Probability assistance
I have 2 questions:
1. When determining the probable outcome with the "cyclists" as an example:
If there are 469 total "frequencies" and we want to know the probability that those between the ages of 50-59 (60 frequency) won't be participating, you calculate this how???
I approached this by dividing 60/469 = 0.128 which is incorrect
2. I am confused when it comes to understanding "mutually exclusive."
Given P(A )= 0.72 , P(B) =0.81, P(A or B) = 0.66
I arrive at 0.66 = 0.81 + 0.72 - P(A and B)
0.66 = 1.53 - P(A and B)
P(A and B) = 1.53 - 0.66
P(A and B) = 0.87
Why is this NOT mutually exclusive?
10 years ago 3
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