Circles and Triangles
SuperClassWeek4:Assignment4
Pleaseanswerthefollowingquestions.Someofthequestionsarefromyourtext.
1. Anairplanereachesanaltitudeof3miabovetheearth.Assumingacleardayandthatapassengerhasbinoculars,howfarcanthatpassengersee?(Hint:Theradius oftheearthisapproximately4000miles[CD1] )
2. Statethemeasureoftheangleformedbytheminutehandandthehourhandofaclockwhenthetimeisa)1:30pmandb)2:20am[CD2] .
(Clock 1:30) (Clock 2:20)
Clock: each 5 minutes equals 30° in the circle (360/12=30). Each minute equals 6° (30/5=6)
For the 1:30 clock - four arcs of 5 minutes equals (4*30=120) 120°. The 1 represents half of an arc or two and half minutes (6*2.5=15) 15° 120+15=135° The angle when the clock is at 1:30 measures approximately 135°.
The 2:20 Clock: The 3 to 4 arc equals 30°. The second arc covers 3.5 minutes (look at the hour hand) 6*3.5= 21° the angle when the clock is at 2:20 measures approximately 51°.
3. SupposethatacircleisdividedintothreecongruentarcsbypointsA,B,andC.Whatisthemeasureofeacharc?WhattypeoffigureresultswhenA,B,andCare joinedbysegments[CD3] ?
Answer: Congruent arcs are arch in the same circle or in congruent circles that measures the same in degrees (Week Four: Arcs and Central Angles). A circle measures 360°. 360/3 (three congruent arcs) = 120° each. The figure form by segments ABC is a triangle.
****I tried to make to a circle to show the shape****
A
C
B
4. Answerthefollowingproblemfromyourtextbook:Problem29,Section6.2.
For the five pointed star (pentagram), inscribed in the circles, find the measures of angle 1 and 2[CD4] .
(Alexander 298)
Polygon Sides =(number of sides -2)*180°
(Alexander 102)
The inside polygon = (number of side -2)*180 = (5-2)*180
The polygon total angles =540° each angle inside the polygon = (540/5)=108°
∠2 = 108°
To calculate ∠1, I need to subtract 180°-108° =72° 72+72+x=180
144+x=180
X=180-144
X=36
∠1=36°
∠1
∠2 = 108°
The measurement of the angles are 36° and 108°.
5. Thelengthsofthelegsofarighttriangleareconsecutiveevenintegers.The numericalvalueoftheareaisthreetimesthatofthelongerleg.Findthelengthsofthelegsofthetriangle.
(Hypotenuse)² = (leg 1)² + (leg 2)² (Week 3:Pythagorean Theorem[CD5] ).
=x
=X+2
(Alexander 140)
Area of a triangle = a =1/2bh
A = numericalvalueoftheareaisthreetimesthatofthelongerleg
3(x+2)= x*(x+2)
2
3x+6=x²+2x
2
6x+12=x²+2x
x²-4x-12=0 This is a quadratic equation
Ax²+Bx+C=0
x²-4x-12=0 (factor )
(x-6) (x+2)
x-6=0 x+2=0
x=6 x=-2
Checking 6 and -2
Area of the triangle 3(x+2)= x*(x+2)
2
3(6+2)= 6*(6+2) 3(-2+2)= 6(+2-2)
2 2
18+6= 48 0=0
2
24=24 (6ü, -2 does not work)
The numericalvalueoftheareaisthreetimesthatofthelongerleg.
3x=24
X=8
Find the lengths of the legs of the triangle. The lengths of the legs are 6 and 8.
6. Answerthefollowingproblemfromyourtextbook:Problem18,Section6.1.
Problem: AB is the common chord of circle O and circle Q. If AB = 12 and each circle has a radius of length 10, how long is segment OQ[CD6] ?
7. Answerthefollowingquestionsfromyourtextbook:Problem39,Section6.1.
If arc ST≅ arc TV, explain why ΔSTY is an isosceles triangle[CD7] .
An isosceles triangle is a triangle that has two congruent sides.
8. TheradiusofaFerriswheel’scircularpathis40ft.Ifa“ride”of12revolutionsismadein3minutes,atwhatrateinfeetpersecondisthepassengerinacartmovingduringtheride[CD8] ?
The circumference of a circle is calculated by 2(Pi)(r) (Alexander 380).
2(Pi) (40)= feet per revolution
2(3.141592654)(40) = feet per revolution = 251.3 feet per revolution
12 revolutions per three minutes = 4 revolutions per minute 12/3 = 4
251.3 * 4 revolutions per minutes = 1,005.2 feet per minute
1005.2/60 (seconds) = 16.75 feet per second.
The passengers in a cart of a Ferris wheel will move 16.75 feet per second.
9. In a given a triangle ABC, AB = 10, BC = 17, and AC = 21cm. What is the area of the triangle[CD9] ?
Work Cited
"Clock 1:30." Educational Technology Clearinghouse. N.p., n.d. Web. 04 July 2014.
"Clock 2:20." Educational Technology Clearinghouse. N.p., n.d. Web. 04 July 2014.
“Week Four: Arcs and Central Angles.” College Math II. The Art Institute of Pittsburgh Online Division, 2014. Web. 4 July 2014.
Alexander, Daniel C., Geralyn Koeberlein. Elementary Geometry for College Students, 5th Edition. Cengage Learning, 01/2010. VitalBook file.
[CD1]I do not understand this problems. Please explain provide every step.
[CD2]Solved but like to verify it is correct.
[CD3]This is answered
[CD4]This one is answered
[CD5]This problem is answered.
[CD6]I do not understand this problem. Please explain in detail. I need to be able to work the problems in our quiz.
[CD7]I am not good with proofs. I know that arcs ST and TV are congruent, then segments ST and TV are also congruent. Segment SV is longer than segments ST and TV. Therefore; it is an isosceles triangle. Please help me put this in a proof form. Thank you
[CD8]This questions is answered
[CD9]Need help with this one
10 years ago
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