Linear Programming

brittni
Template.xlsx

PART 1

BUAD - ASSIGNMENT 3 - OCTOBER 2017
PART 1
Inputs Outputs
Final Product Grade A (lbs) Grade B (lbs) Avg Quality Points /lb Production (cases) Demand Forecast
Canned Slices 80,000
Orange Juice 50,000
Frozen Concentrate 80,000
Total Grade A Used
Total Grade B Used
Total lbs used
Canned Slices Orange Juice Frozen Concentrate
Revenue
Variable Costs
Contribution to Profit
TOTAL Contribution to Profit
Fixed Cost of Oranges $1,800,000
Net Total Profit -$1,800,000

PART 2-LP

BUAD - ASSIGNMENT 3 - OCTOBER 2017
PART 1
a) The shaded cells below will be your variable cells in your Solver input file.
Calculations for all other cells are based on these 5 cells. Thus, you need only 5 variables.
Inputs Outputs
Final Product Grade A (lbs) Grade B (lbs) Avg Quality Points /lb Production (cases) Demand Forecast
Canned Slices 80,000
Orange Juice 50,000
Frozen Concentrate 80,000
Total Grade A Used
Total Grade B Used
Total lbs used
Note: Your formulation will have a constraint that forces the average quality points for orange slices to be at least 8 and another constraint
that forces the average quality points of orange juice to be at least 6. Use the following cells as the left-hand-side of these constraints
If you are having problems determing this Excel formula, see the worksheet 'hint'.
Left-hand-side of constraint (in terms of cells C11 and D11) that forces avg quality points of canned oranges to be at least 8: ----->
Left-hand-side of constraint (in terms of cells C12 and D12) that forces avg quality points of orange juice to be at least 6: ----->
Canned Slices Orange Juice Frozen Concentrate
Revenue
Variable Costs
Contribution to Profit
TOTAL Contribution to Profit
Fixed Cost of Oranges $1,800,000
Net Total Profit -$1,800,000
b)
% increase in profit =
c) Should the additional 80,000 lbs be purchased? Yes or No.
If yes, what's the new maximum profit? Use only your output from the 'Solution Report' worksheet to
answer. No credit otherwise.
If no, why not?

Hint

Suppose you wish to use the following constraint in a linear programming:
X/(X+Y) > 3
This constraint is non-linear and must be algebraically transformed into one that is linear:
X > 3(X+Y)
is equivalent to
2X + 3Y < 0
You would create a cell with the formula '2X + 3Y', then add a constraint with that cell
on the left-hand-side and '0' on the right-hand-side.