Compare two algorithms

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number 7 question I was given the answer below. The above algorithm is one that is in the textbook as an example. I need to know how the answer below compares with the algorithm above.

Worst case

    Best Case

In worst case, Outer loop will be executed n-1 times while inner loop will be executed j-1. So the time complexity in worst case is:

T(n) = n(n-1)/2

T(n) = Θ(n­2)

While in best case inner loop will never be executed so the time complexity in best case:

T(n)  = Θ(n­)

 

 

Need to have these two algorithms compared and how they differ.