Descriptive Statistics
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NURS-8200S-1/NURS-8200-1-Methods for Evidence-Based-2021-Summer-QTR-Term-wks-1-thru-11-(05/31/2021-08/15/2021)-PT27•Assignment 2 - Week 4View Originality Report - Old Design
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DESCRIPTIVE STATISTICS 8
Descriptive Statistics
Jenny Zimmerman
Walden University
June 30, 2021
Part I
Descriptive Statistics
1N Minimum Maximum Mean Std.
Deviation Skewness
2Statistic Statistic Statistic Statistic Statistic Statistic Std.
Error
2Respondent's age at time of interview 1000 19.378 49.430 36.63733 6.198741 -.374 .077
3Highest school grade completed 989 1 16 11.28 1.561 -.727 .078
1Valid N (listwise) 989
FREQUENCIES VARIABLES=race/ethnicity workflow /STATISTICS=MINIMUM MAXIMUM /ORDER=ANALYSIS.
Frequencies
Statistics
3Race/ethnicity Currently employed? N Valid 998 998 Missing 2 2 Minimum 1 0 Maximum 4 1
Frequency Table
Race/ethnicity
3Frequency Percent Valid Percent Cumulative Percent
1Valid Black, not Hispanic 803 80.3 80.5 80.5 Hispanic 128 12.8 12.8 93.3 White, not Hispanic 53 5.3 5.3 98.6 Other 14 1.4 1.4 100.0
3Total 998 99.8 100.0 Missing Refused 1 .1 DK 1 .1 Total 2 .2
1Total 1000 100.0
Currently employed?
3Frequency Percent Valid Percent Cumulative Percent
1Valid No 546 54.6 54.7 54.7 Yes 452 45.2 45.3 100.0
3Total 998 99.8 100.0 Missing System 2 .2
1Total 1000 100.0
The total population of the age recorded was 1000, while those of highest school grade complete was 989.
4The people had a mean age of 36.637 and a standard deviation of 6.199.
This shows that most people deferred from the mean by up to 6.199 difference (George et al.
2016).
The variable of the highest grade complete is 11.28, with a small standard deviation of 1.56.
4On the race and ethnicity variable, the black and not Hispanic are 803, which is 80.3% of the population while Hispanic, where 128 which is 12.8%, whites and not Hispanic were 53 which is 5.3% and others, were 14 which is 1.4% of the population.
On the currently employed variable, 452 were employed, which is 45.2%of the population, and 456 were not employed, which is 45.6% of the population.
The total population of the age recorded was 1000, while those of highest school grade complete was 989.
4The people had a mean age of 36.637 and a standard deviation of 6.199.
This shows that most people deferred from the mean by up to 6.199 difference.
The variable of the highest grade complete is 11.28, with a small standard deviation of 1.56.
4On the race and ethnicity variable, the black and not Hispanic are 803, which is 80.3% of the population while Hispanic, where 128 which is 12.8%, whites and not Hispanic were 53 which is 5.3% and others, were 14 which is 1.4% of the population.
On the currently employed variable, 452 were employed, which is 45.2%of the population, and 456 were not employed, which is 45.6% of the population.
Part II
Figure 1.
Figure 2.
1.
______Neutral_________ skew
2.
_______Negative_______ skew
Part III
5Descriptive Descriptive Statistics
1N Minimum Maximum Mean Std.
Deviation Skewness
2Statistic Statistic Statistic Statistic Std.
1Error Statistic Statistic Std.
Error
2Family income prior month, all sources 895 $0 $6,593 $1,172.59 $26.345 $788.153 2.030 .082
1Valid N (listwise) 895
1.
3What is the mean income in this sample?
6___$ 1,172.59___
2.
3What is the standard deviation (SD)?
___$ 788.153____
3.
3What is the standard error of the mean?
___$26.345___
4.
3Compute a 95% confidence interval around the mean. (Use 1.96 for the 95% CI and get the standard error from the descriptive statistics table). You should get a range (2 numbers) for the salary. The formula is as follows: 95% CI = [mean ± (1.96 SE)] ___95% CI = (1720.95 to 1824.226) ___
5.
3Compute a 99% confidence interval around the mean. (Use 2.58 for the 99% CI and get the standard error from the descriptive statistics table). You should get a range (2 numbers) for the salary. The formula is as follows:
799% CI = [mean ± (2.58 SE)] ____99% CI = 1704.62 to 1840.56___
6.
3Which interval is wider?
Explain.
8The 99% CI interval is wider.
This is because when the confidence interval gets higher, the range widens to increase the probability of the mean falling within it (George et al.
2016)
References.
George, D., & Mallery, P.
(2016).
Descriptive statistics.
In IBM SPSS statistics 23 step by step (pp.
126-134).
Routledge.
Source Matches (35)- 1Student paper100%
Student paper
N Minimum Maximum Mean Std.
Original source
N Minimum Maximum Mean Std
- 2Student paper100%
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Statistic Statistic Statistic Statistic Statistic Statistic Std.
Original source
Statistic Statistic Statistic Statistic Statistic Statistic Std
- 2Student paper100%
Student paper
Respondent's age at time of interview 1000 19.378 49.430 36.63733 6.198741 -.374 .077
Original source
Respondent's age at time of interview 1000 19.378 49.430 36.63733 6.198741 -.374 .077
- 3Student paper100%
Student paper
Highest school grade completed 989 1 16 11.28 1.561 -.727 .078
Original source
Highest school grade completed 989 1 16 11.28 1.561 -.727 .078
- 1Student paper100%
Student paper
Valid N (listwise) 989
Original source
Valid N (listwise) 989
- 3Student paper100%
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Race/ethnicity Currently employed? N Valid 998 998 Missing 2 2 Minimum 1 0
Original source
Race/ethnicity Currently employed N Valid 998 998 Missing 2 2 Minimum 1 0
- 3Student paper100%
Student paper
Maximum 4 1
Original source
Maximum 4 1
- 3Student paper100%
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Frequency Percent Valid Percent Cumulative Percent
Original source
Frequency Percent Valid Percent Cumulative Percent
- 1Student paper100%
Student paper
Valid Black, not Hispanic 803 80.3 80.5 80.5 Hispanic 128 12.8 12.8 93.3 White, not Hispanic 53 5.3 5.3 98.6 Other 14 1.4 1.4 100.0
Original source
Valid Black, not Hispanic 803 80.3 80.5 80.5 Hispanic 128 12.8 12.8 93.3 White, not Hispanic 53 5.3 5.3 98.6 Other 14 1.4 1.4 100.0
- 3Student paper100%
Student paper
Total 998 99.8 100.0 Missing Refused 1 .1 DK 1 .1 Total 2 .2
Original source
Total 998 99.8 100.0 Missing Refused 1 .1 DK 1 .1 Total 2 .2
- 1Student paper100%
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Total 1000 100.0
Original source
Total 1000 100.0
- 3Student paper100%
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Frequency Percent Valid Percent Cumulative Percent
Original source
Frequency Percent Valid Percent Cumulative Percent
- 1Student paper100%
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Valid No 546 54.6 54.7 54.7 Yes 452 45.2 45.3 100.0
Original source
Valid No 546 54.6 54.7 54.7 Yes 452 45.2 45.3 100.0
- 3Student paper100%
Student paper
Total 998 99.8 100.0 Missing System 2 .2
Original source
Total 998 99.8 100.0 Missing System 2 .2
- 1Student paper100%
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Total 1000 100.0
Original source
Total 1000 100.0
- 4Student paper63%
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The people had a mean age of 36.637 and a standard deviation of 6.199.
Original source
From the analysis, the mean age of the participants stood at around 36.64 years with a standard deviation of 6.199
- 4Student paper70%
Student paper
On the race and ethnicity variable, the black and not Hispanic are 803, which is 80.3% of the population while Hispanic, where 128 which is 12.8%, whites and not Hispanic were 53 which is 5.3% and others, were 14 which is 1.4% of the population.
Original source
From the data, the sample population and proportion of Black, not Hispanic, Hispanic, White, not Hispanic, and Other stood at 803 (80.3%), 128 (12.8%), 53 (5.3%), and 14 (1.4%) respectively
- 4Student paper63%
Student paper
The people had a mean age of 36.637 and a standard deviation of 6.199.
Original source
From the analysis, the mean age of the participants stood at around 36.64 years with a standard deviation of 6.199
- 4Student paper70%
Student paper
On the race and ethnicity variable, the black and not Hispanic are 803, which is 80.3% of the population while Hispanic, where 128 which is 12.8%, whites and not Hispanic were 53 which is 5.3% and others, were 14 which is 1.4% of the population.
Original source
From the data, the sample population and proportion of Black, not Hispanic, Hispanic, White, not Hispanic, and Other stood at 803 (80.3%), 128 (12.8%), 53 (5.3%), and 14 (1.4%) respectively
- 5Student paper65%
Student paper
Descriptive Descriptive Statistics
Original source
DESCRIPTIVE STATISTICS 2 DESCRIPTIVE STATISTICS 2
- 1Student paper100%
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N Minimum Maximum Mean Std.
Original source
N Minimum Maximum Mean Std
- 2Student paper100%
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Statistic Statistic Statistic Statistic Std.
Original source
Statistic Statistic Statistic Statistic Std
- 1Student paper100%
Student paper
Error Statistic Statistic Std.
Original source
Error Statistic Statistic Std
- 2Student paper100%
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Family income prior month, all sources 895 $0 $6,593 $1,172.59 $26.345 $788.153 2.030 .082
Original source
Family income prior month, all sources 895 $0 $6,593 $1,172.59 $26.345 $788.153 2.030 .082
- 1Student paper100%
Student paper
Valid N (listwise) 895
Original source
Valid N (listwise) 895
- 3Student paper100%
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What is the mean income in this sample?
Original source
What is the mean income in this sample
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___$ 1,172.59___
Original source
$1,172.59
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What is the standard deviation (SD)?
Original source
What is the standard deviation (SD)
- 3Student paper100%
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What is the standard error of the mean?
Original source
What is the standard error of the mean
- 3Student paper100%
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Compute a 95% confidence interval around the mean. (Use 1.96 for the 95% CI and get the standard error from the descriptive statistics table). You should get a range (2 numbers) for the salary. The formula is as follows:
Original source
Compute a 95% confidence interval around the mean (Use 1.96 for the 95% CI and get the standard error from the descriptive statistics table) You should get a range (2 numbers) for the salary The formula is as follows
- 3Student paper66%
Student paper
95% CI = [mean ± (1.96 SE)] ___95% CI = (1720.95 to 1824.226) ___
Original source
95% CI = [mean ± (1.96 SE)]
- 3Student paper100%
Student paper
Compute a 99% confidence interval around the mean. (Use 2.58 for the 99% CI and get the standard error from the descriptive statistics table). You should get a range (2 numbers) for the salary. The formula is as follows:
Original source
Compute a 99% confidence interval around the mean (Use 2.58 for the 99% CI and get the standard error from the descriptive statistics table) You should get a range (2 numbers) for the salary The formula is as follows
- 7Student paper68%
Student paper
99% CI = [mean ± (2.58 SE)] ____99% CI = 1704.62 to 1840.56___
Original source
99% CI = [mean ± (2.58 SE)] A 99% CI on the population is 2.576
- 3Student paper100%
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Which interval is wider?
Original source
Which interval is wider
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The 99% CI interval is wider.
Original source
The 99% interval is wider
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