Coulomb's law for the magnitude of the force F
blazino9t9What is the net force exerted by these two charges on a third charge q3 = 49.5nC placed between q1 and q2 at x3 = -1.195m ?
Your answer may be positive or negative, depending on the direction of the force.
Coulomb's law for the magnitude of the force F between two particles with charges Q and Q′ separated by a distance d is
|F|=K|QQ′|d2,
where K=14πϵ0, and ϵ0=8.854×10−12C2/(N⋅m2) is the permittivity of free space.
Consider two point charges located on the x axis: one charge, q1 = -18.0nC , is located at x1 = -1.670m ; the second charge, q2 = 33.0nC , is at the origin (x=0.0000).
- 9 years ago
- 5
Answer(1)
Purchase the answer to view it
Bids(0)
other Questions(10)
- Predict the Microsoft Office component that you believe will be the least difficult for you to learn and explain why
- precalculus
- Data Structures
- Financial Statement Case Study
- WEEK 4, 1 & 2 DQ
- Companies should not be held liable for losses sustained in a successful attack made on their AIS by outside sources
- English Help
- the fundamental determinant of the elasticity of demand for a good is
- Econ homework
- MANAGERIAL ACCOUNTING : 8 PROBLEMS :