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Copyright ©2015 by Pearson Education, Inc.
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Engineering Economy
Chapter 12: Probabilistic Risk
Analysis
Copyright ©2015 by Pearson Education, Inc.
Upper Saddle River, New Jersey 07458
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
The objective of Chapter 12 is to
discuss and illustrate several
probabilistic methods that are
useful in analyzing risk and
uncertainty associated with
engineering economy studies.
Copyright ©2015 by Pearson Education, Inc.
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Decision making is fraught with risk and
uncertainty.
• Decisions under risk are those where the
decision maker can estimate probabilities of
occurrence of particular outcomes.
• Decisions under uncertainty are those
where estimates of probabilities of the
several unknown future states cannot be
estimated.
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Four major sources of uncertainty are
present in engineering economy studies
• Possible inaccuracy of cash-flow estimates
• The type of business involved in relation to
the future health of the economy
• The type of physical plant and equipment
involved
• The length of the study period used in the
analysis
Copyright ©2015 by Pearson Education, Inc.
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Factors such as revenues, costs, salvage
values, etc., can often be considered
random variables.
For discrete random variables X, the
probability X takes on any particular value
xi is
where
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Some other properties of discrete random
variables.
Probability mass function
Cumulative distribution function
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
For continuous random variables…
The probability that X takes on any particular value is 0.
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
The cumulative distribution function (CDF) is
which leads to
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
The expected value (mean, central
moment), E(X), and variance (measure of
dispersion), V(X), of a random variable
X, are
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Some properties of the mean and
variance.
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Acme manufacturing has installed a much-needed
new CNC machine. The initial investment in this
machine is $180,000 and annual expenses are
$12,000. The life of the machine is expected to be 5
years, with a $20,000 market value at that time.
Acme’s MARR is 10%. Possible revenues follow the probabilities given below.
Revenue Probability
$35,000 0.1
$44,000 0.3
$50,000 0.4
$60,000 0.2
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
What are the expected value and
variance of Acme’s revenue?
Copyright ©2015 by Pearson Education, Inc.
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
What are the expected value and
variance of Acme’s revenue?
Copyright ©2015 by Pearson Education, Inc.
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Acme is considering purchasing a new vision system for
their production line. The vision system would allow them
to increase revenue due to improved quality and therefore
reduced warranty expense. The initial cost of the system is
$220,000, and the annual increase in net revenue is $45,000.
Acme’s MARR is 15%. However, the life of the system is uncertain, with the probability of different asset lives in the
following table. Given this information, should Acme
purchase the vision system?
Useful life, years (N) 8 9 10 11 12 13 14
p(N) 0.10 0.15 0.25 0.20 0.20 0.05 0.05
Pause and solve
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Probability tree diagrams can display
prospective cash flows, and their respective
probabilities that occur in each time period.
End-of-Year 0 1 2
0.5
0.5
0.6
0.4
$700
$825
$800
$1,000
$900
$1,100
0.3
0.4
0.3
0.3
0.7
$625
$700
$750
-$2,000
Copyright ©2015 by Pearson Education, Inc.
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Continuous random variables present special
challenges, and special opportunities.
• Two frequently used assumptions are
– cash-flow amounts are distributed according to a
normal distribution, and
– cash flows are statistically independent.
Thus, if
then
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Apply these concepts to cash flows over
time to fine the expected PW, and SD of
PW, for the expected values and standard
deviations in the table below. (Use
i=8%.)
End of
Year,k
Expected Value of Net
Cash Flow, Fk
SD of Net
Cash Flow, Fk
0 -$10,000 $0
1 $4,000 $400
2 $4,000 $600
3 $5,000 $650
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
For the expected PW.
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
For V(PW) and SD(PW)
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
With our estimates of cash flow variables, and
using the normal distribution, we can find the
probability of events about the random
variable occurring. For instance, in the
previous example, what is the probability that
the PW of the cash flows is positive? Recall
Copyright ©2015 by Pearson Education, Inc.
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
The standard normal (mean=0 and
standard deviation=1) variable, Z, is
defined as
For our problem, since our random variable is
present worth,
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
The probability is found by looking up a
value in the standard normal table
(Appendix E).
So
Copyright ©2015 by Pearson Education, Inc.
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Another way to handle uncertainty is to
use Monte Carlo simulation.
• Based on the probability of different outcomes for each
random variable, a particular value is randomly generated.
• The numbers generated for all random variables constitute
an instance or realization reflecting a particular outcome.
• Hundreds or thousands of these instances are generated,
and these are examined to assist in decision making.
• A caution: these will yield long term, average results, and
you will be able to see the variation over time. However,
your decision may be a one-time decision, so don’t expect the “average” outcome to be your outcome.
Copyright ©2015 by Pearson Education, Inc.
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Remember Acme Manufacturing and the new
CNC machine. The revenues and associated
probabilities are given below, and also now
the expenses have been given probabilities.
Revenue Probability
$35,000 0.1
$44,000 0.3
$50,000 0.4
$60,000 0.2
Expenses Probability
$6,000 0.1
$8,000 0.4
$11,000 0.3
$14,000 0.2
Copyright ©2015 by Pearson Education, Inc.
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Using the RAND() function in Excel, and
following the probabilities on the previous
slide, we generated 1000 revenue and expense
values (each using a separate random number
for independence), and found the resulting
PW for Acme. We found the following useful
information (we could discuss a lot more).
Not a good deal!
1. The average PW was -$20,670
2. The number of positive PW values, out of the
1000 simulated, was 216.
Copyright ©2015 by Pearson Education, Inc.
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Monte Carlo simulation is very flexible.
• The example used a discrete distribution, but there is a way
to use any discrete or continuous distribution. If Excel is
used, it has several special functions that generate random
variates (e.g., NORMINV to generate normal random
variates and BETAINV for beta random variates.)
• There are many ways to look at the performance of an
alternative using Monte Carlo simulation (we examined
only two in the previous example). Graphs can be
especially valuable.
• Generate lots of data, through many trials. When average
values converge to a fairly constant amount, you probably
have enough data.
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Decision trees can be helpful in
examining sequential decision problems
with outcomes that vary over time.
• Break down large problems into a series of smaller
problems.
• Provide objective analysis that explicitly considers
the risk and effect of the future.
• A decision tree is built from a series of nodes,
where decisions are made (square symbols) or
chance outcomes are noted (circle symbols), and
branches, which specify outcomes.
Copyright ©2015 by Pearson Education, Inc.
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Revisiting Acme Manufacturing and
their CNC machine decision.
Acme already has a machine they can use that is adequate
for their needs. However, they wish to make a decision
about their purchase of the new machine. The time
horizon is 4 years, and they know that they won’t replace their existing machine if there is only one years of the
time horizon remaining. So, they will make a decision
today, and at the end of the first and second years
regarding the new machine. We assume no chance
elements, only a deterministic decision tree. The tree on
the following slide depicts the situation. Cash inflows
and durations are above the arrows, and capital
investments below the arrows.
Copyright ©2015 by Pearson Education, Inc.
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Acme’s decision tree.
Old: 30k/yr
1 yr
Old: 25k/yr
1 yr
Old: 20k/yr
2 yr
-15k -20k -30k
New: 55k/yr
4 yr
New: 70k/yr
3 yr
New: 70k/yr
2 yr
0 1 2
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Analyze decision trees from the last
decision, backward to the first.
Decision Point Alternative Monetary Outcome Choice
2 Old $20k(2)-$30k = $10k
Old New $70k(2)-$180k = -$40k
1 Old $10k+$25k(1)-$20k = $15k
New New $70k(3)-$180k = $30k
0 Old $30k+$30k(1)-$15k = $45k
Old New $55k(4)-$180k = $40k
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Acme should keep their current machine
for one more year.
• The table reveals that at decision point 2, if Acme still has
the old machine, they should keep it.
• At decision point 1, purchasing the new machine provides
greater return than keeping the old one.
• At decision point 0 (today), it is more advantageous to
keep the old (current) machine for one more year, given
that the best decision at decision point 1 is to get the new
machine.
• It would be appropriate to include the time value of money,
so cash flows should be discounted to the present and the
analysis performed again.
Copyright ©2015 by Pearson Education, Inc.
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Adding probabilities to decision trees.
• Most decisions also include chance outcomes, so we use
chance nodes.
• All alternatives emanating from either a decision or chance
node must be mutually exclusive (no more than one may be
selected) and exhaustive (contain all possible outcomes).
• The probabilities on the branches from a chance node must
sum to one (like probability tree diagrams).
• The value assigned to a chance node is the expected value
of the possible outcomes along each of the branches
leaving the node.
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Mitselfik, Inc. believes new scheduling software (at
a cost of $150,000) will allow them to better manage
product flow and therefore increase sales. The
projection of increased annual sales (for the next 5
years), and the associated probabilities, are below.
The following slide shows the decision tree, and
resulting PW at a MARR of 12%.
Increased annual sales Probability
$75,000 0.35
$60,000 0.45
$40,000 0.15
$30,000 0.05
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
New
software
Sales increase
75,000 $120,360
$68,992
PW Probability
0.45
0.15
0.05
0.35
30,000
40,000
60,000
$0
$0Current
software
$66,288
-$5,808
-$41,856
$68,992
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Mitselfik should purchase the software;
the expected PW of the investment is
$68,992.
• The PW of each annual sales increase amount is
given in the far right of the tree.
• The expected value of the annual sales increase is
$218,992 (the sum of the probabilities times the
respective PW).
• Subtracting the initial cost yields a net PW of
$68,992, which is superior to “do nothing” (which is eliminated, signified by the double lines on that
decision branch).
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
How much would we pay to have perfect
information about the future?
• Perhaps with additional information we might have a better estimate of sales, or exact knowledge of sales (“perfect” information).
• The cost of reducing the uncertainty must be balanced against the value.
• Perfect information is not obtainable, so the expected value of perfect information (EVPI) is an upper limit on what we would consider spending.
• EVPI = the value of the decision based on perfect information minus the value without the information.
Copyright ©2015 by Pearson Education, Inc.
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Mitselfik could make the right decision
with perfect information.
Decision with perfect
information
Increased
sales Probability Decision Outcome
Prior
decision
$75,000 0.35 Purchase $120,360 $120,360
$60,000 0.45 Purchase $66,288 $66,288
$40,000 0.15 No purchase $0 -$5,808
$30,000 0.05 No purchase $0 -$41,856
Expected Value $71,956 $68,992
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
How much should Mitselfik pay for
perfect information?
• If Mitselfik had perfect information they would decide not to purchase the software if the increase in sales were $30,000 or $40,000.
• EVPI = $71,956 - $68,992 = $2,964.
• It is possible to find the expected value of any additional information that is not “perfect.” This is discussed in detail in the text.
Copyright ©2015 by Pearson Education, Inc.
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Decision trees can be used to assist in
analyzing real options.
• Real options, similar to financial call
options, allow decision makers to invest
capital now or postpone all or part of the
investment until later.
• When a firm makes an irreversible capital
investment that could be postponed, it
exercises its call option, which has value by
virtue of the flexibility it gives the firm.
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
A good example of postponable
investment is a plant addition.
Consider Mitselfik, Inc., which in addition to
purchasing software needs to expand the
facility. It can complete the entire expansion
now at a cost of $7 million, leading to
anticipated net cash flows (after tax) of $1.2
million for the next ten years. At an after-tax
MARR of 12%, is this an attractive
investment?
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
This does not look attractive for
Mitselfik.
What if demand should change, rising higher than
originally anticipated? Perhaps Mitselfik, Inc. could
be prepared and have an option available that would
allow them to respond to this increased demand.
Copyright ©2015 by Pearson Education, Inc.
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Assume that demand could balloon to $3.5 million
(or, it could go to zero). The original expansion
could handle sales of $1.5 million, and Mitselfik
could acquire additional space (an option) to handle
the additional increased demand of $2 million at a
cost of $4 million. If this additional demand did not
materialize, the original expansion could be sold for
$1 million. What is the best decision for Mitselfik?
This is modeled as a decision tree on the next slide.
Copyright ©2015 by Pearson Education, Inc.
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Mitselfik’s decision tree
Buildinge
xpansion
$9.20mil
-$10.6mil
-$3.79mil
$1.48mil
-$6.55mil
-$0.22mil
-$6.11mil with
option
Sales
$2.1mil
Negligible
sales
Sales
$1.2mil
Add
Continue
Abandon
Add
Add
Continue
Continue
Abandon
Abandon
-$7.00mil
-$6.11mil
PW
Expected value =
$0.96mil if all
outcomes are
equally likely.
-$6.11mil
$9.20mil
-$0.22mil
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Engineering Economy, Sixteenth Edition
By William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling
Mitselfik should strongly consider
investing since the option to add capacity
can provide a positive return.
• Using the decision tree model to assess the option
reveals that the expected return, given the best
decisions along the way, is $960,000.
• However, losses could be large, and there is a 2/3
chance of a loss (if all outcomes are equally
likely). Issues like this are covered in Chapter 14.