Statistic Question
Using the data in BELOW find the 99% confidence interval for the variance AND standard deviation of the ages of the babies born at this particular hospital this year.
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The data shown below represents the ages in months of 25 babies born at a particular hospital this year. Babies who are less than a month old are given an age of 0 months.
0 | 9 | 2 | 3 | 10 |
0 | 11 | 1 | 3 | 1 |
2 | 8 | 4 | 7 | 1 |
4 | 7 | 6 | 6 | 1 |
5 | 6 | 7 | 8 | 4 |
Find the 95% confidence interval for the mean age of the babies born at this particular hospital this year.
The mean (average) X is given calculated as
X = Sum of all the ages of babies / Number of babies
X = 116/25
X = 4.64 months
Standard Deviation = SD = 3.2259
The degree of freedom = d.f. = n – 1 = 24
The t value is tα/2 = t0.025 = 2.0639
The 95% confidence interval is given as
X +/- tα/2 S/n
4.64 +/- ((2.0639*3.2259)/25)
14 years ago 3
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