Lab 6

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Report6.docx

Experiment 6:

Student name:

Pre-lab section:

1) Introduction: Explain the theory behind this experiment in a paragraph between 150 and 250 words. (3 Points)

Suppose you are using external resources; include the reference. It would be best if you had any relevant formulas and explanations of each term. You may use the rich formula tools embedded here. 

2) Hypothesis: In an If /Then statement, highlight the purpose of the experiment.

For instance: If two same shape objects with different masses are dropped from the same height, they will hit the ground simultaneously. (1 point)

Post-lab section:

3) Attach an image of your signed data sheet here. (2 Points)

4) Attach your analysis here, including any table, chart, or plot image. (8 points)

This should include:

Table 1: 0.5 points

Table 2: 0.5 points

Table 3: 0.5 points

Table 4: 0.5 points

Table 5: 1.5 points

Table 6: 1.5 points

Table 7: 1.5 points

Table 8: 1.5 points

5) Attach the image of samples of your calculation here. (1 point)

6) In a paragraph between 100 and 150 words, explain what you Learn. What conclusion can you draw from the results of this lab assignment? (2 points)

7) In one sentence, compare the results of the experiment with your Hypothesis. Why? (1 point)

8) Attach your response to the questions in the lab manual here. (2 points)

Question 1: 1 point

Question 2: 1 point

PHY2048LExp6Theory.pdf

Introduction to necessary physical concept

Kinetic Energy: Energy of a body associated with its motion:

K = 1

2 mϑ

2

Potential Energy: Energy of a body associated with its position: U = mgh Total mechanical energy: E= K + U Conservation of total mechanical energy: If non-conservative

forces do no work, total mechanical energy of system is conserved: Ef = Ei → Uf + Kf = Ui + Ki (f − final , i−innitial)

Linear momentum: ⃗p = mϑ⃗ Conservation of linear momentum:

The total momentum of an isolated system (⟨ F⃗net ext ⟩ = 0 ) remains

constant. For a 2-body system, this implies: p⃗f tot = p⃗i

tot → m 1 ϑ⃗ 1 f + m2 ϑ⃗2 f = m1 ϑ⃗ 1i + m2 ϑ⃗2 i

Totally elastic collision

If both the total momentum and total kinetic energy of the two-ball system are conserved before and after collision, i.e.,

P⃗i tot (before collision)= P⃗f

tot (after collision)

and Ki tot (before collision) = Kf

tot (after collision)

Totally inelastic collision

If the total momentum but not the total kinetic energy of the two-ball system is conserved before and after collision, i.e.,

P⃗i tot (before collision)= P⃗f

tot (after collision)

but Ki tot (before collision) ≠ Kf

tot (after collision)

A

B

1

1

Figure 1

d T

mg

h

2

mg Photogate #1photogate #2

2 1

1 A

T

guide bar

Figure 2 Collision apparatus

to 850 interface to 850 interface

B

Illustrations for Experimental Set-up

Release ball #1 from A

Collision occurs at B

d → diameter of each ball

m → mass of each ball

h → height of drop

Explanation of Dimensions in Table 1

d → diameter of 1 ball

d1 → dimension of (1 ball + 1 velcro pad) = d + thickness of 1 velcro pad

d2 → dimension of (2 balls + 2 velcro pads) = 2 d1

Explanation of Time Measurements in Table 2

⟨t 1(elastic)⟩ → Time needed for ball #1 to pass through

photogate #1 before elastic collision

⟨t 2(elastic)⟩ → Time needed for ball #2 to pass through

photogate #2 after elastic collision

⟨t 1(inelastic )⟩ → Time needed for (ball #1 + 1 velcro pad) to pass

through photogate #1 before inelastic collision

⟨t 2(inelastic)⟩ → Time needed for (ball #1 + ball #2 + 2 velcro

pads) to pass through photogate #2 after inelastic collision

Computation of velocities in table 3

Key Idea:

velocity = dimensionof object passing through photosensor

time takenby object while passing through photosensor

Velocityϑ 1 → velocity of 1st ball before elastic collision :

ϑ 1 =

d

⟨t 1(elastic)⟩

Velocityϑ ' 2 → velocity of ball #2 after elastic collision:

ϑ ' 2 =

d

⟨t 2(elastic)⟩

Computation of velocities in table 3 (contd.)

Velocityϑ 1(i n)→ velocity of ball #1 before inelastic collision:

ϑ 1(i n) =

d 1

⟨t 1(inelastic )⟩

Velocityϑ→ velocity of 2-ball system after inelastic collision:

ϑ = d 2

⟨t 2(inelastic)⟩

Tables 4 through 8

Table 4: Verify total energy conservation for ball #1 between point A and point B just before elastic collision.

Tables 5 & 7 : Verify if the total momentum of 2-ball system is conserved.

Tables 6 & 8 : Verify if the total kinetic energy of 2 -ball system is conserved.

To verify conservation, we compute % difference between the total magnitude of each quantity before and after collision.

The % difference between quantitiesa andb is given by:

% difference = |a − b| 1

2 (a + b)

×100%

End of Theory

PHY2048LExp6DataandInstructions28129.pdf

Provided data for Exp 6 and instructions for data analysis and lab report

1. Provided data for Exp 6

Table 1 Data of the balls’ mass, dimension and position change. m (kg) d (m)

1 d (m)

2 d (m) h (m)

0.130 0.0314 0.0330 0.0660 0.0780

:m mass of one steel ball, :d the diameter of the steel ball,

1 d d= + the thickness of one velcro pad, 2 1

2 2d d d= = + the thickness of 2 velcro pad,

2 1 A B h h h h h= − = − : the vertical distance between points A & B as shown in Fig. 2.

Table 2 Computer recorded data from Measurement #1: elastic collision

Table 3 Computer recorded data from Measurement #2: inelastic collision

2. Instruction for data analysis

(a) Calculate 1( )elastic

t  , i.e., the average value of the three mean values in columns 1, 3 and 5 in Table 2.

Record the calculated data in Table 4.

(b) Calculate 2 ( )elastic t  , i.e., the average value of the three mean values in columns 2, 4 and 6 in Table 2.

Record the calculated data in Table 4.

(c) Calculate 1( )inelastic

t  , i.e., the average value of the three mean values in columns 1, 3 and 5 in Table 3.

Record the calculated data in Table 4.

(d) Calculate 2( )inelastic

t  , i.e., the average value of the three mean values in columns 2, 4 and 6 in Table

3. Record the calculated data in Table 4.

Table 4 Measured average time of ball(s) passing the photogates

1( )elastic t  (s)

2 ( )elastic t  (s)

1( )inelastic t  (s)

2( )inelastic t  (s)

(e) Use data in Tables 1 and 4 as well as Eqs. (4) and (7) to calculate the speed(s) of the ball(s) before

and after elastic/inelastic collision. Record the results in Table 5.

Table 5 Measured speed(s) of the ball(s) before and after elastic/inelastic collision

1  (m/s)

2   (m/s) 1( )in

 (m/s)  (m/s)

(f) Use Eqs. (1), (2), (6), and the data in Tables 1 and 5 to calculate the quantities listed in Tables 6 to 10.

Table 6 Total energy of ball #1 in Measurement #1 (elastic collision)

total energy of ball #1 at

position A (J)

total energy of ball #1 just

before collision (J)

%

difference

Is the total energy

conserved?

Table 7 Momentum conservation in Measurement #1 (elastic collision)

momentum before

collision (kg m/s)

momentum after

collision (kg m/s)

%

difference

Is the momentum

conserved?

Ball #1

Ball #2

total

Table 8 Kinetic energy conservation in Measurement #1 (elastic collision)

kinetic energy

before collision (J)

kinetic energy

after collision (J)

%

difference

Is the kinetic energy

conserved?

Ball #1

Ball #2

total

Table 9 Momentum conservation in Measurement #2 (inelastic collision)

momentum before

collision (kg m/s)

momentum after

collision (kg m/s)

%

difference

Is the momentum

conserved?

Ball #1

Ball #2

total

Table 10 Kinetic energies in Measurement #2 (inelastic collision)

kinetic energy

before collision (J)

kinetic energy

after collision (J)

%

difference

Is the kinetic energy

conserved?

Ball #1

Ball #2

total

3. Instructions for lab report

(a) Tables 1 to 10 with all the analyzed data must be included in your Exp 6 lab report.

(b) Answer to question #2 at the end of Exp 6 lab manual must be included in your Exp 6 report.

Note: Answer to question #1 is not required for online lab course.

(c) Other required contents and format for your lab report can be found in the syllabus.