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10-HighAngularResolution.pdf

1

High Angular Resolution Techniques (Ch 12)

Phased Arrays Doppler Beam Sharpening Synthetic Aperture

PHASED ARRAYS

G. Brooker, Introduction to Sensors for Ranging and Imaging: SciTech, 2008. http://www.fas.org/programs/ssp/man/us wpns/air/special/e3.html

2

Resolution of a Single Aperture  For imaging systems (not null steering trackers), the angular

resolution is limited by the beam divergence.

 Beam divergence 3dB (beamwidth) is a function of the wavelength and the aperture size

where 3dB – 3dB Beamwidth k – Constant (70 for  and 1.22 for rad)  - Wavelength (m) d – Aperture diameter (m)

 The for a weighted aperture, the cross range resolution, xr, is the product of the beamwidth (rad) and range (m)

d

k dB

  3

d

R Rxr dB

 

22.1 3 

Requirement for Phased Arrays  The wavelength is fixed by atmospheric window,

propagation effects or physical size constraints.  It is difficult to make the antenna diameter, d, arbitrarily

large to obtain the required angular resolution because of manufacturing limitations

 Use two or more transceivers in an array to synthesise an effective linear aperture equal to the array baseline.

 Uses  Phased array radars  Phased array sonar (linear or 2D) underwater or in the air  Long baseline radio telescopes

http://www.a-research.com.au/sodar.html

3

Transmitter Beam Synthesis

 Individual elements radiate precisely in phase to produce wave crests that move forward in phase

 Interfere constructively to produce a strong narrow beam directed straight ahead

 If a linear phase shift is applied across the array, then the beam is reconstructed at an angle

Receiver Beam Forming  The power received by each element is the sum of the received power

scattered by target P from all the transmit elements

 The elements outputs are summed via lines of equal length to give Ea

ddd

 

Incoming Wave

123N N-1

E1E2EN

Ea

 

 N

k ka tE

1

)sin( 

4

Phase Shift Between Elements  For an incoming signal at an angle  to the array  The phase shift between adjacent elements is  (rad) where d (m) is

the element spacing

rad 2

  

Sin d



Moving Phase Reference to Geometric Centre of Array

 The equation that describes the output voltage from the array for phase shifts starting with element 1 at B is

 It is usual to measure the phase shift relative to the geometric centre of the array, not element 1.

 This displaces the phase front represented by line AB, down to CD

   

 N

k a ktE

1

1sin 

5

Revised Equation Counting from Centre

 The equation that describes the output voltage for phase shifts displaced to the geometric centre is

 

 

  

 

  

N

k

N

k a

N kt

N ktE

1

1

2

1 sin

2

1 1sin





Two Point Array

Ea = sin(t+/2) + sin(t-/2) Ea = sin(t).2cos(/2)

sinA+sinB=2sin[(A+B)/2]cos[(A-B)/2]

sin2A = 2sinAcosA

)2/sin(

)2/2sin( )sin(

 

 tEa 

The field intensity pattern, |Ea()| for the antenna is the magnitude of the amplitude factor

6

Four Point Array

       sin 3 / 2 sin / 2 sin / 2 sin 3 / 2aE t t t t               (1) (2) (3) (4)

See your book for the trig identities used to manipulate this equation

     

sin 4 / 2 sin

sin / 2 aE t

 

 

The General Case

N Point Array

     1

sin / 21 sin sin

2 sin / 2

N

a k

NN E t k t

    

  

      

These equations give identical results if you plug in the numbers, but I have never managed prove the relationship rigorously

7

The Field Intensity Pattern  Substituting for =2dsin/

 The field intensity pattern Ea() is equal to the magnitude of the Amplitude factor

  

  

  

  

 

 

  

 Sin

d Sin

Sin dN

Sin tSinEa )..(

  

  

  

  

 

 

  

 Sin

d Sin

Sin dN

Sin Ea )(

Amplitude factor

The Field Intensity Pattern Continued

 Nulls where the numerator is zero = 0, +/-, +/-2 etc

 The denominator is zero at = 0, +/-, +/-2 etc

 Applying L’Hopitals rule where Ea = 0/0 we find maxima each with value N where sin = +/-nλ/d

  

  

  

  

 

 

  

 Sin

d Sin

Sin dN

Sin Ea )(

  

Sin dN

  

Sin d

8

The Field Intensity Pattern cont… • The maximum where sin = 0 is

called the Main lobe, all the other lobes are called Grating lobes.

• If d/ = 0.5, the grating lobe does not appear for n = +/-1 in real space because sin>1 which is not possible.

• If d/ = 1 the grating lobes appear at +/-90, however as most real radiating elements do not radiate much at  = 90, the grating lobes are suppressed.

• For a non scanning array, the best element spacing is d = 

• For a scanned array the best spacing is d < /2

Grating Lobes for N=10 and d/ = 1

9

No Grating Lobes for N=20 and d/ = 0.5

Radiation Pattern: Linear Array  The radiation pattern is defined as the normalised square of the

amplitude factor

 For Nd = L (the length of the array) and for sin =  (small angle)

  

  

  

  

 

 

  

 Sin

d SinN

Sin dN

Sin

N

E G

a

a 22

2

2

2

)(

2

2

)(

  

  

  

  

  

  

 Sin

L

Sin L

Sin Ga

10

Linear Array cont…

 For d = /2, the half power beamwidth 3dB (rad) is as follows

 If N is sufficiently large, the antenna will be equivalent to a uniformly illuminated aperture, and the first sidelobe will be 13.2dB down.

 For directive elements, the antenna pattern is the product of the element factor Ge() and the array factor Ga().

G() = Ge().Ga()

rad 73.1

3 N

dB 

The beamwidth is smaller than the normal 1.22/d which gives 2.44/N. This is because the sidelobes are so high in this case. See eqn 5.14

Arrays of Directive Elements

Directive Element Pattern

Isotropic Array Pattern

Directive Element Array pattern

11

2D Rectangular Array

Radiation Pattern: 2D Rectangular Array

 The radiation pattern may be approximated as the product of the patterns of the two planes that contain the principle axes of the antenna

G(,) = G()G()

  

  

  

  

  

  

  

  

 

 

  

  

  

 Sin

d SinSin

d Sin

Sin dM

SinSin dN

Sin

G 22

22

),(

12

4x4 Rectangular Array of Isotropic Elements

Antenna Gain  For large arrays, the non-scanned antenna gain can be

approximated by the gain of a uniformly illuminated aperture

 For a scanned array, the gain is reduced by the scan angle o because the projected aperture is reduced in size.

2

4

 A

Go 

2

cos4 )(

 

 oo A

G 

13

Beam Steering

•If the same phase is applied to all the elements of the array, then the main beam will be broadside to the array and  = 0 •The direction of the main beam will be o if the relative phase difference between elements is

o

d 

 

 sin 2

A nt

e n n a

A nt

e n n a

(a)

(b)

Generators Phase Shifters

Radiating Elements

Steered Radiation Pattern

 The radiation pattern is then

 Grating lobes will occur at

 For a scan over +/-90, the element spacing should be d=/2  For a practical array that can scan over +/-60, the spacing d>0.54

  

  

  

  

 

)(

)( )(

22

2

2

2

o

o a

a

SinSin d

SinN

SinSin dN

Sin

N

E G

  

  

  

nSinSin d

og  )(

14

Corrections to Improve Range Resolution

1

2

3

4

5

6

Phase Shift

1

2

3

4

5

6

Time Delay

1

2

Phase Shift

Time Delay

1

2

1

2

1

2

5ns

10ns

Sum Signal

5ns

Sum Signal

Sum Signal

6.5ns

5ns

(a) (b) (c)

Phase shift only Delay adjust only Delay adjust And phase shift

Half Power Beamwidth  The half power beamwidth of a scanned array can be approximated

by the following formula (not valid near end-fire)

 Taper is generally used to reduce the sidelobe levels. Using cosine on a pedestal An = a0 + 2a1Cos(2n/N) where 0 < 2a1 < a0

rad 886.0

3 o

dB NdCos

  

rad 2

636.01 886.0

2

0

1 3



  



  

 

  

 

a

a

NdCos o dB 

 

15

Active and Passive Arrays  With the advent of low-cost MMICs, it is now practical to

manufacture individual transceiver modules to build active arrays  Some of the best in the world are produced by CEA in Canberra,

Australia

Scalable in size and power to meet a broad range of applications, suitable from 'Corvettes to Cruisers'; Full 3D multifunction capabilities; Advanced classification capabilities; Optimised for littoral and open ocean; Evolves to meet changing requirements; Very high reliability, no in-mission maintenance.

CEAFAR Active phased Array

16

Matching and Mutual Coupling  The impedance of the array elements varies with the scan angle  Spurious lobes may appear due to the miss-match  This is a difficult problem to solve analytically, and is often

determined experimentally by exciting a single element and terminating all of the surrounding ones

 Coupling is proportional to 1/d for d=/2, so the pattern and impedance are drastically altered by surrounding elements. Generally the surrounding 5x5 or even 9x9 elements must be considered.

http://www.zonamilitar.com.ar/foros/threads/rinc%C 3%B3n-de-aviones-especializados.23364/page-7

http://www.fas.org/programs/ssp/man/uswpns/air/special/e3.html

17

The Saab Erieye system uses an active phased array radar mounted in a two sided array geometry contained in a large beam shaped structure carried above the fuselage. The limitation of the two sided array is that it can only cover two 120 degree sectors abeam of the aircraft, leaving 60 degree blind sectors over the nose and tail of the aircraft

Erieye video

http://www.youtube.com/watch?v=BOaxi2G0aNI

Thinned Arrays

 Reducing the number of elements leaves the main lobe unaltered but degrades the sidelobe level

 Thinning to 10% reduces the main lobe level down to 10%, but leaves the sidelobe level at 90%

 If the removed elements are replaced by matched dummy elements, then the pattern remains unchanged, only the gain is decreased

M. Skolnik, Radar Handbook: McGraw Hill, 1970.

18

Advantages of Phased Arrays

 Inertialess rapid beam steering

 Multiple, independent beams

 Potential for large peak and average powers

 Control of radiation pattern

 Graceful degradation

 Convenient aperture shape

 Electronic beam stabilisation

Courtesy Eli Brookner

MMIC Based Phased Arrays

Courtesy Eli Brookner

19

Courtesy Eli Brookner

Pave Paws AN/FPS-115 Early Warning Radar

 Frequency 433MHz  Tx Power 284-440W  1792 radiating elements  Each array scans +/-60  30m diameter  6000km range for 10m2

target

 Note the 1980s graphical interface

E. Brookner. (1985) Phased-Array Radars. Scientific American. 76-84.

20

Pave Paws Radar Coverage

http://www.globalsecurity.org/space/systems/pavepaws.htm

Sea Based X-Band Radar

 Tracking and discrimination for ground-based midcourse defence (Starwars mk II)

 Mass 50,000 tons, tall as a 24 story building  Mechanically scanned X-Band phased array, 65%

populated  45,000 Tx/Rx elements

http://www.mda.mil/news/11news0001.html

21

Acoustic Phased Array: Paul Thompson

 16 radiating elements

 16 receiver elements

 3D imaging from a single “ping”

Target Acoustic Image

P. Thompson, "Design and Construction of an Ultrasound Imaging System Using Phased Arrays," BE Honours Thesis, ACFR/AMME, University of Sydney, Sydney, 2003.

Sidescan Sonar & Towfish

Sidescan Array

Operational Principle

G. Brooker, Introduction to Sensors for Ranging and Imaging: SciTech, 2008.

22

Operational Principle  A side-scan sonar antenna a short (50) linear transducer array

made of a piezo-electric material that is towed behind a ship

 The transducer is excited by a short (  3s) high voltage sinusoidal stimulus at a frequency close to the resonant frequency of the array which the array converts to vibrations and radiates into the water.

 The operational frequency is generally between 50kHz and 500kHz with some short-range units operating up to 1MHz.

 The same array is used to receive any echoes. These are then amplified and recorded to form an image. In modern systems, the signal is digitised in the tow-fish and transmitted to the surface for processing and display.

 The operational range for low frequency units (f  100kHz) is about 500m, this decreases to 50m at a frequency of 1MHz due to the increasing attenuation of water with frequency.

Sound Attenuation in Water

Attenuation increases by a factor of 10 from 100kHz to 1MHz

23

Beam Pattern

 Because of its shape, the array produces a fan beam pattern  narrow azimuth beamwidth

(typ. 0.75 to 1.5) determined by the length of the array

 wide elevation beamwidth (typ. 35 to 65) determined by the vertical aperture of each element.

 Arrays are placed on either side of the tow-fish and angled slightly downward to produce the patterns shown

Sidescan Image: The Port Hunter

Bang Pulse

Water Krill & Fish etc

Ocean Floor

http://uboat.net/allies/mer chants/1925.html

Sidescan Playback

http://www.youtube.com /watch?v=AJoqh2SdQZ k

24

Effect of Shadowing

Because of the shallow grazing angles, shadows can add significantly to the information available from a sidescan image

J. Fish and A. Carr. (2001, March). Acoustics and Sonar (AUSS Ltd). Available: http://www.marine-group.com/acoustic.htm

Signal Processing

 The standard matched-filtering principles developed for radar are applied to sonar systems to ensure that the maximum SNR is achieved.

 Most side-scan systems are real beam in that their cross range resolution is a function of range xr = R.az

 Digital techniques can be applied to correct for phase front curvature. This is known as focussing, and it can be used to achieve a fairly constant linear beamwidth with range (this is similar to SAR processing).

 Beam scanning techniques using phase shifters in the arrays can be used to spotlight particular areas

 Simultaneous multi-frequency operation eg. 100kHz and 600kHz is possible for high resolution short range operation and lower resolution long range operation.

25

Pseudo 3D Images

If views are made from more than one perspective, they can be combined into a pseudo 3D image as shown here for the Fritzen

S. Hultqvist. (2007). Swedish East Coast Wrecks. Available: http://www.abc.se/~m10354/uwa/wreck-se.htm

3D Sonar Imaging

 Sophisticated 2D sonar arrays such as the one developed by Thomson Marconi Sonar (TMS) in Sydney can produce short range 3D images with voxel resolutions down to 1x1x1mm

 A group of 3 uniformly spaced transmitters illuminates the target with high frequency (>1MHz) sound pulses.

 A sparse phased array made up of 84 tiles each made up of a random pattern of 32 hydrophone receivers receives the echo.

26

Sonar Images

Synthetic Aperture Radar

27

Definition

 Synthetic Aperture Radar (SAR) and Doppler beam- sharpening (DBS) are techniques that use the forward motion of an aircraft carrying a radar to improve the cross-range resolution

 Both these techniques can be used for sonar applications as well

Space Based SAR

Doppler Beam Sharpening

 Doppler beam-sharpening uses the decreasing radial velocity (hence Doppler shift) across the beam footprint to synthesise improved cross range resolution

 For an aircraft flying at 250m/s, the isovel (and isodop) lines at 1.25m/s spacing are shown

h

slant range

ground

elevation beamwidth

beam footprint

PLAN VIEW

SIDE VIEW

azimuth beamwidth

range gates

lin es

o f c

on st

an t

D op

pl er

s hi

ft (is

od op

s)

real aperture resolution

Doppler beam-sharpened resolution

Decrease in Velocity (m/s)

Azimuth Angle (deg)

1.25 5.73

2.5 8.11

3.75 9.93

5 11.48

6.25 12.84

7.5 14.07

28

Doppler Beam Sharpening

 Limitations include a trade off between the “sharpening” and the observation time

 At 10GHz, 1.25m/s isodop lines are 83Hz apart requiring an observation time of 12ms to resolve them, 3m travel time at 250m/s

 At 94GHz, the lines are 800Hz apart requiring an observation time of 1.2ms (0.3m)

 The beam is scanned physically to the one side of the direction of travel

 A reflectivity image is built up using the higher cross-range resolution

Real Image Sharpened Image

Developing a Synthetic Aperture

Azimuth

Range

Doppler

Pulse Width

29

Generation of the Synthetic Aperture

 The term “synthetic aperture” refers to the distance that the sensor travels during the time that the reflectivity data are collected from a single point

 Energy from each point is made to arrive in phase at the output of the processor for all of the samples to realise the narrow beamwidth.

 Good range resolution is obtained using one of the pulse compression techniques discussed in the previous lecture

Azimuth

R a n ge

Point target signature from a moving target, before and after pulse compression

Sampling the Aperture

30

Synthesizing a Beam  The process to determine the radiation pattern is similar to that used

for the fixed array  The primary difference is that the signal received by each element is

due only to the received power scattered by target P from one transmitter element

 This results in a slightly different radiation pattern for SAR. The beamwidth is narrower, but the sidelobes are higher than that for the equivalent phased array. For Le the synthetic array length

 The half power beamwidth can be found by solving for GSAR()=0.5 and solving graphically (or using Newton)

2

2

)(

  

  

  

  

  

  

Sin L

Sin L

Sin

G e

e

SAR

39.1 2

886.0 

 

 

Sin Le

Unfocussed SAR  Aircraft motion that deviates from a

straight line and “range walk” is compensated for.

 One limiting condition for the largest aperture Lmax is the point where the round trip phase error reaches /4 as determined in the diagram

 for

)2/( 28 max 

 Sin

L 

R

L Sin

2 )2/( max

R

L

48

2 max

2/max RL 

Azimuth

R a n g e

Point target signature corrected for range walk

31

Cross Range Resolution: Unfocussed SAR  A second limiting condition is that the beamwidth is sufficiently wide

to illuminate the target at point P.

 The beamwidth is obtained by equating GSAR()=0.5 as before

 The cross-range resolution cr = R = R.sin for small angles

 Substituting for Le and simplifying

dBRL 3max 

39.1 2

886.0 

 

 

Sin Le

eL Sin

 

 2

886.0 

e cr

L

R

 

 4

886.0 

2/max RLLe   Rcr 3.0

Focussed SAR

Azimuth

R a ng

e

Removal of the range curvature from the returns from a point target into a single range gate to allow correlation in azimuth that results in the improved cross- range resolution

32

A Doppler Perspective  A point scatterer enters the forward

edge of the beam. It will have Doppler frequency:

 For small beamwidths, the Doppler frequency decreases linearly to 0 and then increases again.

 The angle to the target as a function of time is

 The Doppler frequency as a function of time will then be

Target just enters beam

Target just leaves beam

Target

Synthetic Aperture

)2/cos( 22

3dB r

d

vv f 

 

R

vt 

 

 

 R

vtvv tf rd cos

22 )(



Doppler Perspective cont…  Taking the derivative to obtain the rate of change of Doppler

frequency, or the Doppler slope

 At t=0

 The total Doppler shift over time Td = time within the beam for  = -3dB/2 to +3dB/2, assuming a linear change in frequency

 By analogy to the linear FM range resolution, the signal can be passed through a matched filter to give a spectral resolution f = 1/Td

 

 

 R

vt

R

vv

dt

df d sin. 2

R v

dt

df d 22

dd T R

v f .

2 2

 

33

Doppler Perspective cont…  The cross range resolution is then the optimised cross range resolution

of the real beam b = Le scaled by the ratio of the spectral resolution to the whole Doppler shift

Substituting

But Le = v.Td = Rb = R/D where D = antenna aperture

The cross range resolution for focussed SAR is independent of the range R

d e

d bcr

f

f L

f

f

 

 

  .

222 2

1

2 d

e dd

ecr Tv

R L

TTv

R L

  

2 .

22

D

R

DR

L

R

e cr  

 

Resolution Comparison

Frequency f = 94GHz Aperture D = 120mm

34

Layover Weak Return

Shadow Shadow Shadow

ForeshorteningLayover

Terrain with slopes steeper than these tangentials will be imaged with layover

Depression angle

(a) (b) (c) (d)

Ground range projection

Distortion in SAR Images

 layover, when the range to the top of an object is less than the distance to its base

 foreshortening, when the near side of elevated objects appears steeper than it actually is

 shadowing, when a tall opaque object blocks the signal path behind it, and no returns are received

35

Distortion in SAR Images: Stretching

Depression angle

Ground range image plane

Slant range image plane

Shadowing in SAR Imagee

Sandia. (2004). X-band Synthetic Aperture Imagery, Sandia Labs, . Available: http://www.sandia.gov/RADAR/imageryx.html

36

Measurement Coherence:

Speckle

Sandia Lab’s Miniature SAR  Specifications Total mass 10kg

Range 15km

Resolution 10cm

37

China Lake Airfield 3m

Sandia. (2004). X-band Synthetic Aperture Imagery, Sandia Labs, . Available: http://www.sandia.gov/RADAR/imageryx.html

Another Airport that isn’t Hong Kong

Sandia. (2004). X-band Synthetic Aperture Imagery, Sandia Labs, . Available: http://www.sandia.gov/RADAR/imageryx.html

38

Piers and a River 1mSandia. (2004). X-band Synthetic Aperture Imagery, Sandia Labs, . Available: http://www.sandia.gov/RADAR/imageryx.html

Pipeline Crossing a River 1mSandia. (2004). X-band Synthetic Aperture Imagery, Sandia Labs, . Available: http://www.sandia.gov/RADAR/imageryx.html

39

T-72 Tanks in Formation 10cm

Space Based SAR  To achieve good angular resolutions

from real aperture space-borne radars is impossible at lower frequencies because the size of the antenna becomes prohibitively large.

 With a SAR, the large synthetic aperture results in a cross range resolution independent of range cr = D/2 where D is the antenna aperture

 The good range resolution r = c/2f is achieved by transmitting a wide bandwidth chirp.

 Because the trajectory of the satellite or shuttle is precisely known and stable, motion compensation is not required and exceptionally high quality images can be produced.

40

Interferometry

 Because SAR is concerned with the phase relationships between scatterers on the ground  Two similar images are produced using offset

antennas, or on subsequent passes over the same area,

 Interference patterns can be used to determine the true height of the objects on the ground.

 In addition to being useful for mapping ground features, this technology has a number of other uses:  Local deformation of the earth’s crust as an early

warning of earthquakes or volcanoes.  Ground subsidence due to mining activities or

excessive use of ground-water

Interferometric SAR Image of the San Francisco Area

41

Oil rigs

Mississippi Delta

Ship

42

Magellan SAR map of Venus

(26/11/04). Magellan Mission to Venus. Available: http://www2.jpl.nasa.gov/magellan/

43

Sif Mons 2km High and 300km in diameter 3D Image produced by combining SAR and altimeter data

(26/11/04). Magellan Mission to Venus. Available: http://www2.jpl.nasa.gov/magellan/

Phased Array Application

Performance of Sidescan Sonar System

44

Sidescan System Evaluation ITC 5202 Transducer

Size of Unit 68.5x3.8cm

Array Dimensions 1.27x53cm shaded active array

Resonance Frequency 117kHz

Useable frequency range 111-126kHz

Beam pattern: 53cm line

1.27cm line

1.5 at 117kHz 60 at 117kHz

Efficiency >40%

Input power <5% duty cycle 1500W

Operating Depth Unlimited

Weight 4.3kg

Housing aluminium

Transducer Array

Receive -180dB rel 1V/Pa

Transmit 170dB rel 1Pa/V at 1m

45

Worked Example

 What is the smallest target that can be detected by the ITC-5202 transducer at a range of 500m?

 Operational frequency f = 117kHz

 Velocity of sound (assumed constant) c = 1522m/s

 Wavelength  = c/f = 13mm

Pulse Width and Range Resolution  The quality factor is determined from the operational band

 The rise time of any pulse generated by the transducer is related to the resonant frequency and the quality factor

 The minimum pulse-width must be at least twice the rise time if the pulse it to reach its peak value. For a “rectangular” pulse, the total pulse-width should be 5rise = 333s. This longer pulse gives improved long range performance at the expense of the resolution

8.7 111126

117 

 

 

lu

r

ff

f Q

s f

Q

r rise  7.66

10117

8.7 3 

 

m c

R 25.0 2

103331522

2

6

 

 

46

Cross Range Resolution

 The cross range resolution at 500m (for the given azimuth beamwidth of 1.5) is the product of the beamwidth in radians and the range (no focussing)

mRxr 1.13 3.57

5.1 500  

Pulse Repetition Frequency (PRF) and Duty Cycle (DC)

 To operate out to a maximum unambiguous range of 500m, the maximum pulse repetition frequency PRF is

 The transmitter power is limited to a maximum of 1500W for a Duty Cycle of less than 5%. The duty cycle in this case is

 which is much smaller than the limit, so the maximum power can be applied to the transmitter.

Hz R

c PRF 52.1

5002

1522

2 max max 



%05.01033352.1100100DutyCycle 6  PRF

47

Pulse Compression

 If pulse compression is applied to obtain the best possible resolution for the sonar but using the full duty cycle =5%, then

 And the duration of the pulse increases to

0.05m 10152

1522

2 3 

 

 

f

c Rpc

s109.32 52.1100

5

100 3

 

pr pc

f

 

Transmitter Power Density  If the transducer was omnidirectional, then the power density at a

range of 1m would be the product of the electrical power Pelec , and the conversion efficiency  divided by the surface area of a sphere with a radius of 1m

 The antenna gain, known as the Directivity Index (DI), which is defined in terms of the power with respect to an isotropic radiator can be calculated from the elevation and azimuth beam widths (in radians)

 The actual power density in the direction of the peak gain is the product of the gain and the isotropic value

2/7.47 4

4.01500

4 mW

P I eleciso 

 

 

4.458 605.1

3.5744 2 

 

 

 

G

2/218644.4587.47 mWGII iso 

48

Sound Pressure Level  The sound pressure level (SPL) or S is generally given in dB relative

to 1Pa at a range of 1m. This can be calculated from the power density and the acoustic impedance of the water.

 The acoustic impedance, Z of water is the product of the density and the velocity

 The relationship between the acoustic pressure, P in Pascals, the power density, I in W/m2 , and the impedance, Z, is

 This can be re written for the acoustic pressure in Pa for the sound pressure level, S, as follows

sec/1056.115224.1026 26 mkgcZ o  

IZP 2

IZPS 1226 10)10( 

Sound Pressure Level in dB

 This is generally written in dB form

dBS

IZPS

dB 3.2253.105120)1056.121864(log10120

)(log1010log10)10(log20log10 6

10

10 12

10 6

1010





49

Sound Pressure Level from Graphs  It can be seen that at 117kHz, the

transmitter voltage response is 170dB rel to 1Pa/Volt at 1meter.

 The electrical power input Pelec is related to the RMS voltage V and the transducer conductance G

 For a conductance G = 5.5k mho from the transducer specification table and a power Pelec = 1500W

 The sound pressure level SdB for 522V applied to the transducer is

GVPelec 2

Vrms G

P V elec 522

105.5

1500 3 

 

dBVSdB 3.224)522(log20170)(log20170 1010 

Transmission Loss  As the signal propagates through the water, the sound pressure

level reduces because the wave is expanding on a spherical wave- front and due to attenuation. The transmission loss in dB is H and is determined as follows:

 Because the sound pressure is determined relative to the level existing at one meter from the effective centre of the sound source, the equation can be rewritten for this reference distance as follows

 The attenuation in dB/m is given by the following formula where f is the frequency of the sound in kHz.

)(log20 12 1

2 10 rr

r

r H dB  

rrH dB 10log20

mdBf f

f dB /0329.0117102.3

3600117

117036.0 102.3

3600

036.0 27 2

2 27

2

2

  

 

 

50

Target Strength T  T in dB is defined by ratio of the reflected sound pressure scattered

by the target at a distance of one meter from the effective centre of the scattered sound to the incident sound pressure on the target

 This target strength is determined by its size, shape and the fraction of sound that is re-radiated.

 If the scattering cross section is  square meters, then T in dB is given by the following formula

 As with the radar case, a sphere with a radius, a, much larger than the wavelength will have a cross section equal to the projected area

i

r

P

P T 10log20

  4

log10 10T

2 log20

2 log10

4 log10 10

2

10

2

10

aaa T 

 

  

 

Applying the Sonar Range Equation for a Spherical Target

 For a spherical target, the echo sound pressure level E relative to 1Pa at a range of 1m from the receiver is easily calculated as follows

THSE dBdB  2

2 log202log40 1010

a rrSE dBdBdB  

120656.0log403.225 10  rrEdB

51

Range Eqn Applied to the Sea Floor  Target strength will be the product of the range resolution and the

cross range resolution modified by a scaling factor to take into account the reflectivity o of the surface.

 and the echo SPL 1m from the receiver will be

SdB – 225.3dB dB – 0.0328 dB/m o – 0.1 m2/m2 az – 1.5 (0.0262 rad) R – 0.25m

 

 

 

4

.. log10

4

.. log10

4 log10 101010

az ooo rRXRRA

T 

r R

rrSE az o

dBdBdB  

 4

. log102log40 1010 

rrrEdB 1010 log108.420656.0log403.225 

Noise Floor  The noise level at sea is mostly generated by wind and wave action

on the surface. It is proportional to sea-state and inversely proportional to frequency.

 From the table reproduced in the notes, we will assume sea state 3 generated by a wind speed of 15 knots

 Isotropic Noise pressure N1 (dB relative to 1Pa) into a 1Hz bandwidth at a frequency of 1kHz is 65dB

 The frequency relationship to map the noise pressure level at 1kHz to the transducer frequency is (see Fig 9.4 in your book)

 For a sea state 3 and the transducer frequency of 117kHz

kHzf fNN 101 log17

dBN f 30117log1765 10 

52

Noise Floor

53

Noise Pressure Level: Pulsed System

 Because the noise floor is defined for an isotropic receiver into a 1Hz bandwidth

 The total noise pressure level in dB relative to 1Pa must take into account the bandwidth  of the receiver (in Hz) and its directivity or gain G.

 The minimum detectable signal level will be 13dB higher than this

Smin = 38+13 = 50dB

dBLN 38)4.458(log10)103(log1030 10 3

10 

GNL fN 1010 log10log10  

Noise Pressure Level: Pulse Compression

 The receiver bandwidth for a pulse compression system can be approximated by the reciprocal of the uncompressed pulse width (signal observation time

pc = 1/pc = 30Hz

 The minimum detectable signal level will be 13dB higher than this

Smin = 38+13 - 20 = 30dB

54

Signal and Noise Levels

Targets Detectable at 500m

 The sea floor with a SNR = 25dB

 A sphere with a diameter of 1m with a SNR = 30dB

 A sphere with a diameter of 0.1m might be detectable but with an SNR = 10dB it cannot produce a Pd = 0.9 and a Pfa = 10

-6

55

Signal Level out of Transducer

 The actual voltage output by the transducer is determined from the transducer specifications. The open circuit receiving response at 117kHz is –180dB rel 1V/Pa. For a signal pressure of 50dB (the sea-floor return at 500m), the output is

 This is very small, and so receiver noise would be a consideration when the actual detection characteristics of the system were being considered.

dBV 13018050)(log20 10 

nVV 32010 20/130  