Assignment !!
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© 2014 Pearson Education, Inc.
Inventory Management
PowerPoint presentation to accompany
Heizer and Render
Operations Management, Eleventh Edition
Principles of Operations Management, Ninth Edition
PowerPoint slides by Jeff Heyl
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© 2014 Pearson Education, Inc.
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© 2014 Pearson Education, Inc.
Outline
Global Company Profile:
Amazon.com
- The Importance of Inventory
- Managing Inventory
- Inventory Models
- Inventory Models for Independent Demand
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Outline - Continued
Probabilistic Models and Safety Stock
Single-Period Model
Fixed-Period (P) Systems
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Learning Objectives
When you complete this chapter you should be able to:
- Conduct an ABC analysis
- Explain and use cycle counting
- Explain and use the EOQ model for independent inventory demand
- Compute a reorder point and safety stock
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Learning Objectives
When you complete this chapter you should be able to:
- Apply the production order quantity model
- Explain and use the quantity discount model
- Understand service levels and probabilistic inventory models
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Inventory Management at Amazon.com
- Amazon.com started as a “virtual” retailer – no inventory, no warehouses, no overhead; just computers taking orders to be filled by others
- Growth has forced Amazon.com to become a world leader in warehousing and inventory management
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Inventory Management at Amazon.com
Each order is assigned by computer to the closest distribution center that has the product(s)
A “flow meister” at each distribution center assigns work crews
Lights indicate products that are to be picked and the light is reset
Items are placed in crates on a conveyor, bar code scanners scan each item 15 times to virtually eliminate errors
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Inventory Management at Amazon.com
- Crates arrive at central point where items are boxed and labeled with new bar code
- Gift wrapping is done by hand at 30 packages per hour
- Completed boxes are packed, taped, weighed and labeled before leaving warehouse in a truck
- Order arrives at customer within 1 - 2 days
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Inventory Management
The objective of inventory management is to strike a balance between inventory investment and customer service
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Importance of Inventory
- One of the most expensive assets of many companies representing as much as 50% of total invested capital
- Operations managers must balance inventory investment and customer service
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Functions of Inventory
- To provide a selection of goods for anticipated demand and to separate the firm from fluctuations in demand
- To decouple or separate various parts of the production process
- To take advantage of quantity discounts
- To hedge against inflation
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Types of Inventory
- Raw material
- Purchased but not processed
- Work-in-process (WIP)
- Undergone some change but not completed
- A function of cycle time for a product
- Maintenance/repair/operating (MRO)
- Necessary to keep machinery and processes productive
- Finished goods
- Completed product awaiting shipment
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The Material Flow Cycle
Figure 12.1
Input Wait for Wait to Move Wait in queue Setup Run Output
inspection be moved time for operator time time
Cycle time
95% 5%
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Managing Inventory
- How inventory items can be classified (ABC analysis)
- How accurate inventory records can be maintained
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ABC Analysis
- Divides inventory into three classes based on annual dollar volume
- Class A - high annual dollar volume
- Class B - medium annual dollar volume
- Class C - low annual dollar volume
- Used to establish policies that focus on the few critical parts and not the many trivial ones
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ABC Analysis
| ABC Calculation | ||||||||
| (1) | (2) | (3) | (4) | (5) | (6) | (7) | ||
| ITEM STOCK NUMBER | PERCENT OF NUMBER OF ITEMS STOCKED | ANNUAL VOLUME (UNITS) | x | UNIT COST | = | ANNUAL DOLLAR VOLUME | PERCENT OF ANNUAL DOLLAR VOLUME | CLASS |
| #10286 | 20% | 1,000 | $ 90.00 | $ 90,000 | 38.8% | A | ||
| #11526 | 500 | 154.00 | 77,000 | 33.2% | A | |||
| #12760 | 1,550 | 17.00 | 26,350 | 11.3% | B | |||
| #10867 | 30% | 350 | 42.86 | 15,001 | 6.4% | B | ||
| #10500 | 1,000 | 12.50 | 12,500 | 5.4% | B | |||
| #12572 | 600 | $ 14.17 | $ 8,502 | 3.7% | C | |||
| #14075 | 2,000 | .60 | 1,200 | .5% | C | |||
| #01036 | 50% | 100 | 8.50 | 850 | .4% | C | ||
| #01307 | 1,200 | .42 | 504 | .2% | C | |||
| #10572 | 250 | .60 | 150 | .1% | C | |||
| 8,550 | $232,057 | 100.0% |
72%
23%
5%
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ABC Analysis
Figure 12.2
A Items
B Items
| | | | | | | | | |
10 20 30 40 50 60 70 80 90 100
Percentage of annual dollar usage
80 –
70 –
60 –
50 –
40 –
30 –
20 –
10 –
0 –
Percentage of inventory items
C Items
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ABC Analysis
- Other criteria than annual dollar volume may be used
- High shortage or holding cost
- Anticipated engineering changes
- Delivery problems
- Quality problems
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ABC Analysis
- Policies employed may include
More emphasis on supplier development for A items
Tighter physical inventory control for A items
More care in forecasting A items
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Record Accuracy
- Accurate records are a critical ingredient in production and inventory systems
- Periodic systems require regular checks of inventory
- Two-bin system
- Perpetual inventory tracks receipts and subtractions on a continuing basis
- May be semi-automated
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Record Accuracy
- Incoming and outgoing
record keeping must be
accurate - Stockrooms should be secure
- Necessary to make precise decisions about ordering, scheduling, and shipping
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Cycle Counting
- Items are counted and records updated on a periodic basis
- Often used with ABC analysis
- Has several advantages
Eliminates shutdowns and interruptions
Eliminates annual inventory adjustment
Trained personnel audit inventory accuracy
Allows causes of errors to be identified and corrected
Maintains accurate inventory records
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Cycle Counting Example
5,000 items in inventory, 500 A items, 1,750 B items, 2,750 C items
Policy is to count A items every month (20 working days), B items every quarter (60 days), and C items every six months (120 days)
| ITEM CLASS | QUANTITY | CYCLE COUNTING POLICY | NUMBER OF ITEMS COUNTED PER DAY | |
| A | 500 | Each month | 500/20 = | 25/day |
| B | 1,750 | Each quarter | 1,750/60 = | 29/day |
| C | 2,750 | Every 6 months | 2,750/120 = | 23/day |
| 77/day |
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Control of Service Inventories
- Can be a critical component
of profitability - Losses may come from
shrinkage or pilferage - Applicable techniques include
Good personnel selection, training, and discipline
Tight control of incoming shipments
Effective control of all goods leaving facility
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Inventory Models
- Independent demand - the demand for item is independent of the demand for any other item in inventory
- Dependent demand - the demand for item is dependent upon the demand for some other item in the inventory
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Inventory Models
- Holding costs - the costs of holding or “carrying” inventory over time
- Ordering costs - the costs of placing an order and receiving goods
- Setup costs - cost to prepare a machine or process for manufacturing an order
- May be highly correlated with setup time
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Holding Costs
| TABLE 12.1 | Determining Inventory Holding Costs |
| CATEGORY | COST (AND RANGE) AS A PERCENT OF INVENTORY VALUE |
| Housing costs (building rent or depreciation, operating costs, taxes, insurance) | 6% (3 - 10%) |
| Material handling costs (equipment lease or depreciation, power, operating cost) | 3% (1 - 3.5%) |
| Labor cost (receiving, warehousing, security) | 3% (3 - 5%) |
| Investment costs (borrowing costs, taxes, and insurance on inventory) | 11% (6 - 24%) |
| Pilferage, space, and obsolescence (much higher in industries undergoing rapid change like PCs and cell phones) | 3% (2 - 5%) |
| Overall carrying cost | 26% |
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Holding Costs
| TABLE 12.1 | Determining Inventory Holding Costs |
| CATEGORY | COST (AND RANGE) AS A PERCENT OF INVENTORY VALUE |
| Housing costs (building rent or depreciation, operating costs, taxes, insurance) | 6% (3 - 10%) |
| Material handling costs (equipment lease or depreciation, power, operating cost) | 3% (1 - 3.5%) |
| Labor cost (receiving, warehousing, security) | 3% (3 - 5%) |
| Investment costs (borrowing costs, taxes, and insurance on inventory) | 11% (6 - 24%) |
| Pilferage, space, and obsolescence (much higher in industries undergoing rapid change like PCs and cell phones) | 3% (2 - 5%) |
| Overall carrying cost | 26% |
Holding costs vary considerably depending on the business, location, and interest rates. Generally greater than 15%, some high tech and fashion items have holding costs greater than 40%.
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Inventory Models for Independent Demand
Need to determine when and how much to order
- Basic economic order quantity (EOQ) model
- Production order quantity model
- Quantity discount model
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Basic EOQ Model
- Demand is known, constant, and independent
- Lead time is known and constant
- Receipt of inventory is instantaneous and complete
- Quantity discounts are not possible
- Only variable costs are setup (or ordering) and holding
- Stockouts can be completely avoided
Important assumptions
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Inventory Usage Over Time
Figure 12.3
Order quantity = Q (maximum inventory level)
Usage rate
Average inventory on hand
Q
2
Inventory level
Time
0
Minimum inventory
Total order received
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Minimizing Costs
Objective is to minimize total costs
Table 12.4(c)
Annual cost
Order quantity
Total cost of holding and setup (order)
Holding cost
Setup (order) cost
Minimum total cost
Optimal order quantity (Q*)
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Minimizing Costs
- By minimizing the sum of setup (or ordering) and holding costs, total costs are minimized
- Optimal order size Q* will minimize total cost
- A reduction in either cost reduces the total cost
- Optimal order quantity occurs when holding cost and setup cost are equal
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Minimizing Costs
Q = Number of pieces per order
Q* = Optimal number of pieces per order (EOQ)
D = Annual demand in units for the inventory item
S = Setup or ordering cost for each order
H = Holding or carrying cost per unit per year
Annual setup cost = (Number of orders placed per year)
x (Setup or order cost per order)
Annual demand
Number of units in each order
Setup or order cost per order
=
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Q = Number of pieces per order
Q* = Optimal number of pieces per order (EOQ)
D = Annual demand in units for the inventory item
S = Setup or ordering cost for each order
H = Holding or carrying cost per unit per year
Minimizing Costs
Annual holding cost = (Average inventory level)
x (Holding cost per unit per year)
Order quantity
2
(Holding cost per unit per year)
=
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© 2014 Pearson Education, Inc.
Minimizing Costs
Optimal order quantity is found when annual setup cost equals annual holding cost
Solving for Q*
Q = Number of pieces per order
Q* = Optimal number of pieces per order (EOQ)
D = Annual demand in units for the inventory item
S = Setup or ordering cost for each order
H = Holding or carrying cost per unit per year
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An EOQ Example
Determine optimal number of needles to order
D = 1,000 units
S = $10 per order
H = $.50 per unit per year
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An EOQ Example
Determine expected number of orders
D = 1,000 units Q* = 200 units
S = $10 per order
H = $.50 per unit per year
1,000
200
N = = 5 orders per year
Demand
Order quantity
= N = =
Expected number of orders
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An EOQ Example
Determine optimal time between orders
D = 1,000 units Q* = 200 units
S = $10 per order N = 5 orders/year
H = $.50 per unit per year
250
5
T = = 50 days between orders
Number of working days per year
Expected number of orders
= T =
Expected time between orders
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An EOQ Example
Determine the total annual cost
D = 1,000 units Q* = 200 units
S = $10 per order N = 5 orders/year
H = $.50 per unit per year T = 50 days
Total annual cost = Setup cost + Holding cost
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The EOQ Model
When including actual cost of material P
Total annual cost = Setup cost + Holding cost + Product cost
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Robust Model
- The EOQ model is robust
- It works even if all parameters and assumptions are not met
- The total cost curve is relatively flat in the area of the EOQ
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An EOQ Example
Determine optimal number of needles to order
D = 1,000 units Q* = 200 units
S = $10 per order N = 5 orders/year
H = $.50 per unit per year T = 50 days
Only 2% less than the total cost of $125 when the order quantity was 200
1,500 units
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Reorder Points
- EOQ answers the “how much” question
- The reorder point (ROP) tells “when” to order
- Lead time (L) is the time between placing and receiving an order
= d x L
Lead time for a new order in days
Demand per day
ROP =
D
Number of working days in a year
d =
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Reorder Point Curve
Figure 12.5
Resupply takes place as order arrives
Q*
ROP (units)
Inventory level (units)
Time (days)
Lead time = L
Slope = units/day = d
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Reorder Point Example
Demand = 8,000 iPods per year
250 working day year
Lead time for orders is 3 working days, may take 4
ROP = d x L
= 8,000/250 = 32 units
= 32 units per day x 3 days = 96 units
= 32 units per day x 4 days = 128 units
D
Number of working days in a year
d =
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Production Order Quantity Model
Used when inventory builds up over a period of time after an order is placed
Used when units are produced and sold simultaneously
Figure 12.6
Inventory level
Time
Demand part of cycle with no production (only usage)
Part of inventory cycle during which production (and usage) is taking place
t
Maximum inventory
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Production Order Quantity Model
Q = Number of pieces per order p = Daily production rate
H = Holding cost per unit per year d = Daily demand/usage rate
t = Length of the production run in days
Annual inventory holding cost
Holding cost
per unit per year
= (Average inventory level) x
Annual inventory level
= (Maximum inventory level)/2
Maximum inventory level
Total produced during the production run
Total used during the production run
= –
= pt – dt
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Production Order Quantity Model
Q = Number of pieces per order p = Daily production rate
H = Holding cost per unit per year d = Daily demand/usage rate
t = Length of the production run in days
However, Q = total produced = pt ; thus t = Q/p
Maximum inventory level
Total produced during the production run
Total used during the production run
= –
= pt – dt
Maximum inventory level
Q
p
Q
p
d
p
= p – d = Q 1 –
d
p
Q
2
Maximum inventory level
2
Holding cost = (H) = 1 – H
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Production Order Quantity Model
Q = Number of pieces per order p = Daily production rate
H = Holding cost per unit per year d = Daily demand/usage rate
t = Length of the production run in days
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Production Order Quantity Example
D = 1,000 units p = 8 units per day
S = $10 d = 4 units per day
H = $0.50 per unit per year
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Production Order Quantity Model
When annual data are used the equation becomes
Note:
D
Number of days the plant is in operation
1,000
250
d = 4 = =
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Quantity Discount Models
- Reduced prices are often available when larger quantities are purchased
- Trade-off is between reduced product cost and increased holding cost
| TABLE 12.2 | A Quantity Discount Schedule | ||
| DISCOUNT NUMBER | DISCOUNT QUANTITY | DISCOUNT (%) | DISCOUNT PRICE (P) |
| 1 | 0 to 999 | no discount | $5.00 |
| 2 | 1,000 to 1,999 | 4 | $4.80 |
| 3 | 2,000 and over | 5 | $4.75 |
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Quantity Discount Models
Total annual cost = Setup cost + Holding cost + Product cost
where Q = Quantity ordered P = Price per unit
D = Annual demand in units H = Holding cost per unit per year
S = Ordering or setup cost per order
Because unit price varies, holding cost (H) is expressed as a percent (I) of unit price (P)
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Quantity Discount Models
Steps in analyzing a quantity discount
- For each discount, calculate Q*
- If Q* for a discount doesn’t qualify, choose the lowest possible quantity to get the discount
- Compute the total cost for each Q* or adjusted value from Step 2
- Select the Q* that gives the lowest total cost
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Quantity Discount Models
Figure 12.7
1,000
2,000
Total cost $
0
Order quantity
Q* for discount 2 is below the allowable range at point a and must be adjusted upward to 1,000 units at point b
a
b
1st price break
2nd price break
Total cost curve for discount 1
Total cost curve for discount 2
Total cost curve for discount 3
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Quantity Discount Example
Calculate Q* for every discount
Q1* = = 700 cars/order
2(5,000)(49)
(.2)(5.00)
Q2* = = 714 cars/order
2(5,000)(49)
(.2)(4.80)
Q3* = = 718 cars/order
2(5,000)(49)
(.2)(4.75)
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© 2014 Pearson Education, Inc.
Quantity Discount Example
Calculate Q* for every discount
Q1* = = 700 cars/order
2(5,000)(49)
(.2)(5.00)
Q2* = = 714 cars/order
2(5,000)(49)
(.2)(4.80)
Q3* = = 718 cars/order
2(5,000)(49)
(.2)(4.75)
1,000 — adjusted
2,000 — adjusted
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Quantity Discount Example
Choose the price and quantity that gives the lowest total cost
Buy 1,000 units at $4.80 per unit
| TABLE 12.3 | Total Cost Computations for Wohl’s Discount Store | |||||
| DISCOUNT NUMBER | UNIT PRICE | ORDER QUANTITY | ANNUAL PRODUCT COST | ANNUAL ORDERING COST | ANNUAL HOLDING COST | TOTAL |
| 1 | $5.00 | 700 | $25,000 | $350 | $350 | $25,700 |
| 2 | $4.80 | 1,000 | $24,000 | $245 | $480 | $24,725 |
| 3 | $4.75 | 2,000 | $23.750 | $122.50 | $950 | $24,822.50 |
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Probabilistic Models and
Safety Stock
- Used when demand is not constant or certain
- Use safety stock to achieve a desired service level and avoid stockouts
ROP = d x L + ss
Annual stockout costs = the sum of the units short x the probability x the stockout cost/unit
x the number of orders per year
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Safety Stock Example
ROP = 50 units Stockout cost = $40 per frame
Orders per year = 6 Carrying cost = $5 per frame per year
| NUMBER OF UNITS | PROBABILITY |
| 30 | .2 |
| 40 | .2 |
| ROP 50 | .3 |
| 60 | .2 |
| 70 | .1 |
| 1.0 |
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Safety Stock Example
ROP = 50 units Stockout cost = $40 per frame
Orders per year = 6 Carrying cost = $5 per frame per year
A safety stock of 20 frames gives the lowest total cost
ROP = 50 + 20 = 70 frames
| SAFETY STOCK | ADDITIONAL HOLDING COST | STOCKOUT COST | TOTAL COST |
| 20 | (20)($5) = $100 | $0 | $100 |
| 10 | (10)($5) = $ 50 | (10)(.1)($40)(6) = $240 | $290 |
| 0 | $ 0 | (10)(.2)($40)(6) + (20)(.1)($40)(6) = $960 | $960 |
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Probabilistic Demand
Figure 12.8
Safety stock
16.5 units
ROP
Place order
Inventory level
Time
0
Minimum demand during lead time
Maximum demand during lead time
Mean demand during lead time
Normal distribution probability of demand during lead time
Expected demand during lead time (350 kits)
ROP = 350 + safety stock of 16.5 = 366.5
Receive order
Lead time
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Probabilistic Demand
Use prescribed service levels to set safety stock when the cost of stockouts cannot be determined
ROP = demand during lead time + ZsdLT
where Z = Number of standard deviations
sdLT = Standard deviation of demand during lead time
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Probabilistic Demand
Safety stock
Probability of
no stockout
95% of the time
Mean demand 350
ROP = ? kits
Quantity
Number of
standard deviations
0
z
Risk of a stockout (5% of area of normal curve)
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Probabilistic Example
m = Average demand = 350 kits
sdLT = Standard deviation of
demand during lead time = 10 kits
Z = 5% stockout policy (service level = 95%)
Using Appendix I, for an area under the curve of 95%, the Z = 1.65
Safety stock = ZsdLT = 1.65(10) = 16.5 kits
Reorder point = Expected demand during lead time + Safety stock
= 350 kits + 16.5 kits of safety stock
= 366.5 or 367 kits
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Other Probabilistic Models
- When data on demand during lead time is not available, there are other models available
When demand is variable and lead time is constant
When lead time is variable and demand is constant
When both demand and lead time are variable
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Other Probabilistic Models
Demand is variable and lead time is constant
ROP = (Average daily demand
x Lead time in days) + ZsdLT
where sdLT = sd Lead time
sd = standard deviation of demand per day
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Probabilistic Example
Average daily demand (normally distributed) = 15
Lead time in days (constant) = 2
Standard deviation of daily demand = 5
Service level = 90%
Z for 90% = 1.28
From Appendix I
Safety stock is about 9 computers
ROP = (15 units x 2 days) + ZsdLT
= 30 + 1.28(5)( 2)
= 30 + 9.02 = 39.02 ≈ 39
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Other Probabilistic Models
Lead time is variable and demand is constant
ROP = (Daily demand x Average lead time in days) + Z x (Daily demand) x sLT
where sLT = Standard deviation of lead time in days
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Probabilistic Example
Daily demand (constant) = 10
Average lead time = 6 days
Standard deviation of lead time = sLT = 1
Service level = 98%, so Z (from Appendix I) = 2.055
ROP = (10 units x 6 days) + 2.055(10 units)(1)
= 60 + 20.55 = 80.55
Reorder point is about 81 cameras
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Other Probabilistic Models
Both demand and lead time are variable
ROP = (Average daily demand
x Average lead time) + ZsdLT
where sd = Standard deviation of demand per day
sLT = Standard deviation of lead time in days
sdLT = (Average lead time x sd2)
+ (Average daily demand)2s2LT
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Probabilistic Example
Average daily demand (normally distributed) = 150
Standard deviation = sd = 16
Average lead time 5 days (normally distributed)
Standard deviation = sLT = 1 day
Service level = 95%, so Z = 1.65 (from Appendix I)
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Single-Period Model
- Only one order is placed for a product
- Units have little or no value at the end of the sales period
Cs = Cost of shortage = Sales price/unit – Cost/unit
Co = Cost of overage = Cost/unit – Salvage value
Cs
Cs + Co
Service level =
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Single-Period Example
Average demand = = 120 papers/day
Standard deviation = = 15 papers
Cs = cost of shortage = $1.25 – $.70 = $.55
Co = cost of overage = $.70 – $.30 = $.40
Service level =
Cs
Cs + Co
.55
.55 + .40
.55
.95
=
= = .579
Service level 57.9%
Optimal stocking level
= 120
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Single-Period Example
From Appendix I, for the area .579, Z .20
The optimal stocking level
= 120 copies + (.20)()
= 120 + (.20)(15) = 120 + 3 = 123 papers
The stockout risk = 1 – Service level
= 1 – .579 = .422 = 42.2%
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Fixed-Period (P) Systems
- Orders placed at the end of a fixed period
- Inventory counted only at end of period
- Order brings inventory up to target level
- Only relevant costs are ordering and holding
- Lead times are known and constant
- Items are independent of one another
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Fixed-Period (P) Systems
Figure 12.9
On-hand inventory
Time
Q1
Q2
Target quantity (T)
P
P
P
Q3
Q4
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Fixed-Period Systems
- Inventory is only counted at each review period
- May be scheduled at convenient times
- Appropriate in routine situations
- May result in stockouts between periods
- May require increased safety stock
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© 2014 Pearson Education, Inc.
All rights reserved. No part of this publication may be reproduced, stored in a retrieval system, or transmitted, in any form or by any means, electronic, mechanical, photocopying, recording, or otherwise, without the prior written permission of the publisher.
Printed in the United States of America.
= D Q ⎛
⎝ ⎜
⎞
⎠ ⎟S
=
D
Q
æ
è
ç
ö
ø
÷
S
Annual setup cost = D Q S
Annual setup cost =
D
Q
S
= Q 2
⎛
⎝ ⎜
⎞
⎠ ⎟H
=
Q
2
æ
è
ç
ö
ø
÷
H
Annual setup cost = D Q S
Annual setup cost =
D
Q
S
Annual holding cost = Q 2 H
Annual holding cost =
Q
2
H
D Q S =
Q 2
⎛
⎝ ⎜
⎞
⎠ ⎟H
D
Q
S =
Q
2
æ
è
ç
ö
ø
÷
H
2DS =Q2H
Q2 = 2DS H
Q* = 2DS H
2DS=Q
2
H
Q
2
=
2DS
H
Q
*
=
2DS
H
Q* = 2DS H
Q
*
=
2DS
H
Q* = 2(1,000)(10)
0.50 = 40,000 = 200 units
Q
*
=
2(1,000)(10)
0.50
=40,000=200 units
D Q*
D
Q
*
TC = D Q S + Q 2 H
= 1,000 200
($10)+ 200 2 ($.50)
= (5)($10)+(100)($.50) =$50+$50=$100
TC=
D
Q
S+
Q
2
H
=
1,000
200
($10)+
200
2
($.50)
=(5)($10)+(100)($.50)
=$50+$50=$100
TC = D Q S + Q 2 H +PD
TC=
D
Q
S+
Q
2
H+PD
TC = D Q S + Q 2 H
= 1,500 200
($10)+ 200 2 ($.50)
=$75+$50=$125
TC=
D
Q
S+
Q
2
H
=
1,500
200
($10)+
200
2
($.50)
=$75+$50=$125
= 1,500 244.9
($10)+ 244.9 2
($.50)
=6.125($10)+122.45($.50) =$61.25+$61.22=$122.47
=
1,500
244.9
($10)+
244.9
2
($.50)
=6.125($10)+122.45($.50)
=$61.25+$61.22=$122.47
Setup cost = (D /Q)S Holding cost = 1
2 HQ 1− d p( )⎡⎣ ⎤⎦
Setup cost = (D/Q)S
Holding cost =
1
2
HQ1-dp
(
)
é
ë
ù
û
D Q S = 1
2 HQ 1− d p( )⎡⎣ ⎤⎦
Q2 = 2DS
H 1− d p( )⎡⎣ ⎤⎦
Qp * =
2DS H 1− d p( )⎡⎣ ⎤⎦
D
Q
S=
1
2
HQ1-dp
(
)
é
ë
ù
û
Q
2
=
2DS
H1-dp
()
é
ë
ù
û
Q
p
*
=
2DS
H1-dp
()
é
ë
ù
û
Qp * =
2DS H 1− d p( )⎡⎣ ⎤⎦
Qp * =
2(1,000)(10) 0.50 1−(4 8)⎡⎣ ⎤⎦
= 20,000
0.50(1 2) = 80,000
= 282.8 hubcaps, or 283 hubcaps
Q
p
*
=
2DS
H1-dp
()
é
ë
ù
û
Q
p
*
=
2(1,000)(10)
0.501-(48)
é
ë
ù
û
=
20,000
0.50(12)
=80,000
=282.8 hubcaps, or 283 hubcaps
Qp * =
2DS
H 1− Annual demand rate Annual production rate
⎛
⎝ ⎜
⎞
⎠ ⎟
Q
p
*
=
2DS
H1-
Annual demand rate
Annual production rate
æ
è
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ö
ø
÷
Q* = 2DS IP
Q
*
=
2DS
IP
Q* = 2DS IP
Q
*
=
2DS
IP
ROP = (150 packs×5 days)+1.65σdLT
σdLT = 5 days×16 2( )+ 1502 ×12( ) = 5× 256( )+ 22,500×1( )
= 1,280( )+ 22,500( ) = 23,780 ≅154 ROP = (150×5)+1.65(154)≅ 750+ 254 =1,004 packs
ROP=(150 packs´5 days)+1.65s
dLT
s
dLT
=5 days´16
2
( )
+150
2
´1
2
( )
=5´256
( )
+22,500´1
( )
=1,280
()
+22,500
( )
=23,780@154
ROP =(150´5)+1.65(154)@750+254=1,004 packs