The first thing I will be using will be my birthday, December 12, 1956, my integers will be as follows:
a=12
b=1
c=56
I will then plug in12 for variable a,and negative -1 for vairable b
1 to the third and 12 to the third equal 1728-negtive one
I will then raise the i
ntegers to the given exponent which is three.
1728- (-1)
Two negatives make a positive
1728 plus one
Final answer 1729.
I have again plugged in 12 for variable a and -1 for variable
In the beginning the two negatives became a positive
In the second the integers were squared and simplified: Adding two negatives became a positiveand mutiplying a negative by a negative became a positive.
Final answer 1729
(b-c)
----------
(2b-a)
-1-56
----------
2(-1) - 12
-3-12 and reduce to the lowest term would be
57
-----
14
All varibles was use in the expression 12 plugged in for a negative 1 for b
The first part of the equation the two negative was subtract thus resulting in a positive number. The divsor was also solved likewise, because the numerator and denominator is negative then you will get positive.
Final answer was reduced to its lowest term which is:
57
-----
14
I assume the answers was not a coincidence I would say this is the way math works that they are set to come to the same answer when the variables are plugged.