math 141
Write an equation for the polynomial graphed below
12345-1-2-3-4-512345-1-2-3-4-5
Find a degree 33 polynomial that has zeros −44, 44 and 66 and in which the coefficient of x2x2 is −1818.
The polynomial is
Find a possible formula for P(x)Px.
Find a formula for P(x)Px.
Find the polynomial with zeroes at x=1,-2, and 4, where 1 and 4 have multiplicity 1, and -2 has multiplicity 2. Also, the y-intercept of the polynomial is equal to 48.
Answer: the polynomial must look like A(x-1)(x-4)(x+2)^2
note that I've multiplied the factors by a variable A which can be adjusted to match the y-intercept value
y(0)=48 means A(0-1)(0-4)(0+2)^2 = 48
16A=48
A=3
the final polynomial is 3(x-1)(x-4)(x+2)^2
You'll need to use reasoning like this on a few of the problems.
10 years ago 2
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