40 statistics questions
Grove & Cipher Exercise 35
Crosstabs
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Case Processing Summary |
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Cases |
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|
Valid |
Missing |
Total |
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|
|
N |
Percent |
N |
Percent |
N |
Percent |
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Antibiotic_Use * Candiduria |
97 |
100.0% |
0 |
0.0% |
97 |
100.0% |
|
Antibiotic_Use * Candiduria Crosstabulation |
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Count |
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|
Candiduria |
Total |
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|
|
No |
Yes |
|
|
|
Antibiotic_Use |
No |
0 |
39 |
39 |
|
|
Yes |
43 |
15 |
58 |
|
Total |
43 |
54 |
97 |
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Chi-Square Tests |
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|
Value |
df |
Asymptotic Significance (2-sided) |
Exact Sig. (2-sided) |
Exact Sig. (1-sided) |
|
Pearson Chi-Square |
51.938a |
1 |
.000 |
|
|
|
Continuity Correctionb |
48.977 |
1 |
.000 |
|
|
|
Likelihood Ratio |
66.914 |
1 |
.001 |
|
|
|
Fisher's Exact Test |
|
|
|
.000 |
.000 |
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Linear-by-Linear Association |
51.402 |
1 |
.000 |
|
|
|
N of Valid Cases |
97 |
|
|
|
|
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a. 0 cells (0.0%) have expected count less than 5. The minimum expected count is 17.29. |
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b. Computed only for a 2x2 table |