = 

 
(c) Find P(x = 3). (Round final answer to 5 decimal places.)
 
  P(x=3)   

 
(d) Find P(x ≤ 3). (Do not round intermediate calculations.  Round final answer to 5 decimal places.)
 
  P(x ≤ 3)   

 
(e) Find P(x < 3). (Do not round intermediate calculations. Round final answer to 5 decimal places.)
 
  P(x < 3) = P(x ≤ 2)  

 
(f) Find P(x ≥ 4). (Do not round intermediate calculations. Round final answer to 5 decimal places.)
 
  P(x ≥ 4)   

 
(g) Find P(x > 2). (Do not round intermediate calculations. Round final answer to 5 decimal places.)
 
  P(x > 2)   

 
(h) Use the probabilities you computed in part b to calculate the mean, μx, the variance, σ 2x, and the standard deviation, σx, of this binomial distribution. Show that the formulas for μx , σ 2x, and σx given in this section give the same results. (Do not round intermediate calculations. Round final answers to µx and σ 2x in to 2 decimal places, and σx in to 6 decimal places.)
 
  µx   

  σ2x   

  σx   

 
(i) Calculate the interval [μx ± 2σx]. Use the probabilities of part b to find the probability that x will be in this interval. Hint: When calculating probability, round up the lower interval to next whole number and round down the upper interval to previous whole number. (Round your answers to 5 decimal places. A negative sign should be used instead of parentheses.)
 
  The interval is [ ,  ].

  P(  ≤ x ≤  ) = 

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MC Qu. 14 The mean of the binomial distribution is equ...
The mean of the binomial distribution is equal to:
 
p
 
 
 
np
 
(n) (p) (1-p)
 
px (1-p)n-x
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MC Qu. 25 A fair die is rolled 10 times. What is the p...
A fair die is rolled 10 times. What is the probability that an odd number (1, 3, or 5) will occur less than 3 times?
 
.1550
 
.8450
 
.0547
 
.7752
 
.1172
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MC Qu. 31 If n = 20 and p = .4, then the mean of the b...
If n = 20 and p = .4, then the mean of the binomial distribution is
 
.4
 
4.8
 
8
 
12
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MC Qu. 36 The probability that a given computer chip w...
The probability that a given computer chip will fail is 0.02. Find the probability that of 5 delivered chips, exactly 2 will fail.
 
.9039
 
.0000
 
.0922
 
.0038
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3 out of
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MC Qu. 38 In the most recent election, 19% of all elig...
In the most recent election, 19% of all eligible college students voted. If a random sample of 20 students were surveyed:
Find the probability that exactly half voted in the election.
 
.4997
 
.0014
 
.0148
 
.0000
13.
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3 out of
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MC Qu. 39 In the most recent election, 19% of all elig...
In the most recent election, 19% of all eligible college students voted. If a random sample of 20 students were surveyed:
Find the probability that none of the students voted.
 
.0148
 
.4997
 
.0014
 
.0000
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MC Qu. 55 For a random variable X, the mean value of t...
For a random variable X, the mean value of the squared deviations of its values from their expected value is called its
 
Standard Deviation
 
Mean
 
Probability
 
Variance
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MC Qu. 62 If the probability distribution of X is:&nbs...
If the probability distribution of X is:

What is the expected value of X?
 
2.25
 
2.24
 
1.0
 
5.0
 
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MC Qu. 63 If the probability distribution of X is:&nbs...
If the probability distribution of X is:

What is the variance of X?
 
5.0
→
1.0
 
2.25
 
2.24
 
 
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MC Qu. 66 A vaccine is 95 percent effective. What is t...
A vaccine is 95 percent effective. What is the probability that it is not effective for, more than one out of 20 individuals?
 
.3774
 
.7359
→
.2641
 
.3585
P(X ≥ 2) = 1 - [P(X = 0) + p(X = 1)]
P(X ≥ 2) = 1 - [(.3585) + (.3774)] = .2641

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MC Qu. 67 If the probability of a success on a single ...
If the probability of a success on a single trial is .2, what is the probability of obtaining 3 successes in 10 trials if the number of successes is binomial?
 
.1074
 
.2013
 
.5033
 
.0031
 
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MC Qu. 78 For a binomial process, the probability of s...
For a binomial process, the probability of success is 40% and the number of trials is 5.
Find the expected value.
 
5.0
 
1.1
 
1.2
 
2.0
E[X] = (5) (.40) = 2
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MC Qu. 79 For a binomial process, the probability of s...
For a binomial process, the probability of success is 40% and the number of trials is 5.
Find the variance.
 
1.1
→
1.2
 
5.0
 
2.0
 
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MC Qu. 80 For a binomial process, the probability of s...
For a binomial process, the probability of success is 40% and the number of trials is 5.
Find the standard deviation.
 
1.1
 
5.0
 
2.0
 
1.2
 
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MC Qu. 82 For a binomial process, the probability of s...
For a binomial process, the probability of success is 40% and the number of trials is 5.
Find P(X > 4).
 
.0102
 
.0778
 
.0870
 
.3370
P(X = 5) = (.4)5 = .0102
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MC Qu. 92 If X has the probability distribution%...
If X has the probability distribution

compute the expected value of X.
 
0.5
 
0.7
 
1.0
 
0.3
E[X] = -1(.2) + 0(.3) + 1(.5) = .3
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MC Qu. 93 If X has the probability distribution%...
If X has the probability distribution

compute the expected value of X.
 
1.3
 
2.4
 
1.0
 
1.8
E[X] = (-2) (.2) + (-1) (.2) + (1) (.2) + (2) (.2) + (9) (.2) = 1.8
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MC Qu. 95 X has the following probability distribution...
X has the following probability distribution P(X):

Compute the variance value of X.
 
1.58
 
.625
→
.850
 
.955
E[X] = (1) (.1) + (2) (.5) + (3) (.2) + (4) (.2) = 2.5
  = (1 - 2.5)2 (.1) + (2 - 2.5)2 (.5) + (3 - 2.5)2 (.2) + (4 - 2.5)2 (.2) = .850
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MC Qu. 99 Consider the experiment of tossing a fair co...
Consider the experiment of tossing a fair coin three times and observing the number of heads that result (X = number of heads).
Determine the expected number of heads.
 
1.1
 
1.5
 
1.0
 
2.0
 
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MC Qu. 100 Consider the experiment of tossing a fair co...
Consider the experiment of tossing a fair coin three times and observing the number of heads that result (X = number of heads).
What is the variance for this distribution?
→
0.75
 
0.87
 
1.22
 
1.5
 
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MC Qu. 102 Consider the experiment of tossing a fair co...
Consider the experiment of tossing a fair coin three times and observing the number of heads that result (X = number of heads).
If you were asked to play a game in which you tossed a fair coin three times and were given $2 for every head you threw, how much would you expect to win on average?
 
$6
→
$3
 
$9
 
$2
 
46.
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MC Qu. 104 According to data from the state blood progr...
According to data from the state blood program, 40% of all individuals have group A blood. If six (6) individuals give blood, find the probability that None of the individuals has group A blood?
 
.0467
 
.4000
 
.0041
 
.0410
View Hint #1
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MC Qu. 105 According to data from the state blood progr...
According to data from the state blood program, 40% of all individuals have group A blood. If six (6) individuals give blood, find the probability that Exactly three of the individuals has group A blood?
 
.4000
 
.2765
 
.5875
 
.0041
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MC Qu. 106 According to data from the state blood progr...
According to data from the state blood program, 40% of all individuals have group A blood. If six (6) individuals give blood, find the probability that At least 3 of the individuals have group A blood.
 
.4557
 
.8208
 
.1792
 
.5443
P(x ≥ 3) = P(x = 3) + p(x = 4) + p(x = 5) + p(x = 6) = .4557
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MC Qu. 113 An important part of the customer service re...
An important part of the customer service responsibilities of a cable company relates to the speed with which trouble in service can be repaired. Historically, the data show that the likelihood is 0.75 that troubles in a residential service can be repaired on the same day. For the first five troubles reported on a given day, what is the probability that fewer than two troubles will be repaired on the same day?
 
.0010
 
.0146
→
.0156
 
.6328
P(x < 2) = P(x = 0) + P(x = 1) = .0156
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MC Qu. 116 The Post Office has established a record in ...
The Post Office has established a record in a major Midwestern city for delivering 90% of its local mail the next working day. If you mail eight local letters, what is the probability that all of them will be delivered the next day.
 
1.0
 
.5695
→
.4305
 
.8131
P(x = 8) = .4305
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MC Qu. 117 The Post Office has established a record in ...
The Post Office has established a record in a major Midwestern city for delivering 90% of its local mail the next working day. Of the eight, what is the average number you expect to be delivered the next day?
 
4.0
 
2.7
 
3.6
 
7.2
 = np = (8) (.9) = 7.2
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MC Qu. 118 The Post Office has established a record in ...
The Post Office has established a record in a major Midwestern city for delivering 90% of its local mail the next working day. Calculate the standard deviation of the number delivered when 8 local letters are mailed.
 
.72
→
.85
 
2.83
 
2.68
Σ =  =  =  = .85
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MC Qu. 124 A large disaster cleaning company estimates ...
A large disaster cleaning company estimates that 30% of the jobs it bids on are finished within the bid time. Looking at a random sample of 8 jobs that is has contracted calculate the mean number of jobs completed within the bid time.
 
2.0
 
5.6
 
4.0
 
2.4
 = np = 8(.3) = 2.4
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MC Qu. 125 A large disaster cleaning company estimates ...
A large disaster cleaning company estimates that 30% of the jobs it bids on are finished within the bid time. Looking at a random sample of 8 jobs that is has contracted find the probability that x (number of jobs finished on time) is within one standard deviation of the mean.
→
.5506
 
.6867
 
.8844
 
.7483
σ = √npq = 1.3. P(µ+/-σ) = P(2.4+/-1.3) = P(1.1≤X≤3.7) = P(2≤X≤3) = 0.2965+0.2541 = 0.5506